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How many 8 digit numbers contain a 4 or 8 or both?...

Question

How many 8 digit numbers contain a 4 or 8 or both?

how many 8 digit numbers contain a 4 or 8 or both?



Answers

How many 4 -digit numbers are there with no digit repeated?

So for this problem, it helps to think in the idea of what's the largest two digit and three digit number. And unlike Wise, what's the smallest petunia and three digit number? Because since the numbers happen one by one, uh, the number of two digits and three dudes should be equal to the difference between the biggest and smallest number, because every number in between those two should exist. So, for example, the largest two digit number would be a number that's two digits and adding one to it. Turn it into a three digit number. So in this case, that would be 99 and then likewise for the three digit number, the city 999 because adding one to it would turn into 1000 a four digit number. And then if we're thinking the smallest numbers, well, that would be a number where if we subtracted one, they would turn into a one digit number and a two digit number, respectively. Well, we know that the largest possible number for two is 99 so if we subtracted one from 100 we would get 99. And that tells us that the smallest three digit is 100 because attracting one would turn into a two digit. Likewise, for a two digit. If we have a number where if we subtract one, it turns into a one digit number, well, that would be 10. So the number of two digit and three digit numbers should be equal to the differences between these two. So 99 minus 10 and 999 minus 100 nine minus zero is nine and I minus one is eight. So if there will be 89 2 digit numbers and then likewise for three digit numbers nine minus zero twice is going to be nine a nine minus one is eight. So there are 899 3 digit numbers, and this trend actually will continue. Um, for four digits, there are 8999 4 digits, and you just keep adding a nine every time. So to conclude they're 80 90 digit numbers and there are 899 3 digit numbers

So in this question we're asked for how many 10 digits of 123, 456789 10 digit phone numbers are there? If the first and the fourth digit cannot be a zero or a one. So we have eight options for the first and the fourth And for the rest of the 10 Or for the rest of the eight, we have basically 10 Options, so 10 digits phone numbers. So for two digits we have eight options and the other eight digits we have 10 options. So that basically gives us six million Actually much more than six million. So 6,400,000 000, so 400 million six billion.

The greatest three digits, using zero for eight. You want to start with the largest digit, which is gonna be AIDS then for a zero.

In this problem, we're figuring out how many four digit numbers can be made on. What we know is that for the first digit, it can't be a zero. So there are only nine choices. The second digit could be a zero or any other number, and so you have 10 choices. The third digit. You also have 10 choices, and the fourth digit you have 10 choices. And according to the multiplication principle, we should multiply the number of choices for each decision together. So we have nine times, 10 times, 10 times 10 and that would be 9000 different four digit numbers according to those rules.


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