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Write the balanced chemical equation.The burning of methane gas, carbon tetrahydride, in air producescarbon dioxide gas and water vapor....

Question

Write the balanced chemical equation.The burning of methane gas, carbon tetrahydride, in air producescarbon dioxide gas and water vapor.

Write the balanced chemical equation. The burning of methane gas, carbon tetrahydride, in air produces carbon dioxide gas and water vapor.



Answers

Write the balanced chemical equation for the combustion of methane, $\mathrm{CH}_{4}(g),$ to give carbon dioxide and water vapor. Explain why it is difficult to predict whether $\Delta S$ is positive or negative for this chemical reaction.

Hi, everyone. So, in this question gas, right. A complete balanced chemical equation when I repenting unconditioned produces carbon dioxide and water. Now, you know the Brendan from the description. We know that from the description. We know that. Uh huh. We know that Van Dane on commotion. Yeah. Mm. And on my son producers? Yeah, Bruce says sure do. And water? Yeah. Mhm. So, you know, painting. See if I ate, then a normal commercial in presence of oxygen guys. Mhm. He gives see or two guys plus water. I certainly created No, you know, we'll ride a balanced chemical equation. So in an auction here to their three. Okay, so they're not balance. So we will put here advice and then here 15 or two. Now garden becomes 10. So 10, 02 hydrogen, 20. So, again, here, 10 water. So certain balance situation for complete conversion of a painting. So painting on conversion on commission. No process. 10 more of carbon Nixon and 10 more love water. So? So to get access. Yes. Thanks a lot

In this question, we have to write the balanced chemical equation for complete combustion of Benji. Complete combustion means the reaction of busy with enough amount of oxygen cash. So C686 plus or two produces CO. Two plus water. Now we have to balance this equation. The reactant side has six carbon adopts so let me put six before C. 02 reactant side has six hydrogen atoms, so are 23 before water to make six hydrogen atoms. Parents. And the reactant side has to oxygen accounts. But the product site has 12 oxygen atom here and three oxygen atoms here, so total 15 oxygen atoms, But here two oxygen atoms already there. So we have to put here 15 x 5 to so This side reaction side will have 15 oxygen atoms, but we cannot do fractional number. We have to put a whole number for balancing a chemical equation. So we need to multiply both reactant and product side with two, then we'll get 15 or two. So let's do that. C six 86426686 plus Here, 15 x two. Or to multiply by two so we'll get 15 or two. Then we'll multiply two with six carbon dioxide which would be 12 C. 02 And then we'll multiply two with three water so we'll get six water molecules. So if we count we'll see in the reactant side 12 carbon atoms. Products side also has to help carbon atoms react inside 12 hydrogen atoms. Product side also has 12 hydrogen atoms react inside has 30 oxygen atoms. And product side also has 20 for oxygen atoms here and six oxygen atoms atoms here, so total 24-plus 6 hardy atoms. So the reaction is balanced. So let me write it Again to see 686 plus 15 or two 12 0 to plus six. Ace to this. Is that balanced equation for complete compassion of busy

All right. Today we're gonna be doing some combustion reactions with hydrocarbons were given these four hydrocarbons on the left, and we're gonna need to write a balance combustion equation for all of them. So first, here we have a thing which could, see, has two carbons and four hydrogen. So for the first one, we're gonna rock E to H four. Gonna be a gas. All right, so we have two carbons in the left, so we're gonna need to on the rock. So let's go ahead and put to right there. Balance that out. And now we need four hydrogen with right, because we have four on the left. Have this h two from H 20 So if we add a to coefficient right there to see that we have four hydrogen, the rot as well. Go ahead and add up the oxygen to see if we can balance it with this. 02 molecule. We'll have 234 plus thes two, which is six. So to make this six, we're gonna add three. And this will be a balanced equation for the first. Okay, next we have protein. So this will be the three and 123456 hot. The C three h six. Oops. That's gonna be a gas. Okay, so way have three carbon on the left. So let's just go ahead and put three car. But on the rock, we have six hydrogen, and we're gonna need to make this 16 hydrogen. And now let's see if we can balance out the oxygen. We have two oxygen, plus these six plus these three. So you see here, that's an odd number. And with this 02 molecule, we're not gonna be able to balance this one out, so we're gonna have to add something else. So let's go ahead and change. This Do can't change the other ones. Let's see, we have six carbon around here, so go ahead and put six carbon on this side. Now, we have 12 hydrogen now, so we're gonna need to make this 1 12 so we'll add a six is Well, all right. So now we have 12 oxygen, plus the six, which is 18. We're gonna need to make this age 18 so? Well, I had a non right there, and you can see this equation is gonna be balanced all right. For the next one, we have iso butane, which is just the next hydrocarbon in them in the sequence here. So that will be C four h 10 I believe word. Yeah, it would be a gas running over. You are us on. All right, so we have four carbons on the left. So didn't do the same thing, but four on the right. We have 10. Hydrogen will make this 1 10. And then let's add up all the oxygen. It's eight. Plus, these five 13. So we've done the same thing that we did up here. We're getting an odd number of oxygen atoms. No, we're gonna go ahead and change that up a bit. And what another two? Two times four. That's eight, but eight there. 20 hydrogen. So you get 20. We're gonna have to add a tin right there. And so we have kin, plus the 16. That's 26 oxygen on the right side. So what? Can we multiply by two to get 26 13? Because you can see for these kind of problems. You just have to work with the numbers until you get it right. Finally with cyclo butane we're gonna have four carbons, but we're gonna have a different number of hydrogen, so Oh, no. Back a little too far. It was 13. Run. All right, will do e four each eight. But this one. It's similar to the amount of carbons in the last one, but we have a different number of hydrogen since it's in a It's an enclosed circle right here. All right, so we have four carbons on the left side, so we'll go ahead and do the same thing and put four on the rot. We have eight hydrogen, so we'll make this 18 four times two. Now we'll see if we can balance out the oxygen were four times to That's eight plus thes four. That's 12. So all we need is a six here. And so it he's had the same amount of carbon that we didn't have to change the coefficient in front of the hydrocarbon. If you see here, we've balanced all four chemical equations

In this exercise were given four windows. And in these windows we have gaseous methane which is represented. I have a little key in the bottom, right by the ones with the black in them. And guess his oxygen. And we are asked to balancing the equation for the reaction and determine which window is correct for having no excess reactant. Yeah. Pain reacts with oxygen in a combustion reaction to form Co. Two, gas and steam are balanced chemical equations. That will have twos here and here. Please notice that our ratio is one methane for two oxygen's. We have a 1 to 2 ratio. Call these windows A. B. C. D. In the window number one it looks like we have a 4-7 ratio. Not very perfect. In Window number two, it looks like we have a five for the oxygen's And five. We have a 1-1 ratio. Mhm. In C We have three mouth ans And 12345678 Eight oxygen's of 3- 8 8 ratio. Oh my gosh, I forgot to write my. That was almost tragic. Here we have four 21, 678 4- eight, which is 1- two. So the correct answer. Get a new color. Here is letter D. Yeah.


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