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18) Determine the Ka for CH3NH3 at 25*C. The Kb for CH3NHz is 4.4 x 10-4_ A) 6.8 x 10-H1 (B) 2.3 * 10-11 C) 3.1 10-10 D) 2.3 10-3 E) 5.6 * 10-10...

Question

18) Determine the Ka for CH3NH3 at 25*C. The Kb for CH3NHz is 4.4 x 10-4_ A) 6.8 x 10-H1 (B) 2.3 * 10-11 C) 3.1 10-10 D) 2.3 10-3 E) 5.6 * 10-10

18) Determine the Ka for CH3NH3 at 25*C. The Kb for CH3NHz is 4.4 x 10-4_ A) 6.8 x 10-H1 (B) 2.3 * 10-11 C) 3.1 10-10 D) 2.3 10-3 E) 5.6 * 10-10



Answers

Find the $\mathrm{pH}$ and percent ionization of each HF solution. $(K_{\mathrm{a}}$ for $\mathrm{HF}$ is $6.8 \times 10^{-4}.)$
a. 0.250 $\mathrm{MHF} \quad$ b. 0.100 $\mathrm{MHF} \quad$ c. 0.050 $\mathrm{M} \mathrm{HF}$

We have a dissociation reaction which is represented us for low, along with the initial concentration off each other. So the dissociation constant formula is represented over here, which is de presented us the concentration off product divided by the concentration off Jack. Substituting in the values we have a value for X. That is 9.35 to 10 days to burn. Negative three. That is the concentration off each for the divine. We have a pH formula that s p h equals negative. Log off. It was a divine that is H three you, wasn't it? Substituting in the values we have negative log off 9.3 five into 10 resto bar Negative three. Therefore, the pH will be the pH off Jeff Solution will be 2.3 second using the same second. No, we need to calculate the percentage off ionization off the given reaction suppose sent. It can be calculated by the concentration off the act and my nights divided by the initial concentration while deployed with hundreds substituting in those value. We have the percentage off ionization as 73 points at 3.7%. Option B can be also sold using the same method. Exactly same method. First, we need to deter mined, the dissociation constant and the value off X, which is five point 92 into 10 days to plan negative. Three five. When I do know we need to deter mined the pH off the solution be it can be determined by using the negative log off. EJ three. Well, positive. Substituting in that value we have negative log or 5.92 into 10 days. Double negative. Three. The pH off it's a solution will be 2.23 Option three auction. See, It's again exactly the same. We need to deter mined the association constant for the reaction. First on the value off X, which is the concentration of which for the divine the concentration off each positive I interns Toby. 4.18 three into 10 days. Double negative three. Again, we need to do to mind the pH of the solution. Using the same formula. Negative log off concentration off which positive, which in this case is 4.1833 multiplied with 10 days to plan negative. Three. The P it's turned out to be 2.38 and lastly, we need to have. And lastly, we need tohave the percentage off ionization by dividing the concentration off ionized asset with initial acid, and the percentage off each of ionization is a 20%.

This question is almost exactly same. Tow the previous one. So let etch a B the week monitor erotic asset with initial concentration off 0.100 Where Making an i c e table on DDE The reaction This was ionization constant k A. Substituting in the values we have a value off concentration off age for the divine that is X equals 1.0 in tow tend to a stupid negative three. We know the formula for peaches. Negative. Log off it for the divine Substituting in that value we have a pH at three. We now have to deter mined the percentage off ionization that is equal to the that is equal to the concentration off ionized product that is positive. I divided by the initial reacted, multiplied with 100. Using this, we have percentage off ionization as one person. Same has to be done for option B and option C in auction be the value off excess under the value off ex. Turn out to be 1.0 into 10 days to plan. Negative, too, on the value off pH as too along with the ionization as 10%. Exactly same for auction see the value off X is one into 10 days. Tobar negative one in 10 days to one negative one. From that, we need to determine the pH, which is one that is highly acidic. Now we need to deter mined the percentage off ionization as it's 30 positive, divided by the reactor that is edgy. My deployed with 100 gives me 1.0 in tow. Henry's took one negative one, divided by 0.10 multiplied with 100. Gives me 100% organization. That is auctions. See, EJ A is the most acidic one.

To calculate the ph of 8.55 Mueller hydro's ionic solution with a K. value that is provided. Yeah. We simply need to use the little equation that the hydro knee um concentration for a solution containing a weak acid is equal to the square root of the concentration of the weak acid multiplied by its K. A. Value. This will work so long as the hydro knee um concentration that we calculate is less than 5% of the original concentration Which it is. We can then take the negative log of this hydrogen ion concentration or hydro knee um concentration. To get our ph of 4.73. Next we need to calculate the P. O. H. Of a 00.44 Mueller H. I. 03 solution when we do this because we have a very large K. A. Value and they moderately small concentration. We're going to have to use the quadratic formula because when we calculate the hydro knee um concentration with this large K. A. value, it's going to be more than 5% of 50.44. So we'll set it up this way and solve for the hydro knee um concentration. And we get 359 times 10 to the negative too than to get P. O. H. We need to take the negative log of the hydroxide concentration, which is the hydro knee um concentration. We just calculated divided into K. W. And we get a p. o. of 12.56. Mhm.

Move The question is calculated the ph of a 0.05 solution of Benwick acid. And is given. And also calculate representative of the acid that has united in that solution. Okay so in that question we have Initial concentration. That is the 0.05 and the K. Is equal. Do 1.2 into 10 rates. The power -4. Okay. And Ben jake as it will be dissociated in the water like this. He killed on well established and C685. C -1. As through. Yes. And it first we have to calculate the concentration of acid, salt and Iranian iron. With the help of I see table so we will draw I. C. E. Table here will come acid and here welcome salt and here will come. How do you I am correct At T equal to zero initially. Initially as it is presented. And the concentration of this is 0.05 salt concentration. zero man concentration. Okay so what does that change? Mm. Changes minus six X. X. Yeah. Because concentration of reactant is decreasing as the reaction former was. And the concentration at equilibrium act equilibrium. Mhm. That will be 0.05 -6 eggs and eggs, correct? So what is the expression of ionization constant? It will be K. Equals the ratio of concentration of salt and hired Iranian oil. Do that concentration of reactive. That is as So in that question we have value of K. That is equal to one appointed to into 10 regional power minus food X. Into X. Don't worry about it. 0.05- States. Okay. Here value of X is very very less than it is very very less than jiraporn purified because vengeance asset is a very weak acid. So it even ionized very very less. There's why we can ignore X. value in front of 0.05. So it will comes out X squared equals to 1.2 to 10. To the power minus food. 0.05 and X will be equal to 0.6 and two and X will it will do. Yeah. Okay. Two point 44 into 10 regions of our -3. Okay, so this is the concentration of also hired Tony in iron. Okay, now we have to calculate the value of ph so ph is what ph is equal to minus log X plus And as plus we have calculated that is 2.44 into 10. Rich the power -3. So ph will comes out Here 2.61. Okay now we have to calculate also percentage of dissociation. So formula of percentage the association That will be equal to concentration of S. three a plus. Higher. Get worried about it concentration of Benjamin acid in 200. Okay, so hydrogen ion concentration that is employers minus three In 2 0.05 and to my 100. So it will be equal to 4.8%. Okay, It is the degree of the association of Ben drake, a student. Okay, Thanks.


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