5

Using the following sequence, illustrate the process oftranscription by filling in the correct bases forthe mRNA.Sense: A C G G G G C C T A CATemplate: ...

Question

Using the following sequence, illustrate the process oftranscription by filling in the correct bases forthe mRNA.Sense: A C G G G G C C T A CATemplate: ______________________________________mRNA: ______________________________________Now illustrate the process of translation byfilling in the correct tRNA bases using the mRNA you transcribe inthe previous exercise. tRNA: __________ __________ ____________________ Use the chart provided on the next page, find the amino acidsthat ea

Using the following sequence, illustrate the process of transcription by filling in the correct bases for the mRNA. Sense: A C G G G G C C T A C A Template: ______________________________________ mRNA: ______________________________________ Now illustrate the process of translation by filling in the correct tRNA bases using the mRNA you transcribe in the previous exercise. tRNA: __________ __________ __________ __________ Use the chart provided on the next page, find the amino acids that each mRNA codon (not the tRNA anticodons) in the sequence above code for. List the amino acids below. Codon 1: __________________________________ Codon 2: __________________________________ Codon 3: __________________________________ Codon 4: __________________________________



Answers

(a) Write the sequence of the mRNA molecule synthesized from a DNA template strand having the following sequence. $$5^{\prime}-\text { ATCGTACCGTTA-3 }^{\prime}$$ (b) What amino acid sequence is encoded by the following base sequence of an mRNA molecule? Assume that the reading frame starts at the $5^{\prime}$ end. $$5^{\prime}-U U G C C U A G U G A U U G G A U G-3^{\prime}$$ (c) What is the sequence of the polypeptide formed on addition of poly(UUAC) to a cell-free protein-synthesizing system that does not require a start codon?

Okay, I am going to write the complementary Strand Messenger or in a strand, the messenger or in a in a 5 to 3 direction. And that's going to include its code on sequence and the amino acids that it encodes. Or so let's first do the complementary strand for DNA. The DNA strand that was given runs in a 5 to 3 direction. DNA's anti parallel to the complementary strand runs in a 3 to 5 directions. I'm going to start on this side now. The ad mean always piers, but the timing and the side of seen always piers with the Guan E. Right now I'm going to write The messenger are in a strand, just going to go 3 to 5. But I'm going to write it 5 to 3. Now, this is going to complement this original strand and look at the similarities between these two strands. So dream Okay, A we do know have finding a messenger or in a so it would be euros ill. All right now I'm going to switch this messenger or in a to a 5 to 3 prime direction, um, with the code owns so code owns air going to be sequences off three. So we're going to flip this around so we're going to have cheating a a You see, she and C G you now I have divided that into its code ons, which again are going to be three of those bases and then the amino assets that they cope or you used the genetic code and this would be glue tannic. Pass it. This one would be Cering, and this code on would curve for arching.

Thats question below is a DNA sequence in vision that this is a section of a d n a molecule that has separated in preparation for transcription. So you are only seeing the Yankee sent strand construct the M R in a sequence transcribed from this template. So first we have to distinguish between the anti says and the since Strand's So the antisense strand is going to be our template strand, and our sense strand will be our coding strand. So right here we're given our anti sense. We're template strand. This means that we will first have to construct the coding strand of DNA. So as we know, DNA is going to be synthesized in the five prime to £3 of direction. And, um, this way there, there are two options that we have. We can either construct the DNA. Ah, that would be complementary to the template. So the coding strand where we can just go straight to the m r and a. But just to get an idea of what we're doing, we're going to do that middle step of, uh, constructing the d n A strand first. So remember when we're, um, looking at DNA nucleotide disappearing. We know that a present T and C pairs with G. This is for DNA. So since we're looking at our coding strand right here of DNA, then we will follow this base pairing rule. So we will have a T g a C T g a C T g c T a G. But now we have to convert this DNA into M R in a. And this will be our coding, Marnie. So, uh, to do this, we will once again have to flip. Uh, we will base this off of the coding strand. So since we started off with our template strand, we simply to get our m r name, we have the same £5 of three prime orientation because oh, that we're doing is we're substituting in for every t that we see, we're going to substitute in a you because for Arnie A's pairs with a pairs with your so or you and see pairs with G. So this is the are in a nucleotide base pairing rule. So we just take what we have from our DNA, and we're going to, uh, copy it exactly, except for every t that we see we're going to replace it with you, so we'll have a you g a si you g que si u g c you a g So this right here will be your answer.

In this question. We're looking at this strand of DNA and part a asked us to rate the complementary sequence five prime to three prime. So I'm gonna start off just by writing it underneath the strand and matching it up and the multiple bit So it's five grand a year, Brian. So this is the third time to five point version. So T pairs of A and C pers g b c a t c c t a five primes over writing it. Five prime to three prime. Start here. Well, just flip it around. So a t c c t a c she a Part B asked us to write sequence or the strain of m R and A that would be complementary to that original strain of DNA. We're also writing this five prime to three prime. So the only difference between the complementary strand of DNA on the complement of RNA is that we're replacing T with you. Since you are in a uses, you're still, instead of finding that would be a U. C. C you a c g. A. Part C says that assuming this sequence is part of the coding sequence for a protein and that it's lined up. So the first coat on here is the five prime. Um, they asked us to write the sequences for the free anti code ons that would be complementary to the strand of em are on a So let's right, the compliment first in purple. So that would be you. A g g a u she see you. Um, and that is three prime five prime. But we're gonna write the code on by a primitive three prime. So the first one would be g u A. And then we have you a g and you see, g and then part D asked us what sequence of amino acids and selected by this m r and s o. Here. We're still talking about this Amar and a up here. Um, and, uh, What? It tells us that you can use any chart on the Internet that you'll find for the complete genetic code. So, um, a, you see is the first code on here and then see you a and then c g a. So a You see codes for isil. Lucy. Oops, So losing. See you. A codes for losing and c g A codes for Argentine. So I still losing. Losing Argentine would be the sequence of amino acids here

This question involves the topic of base pairing and the general process of transcription. First. Let's see about about base pairing. Remember that you have for D. N. A. You have four naturally no spaces adding. Okay, You have one in, you have cytosine and you have saving for R. N. A. For any type of RNA. The only difference is that instead of timing you have in your arsenal. Okay, that's the only difference. Now. Remember that happening piers with timing or your asylum case of RNA and wanting bears with cyrus in. Now let's talk a little bit about. A DNA. DNA is made of two cents. Okay, this is going to stand and this is the other stand. It just has a name. For example, I suppose this instant is the cold instant according to stand and this is the template strand. The coding strand is called like that. Because when this DNA undergoes the process of transcription, it means the process by which uh M. R. N. A. Is produced. The M. R. Name is going to have the same nucleotide sequence than to the coding standards A. D. N. A. It means if the coding system has a has a following sequence of A then the the M R. N. A is going to have the sequence A. Two. If it is a G C. T then it is going to be G. C. You remember that you use your brazil instead of timing in the in the RNA. Okay, so that's the coding stand talking about a temporary stand. The temporary sent as its name says, it is useful as a template for transcription. So for example and it is going to have the complementary sequence than the M. RNA. For example. Let's give another example. Not this. Let's suppose the template is A C. G. D. A. Okay, so what will be the sequence of the M. RNA? As I mentioned, the template has the complementary sequence to the M. RNA. So the marinade, it's going to be that what binds what place a dining remember it pairs with uracil? So they're going to be in uracil uracil, G C. E. In you. It is going to be the aymara name. Okay. And if you want to know that coding a son for DNA, well it is going to be this sequence. But remember that with time instead of curiosity, it means that calling a son would be T T G C A. T. Okay, so with this knowledge let's transcribe this sequence. Okay, this is the first sequence. Um The question says that all the sequences they are providing us are the template DNA sequences. It means this is the complementary strand to the marina. So our marina is going to be the complementary strength to this. It means instead of tea it is a instead of G it is a C. Instead of a. It is you you the G a do g c c a U G G and you Okay. This is the M r n A produced from this template. A strand of the DNA. Now let's subscribe the next DNA sequence. Okay, as this is the template, the stand then the nitrogenous base that pairs with G. Is see the original space that with C. S. G. A nitrogenous base. That there's a your A C. The G A U U U. She U a n G. Okay. This is the M RNA produced from this is simply the strand of DNA.


Similar Solved Questions

5 answers
Question 1010 ptsAfter balancing the equation for the half reaction acidic media; Cr20z2"(aql 14 Htlaql 2 Cr) (aql 7 HzOmiwnjlthe number 0f electrons tne equation?I"a/4 [4k] /nsutmir Cus
Question 10 10 pts After balancing the equation for the half reaction acidic media; Cr20z2"(aql 14 Htlaql 2 Cr) (aql 7 HzOmi wnjl the number 0f electrons tne equation? I"a/4 [4 k] /n sutmir Cus...
5 answers
Find the measure of an angle @ in quadrant IV such that cos @ 0.725374371. Write your answer in degrees and minutes, rounded to the nearest minute_Answer: 316.5
Find the measure of an angle @ in quadrant IV such that cos @ 0.725374371. Write your answer in degrees and minutes, rounded to the nearest minute_ Answer: 316.5...
5 answers
Ether (the clean-fuel gasoline add tive KTBE): Tamth ERenaoa Faa matha | tert-buty !Ol,Oc(CH,)}moler rmple methyl tert-butyl cther: How manymeasurements thai tnere art 0L0359 moles 0l carbon Acencl enaneer Fat dctennined by hrdrpocn erain tRa Amplel Aolnd Honincan d giti
ether (the clean-fuel gasoline add tive KTBE): Tamth ERenaoa Faa matha | tert-buty ! Ol,Oc(CH,)} moler rmple methyl tert-butyl cther: How many measurements thai tnere art 0L0359 moles 0l carbon Acencl enaneer Fat dctennined by hrdrpocn erain tRa Amplel Aolnd Honincan d giti...
4 answers
|5 e %x dxJ 5e 3x dx=
|5 e %x dx J 5e 3x dx=...
5 answers
Ded )the level of significance, the researcherreject the null hypothesis Ho: 0=2.5will notwillwer boxes
ded ) the level of significance, the researcher reject the null hypothesis Ho: 0=2.5 will not will wer boxes...
5 answers
Flawelja- Drsetsiam TT83 8op MJI MIl oeiud: Iw d4m % [rrihg 07ejxOequk~~ iJo3" -
Flawelja- Drsetsiam TT83 8op MJI MIl oeiud: Iw d4m % [rrihg 07ejxOequk ~~ iJo 3" -...
5 answers
Order the following ionic solids by increasing lattice energy:(low energy high energy) Rbci Naci
Order the following ionic solids by increasing lattice energy: (low energy high energy) Rbci Naci...
5 answers
SALESThe sales $ in terms if units sold x are given by the formula 5 =10 (1 ~0.51x) .Find the number of units sold if sales are S = 4.57. Round to the nearest integer:
SALES The sales $ in terms if units sold x are given by the formula 5 =10 (1 ~0.51x) . Find the number of units sold if sales are S = 4.57. Round to the nearest integer:...
4 answers
QuestionWctis Ihe fst bockward differerce ol yln) to fnd out (he derivative 0 pwen function? O4 [n)*xln-IITOB [yn *[email protected](n)-vin+T)TOD lyin)-xln-IWVTQuESTION ?Lacotlral Olenaka 'Cll # Io sepormaa Iha cothabye U A Rncuon @Olvnd moin urcunlo poaueta ! Zanmatn nronultenalin Ieaud VSUen uiuEccus0FhibrquertionGenWi Iku Iortiul:Ind nva Nred wuirroundedcuneeln tuolocing 4ugram?
question Wctis Ihe fst bockward differerce ol yln) to fnd out (he derivative 0 pwen function? O4 [n)*xln-IIT OB [yn *xn+tIIT [email protected](n)-vin+T)T OD lyin)-xln-IWVT QuESTION ? La cotlral Olenaka 'Cll # Io sepormaa Iha cothabye U A Rncuon @Olvnd moin urcunlo poaueta ! Zanmatn nronultenalin Ieaud VSUen...
1 answers
Find the value of $k$ such that the vectors u and $\mathbf{v}$ are orthogonal. $$\begin{aligned} &\mathbf{u}=-3 k \mathbf{i}+2 \mathbf{j}\\ &\mathbf{v}=-6 \mathbf{i} \end{aligned}$$
Find the value of $k$ such that the vectors u and $\mathbf{v}$ are orthogonal. $$\begin{aligned} &\mathbf{u}=-3 k \mathbf{i}+2 \mathbf{j}\\ &\mathbf{v}=-6 \mathbf{i} \end{aligned}$$...
5 answers
Solve the equation x? ydx + (v-x)dy =0.
Solve the equation x? ydx + (v-x)dy =0....
5 answers
W 8 L 3 [ I # 2 5" 1 4 8 & 1 8 3 8 ! 07 W 87 5 H F Ec? H 3 : 2 8 82 5 1 | 8 3 I 2 F 2 [ iL [
W 8 L 3 [ I # 2 5" 1 4 8 & 1 8 3 8 ! 07 W 87 5 H F Ec? H 3 : 2 8 82 5 1 | 8 3 I 2 F 2 [ iL [...
5 answers
1.) (a)The de Broglie wavelength of a traveling electron is 5x10-10 m. What is its velocity? (b) The momentum of the electron inpart (a) is measured with an uncertainty of 10%. If the position ofthis electron is measured to be at x= 2.37x 10-9 m, also with anuncertainty of 10%, does this violate Heisenberg’s uncertaintyprinciple? show your work.
1.) (a)The de Broglie wavelength of a traveling electron is 5 x10-10 m. What is its velocity? (b) The momentum of the electron in part (a) is measured with an uncertainty of 10%. If the position of this electron is measured to be at x= 2.37x 10-9 m, also with an uncertainty of 10%, does this violate...
5 answers
Question 13 ptsWhich statement does NOT describe properties of a proton?Hint:Atomic structure L video Textbook chapter 2 under "The Structure of the Atom"Protons are attracted to negatively-charged electronsProtons have an overall neutral chargeProtons are located within the nucleus of the atom A proton has a mass of approximately 1 dalton
Question 1 3 pts Which statement does NOT describe properties of a proton? Hint: Atomic structure L video Textbook chapter 2 under "The Structure of the Atom" Protons are attracted to negatively-charged electrons Protons have an overall neutral charge Protons are located within the nucleus...
5 answers
43.9 g spoon made of pure silver (specific heat = 0.235 J/g oC)at 20.1 oC is used to stir a 240.0 g cup of coffee at 91.2 oC. Whatis the final temperature of the coffee? (specific heat of coffee=4.18 J/g ï‚°C)
43.9 g spoon made of pure silver (specific heat = 0.235 J/g oC) at 20.1 oC is used to stir a 240.0 g cup of coffee at 91.2 oC. What is the final temperature of the coffee? (specific heat of coffee =4.18 J/g ï‚°C)...
5 answers
Table 2. Data Table (16 points)WaterPH after 1 PH after 1 mL mL 1OM 1OM HCI NaOH1M CH;COOH 1M NaCH;COO (additional) (in (in mL) (in mL) mL)Orig: pHPart Buffer50.0050.000.00Part | - A25.0025.00O.004.764.39Part ! - B25.0025.000.004.765.12Part Buffer50.00Part II - A25.00Part II - B25.00
Table 2. Data Table (16 points) Water PH after 1 PH after 1 mL mL 1OM 1OM HCI NaOH 1M CH;COOH 1M NaCH;COO (additional) (in (in mL) (in mL) mL) Orig: pH Part Buffer 50.00 50.00 0.00 Part | - A 25.00 25.00 O.00 4.76 4.39 Part ! - B 25.00 25.00 0.00 4.76 5.12 Part Buffer 50.00 Part II - A 25.00 Part II...
5 answers
A manufacturer of booklets packages them in boxes. It has been observed that the weight of a box is normally distributed with mean / and standard deviation 1.3 kilos. sample of n 13 boxes is randomly selected from the output of the machine on given day; and the weigh of each box is measured:Find numbers b1 and b2 such thatP (b1 < 82 < b2) = 0.90
A manufacturer of booklets packages them in boxes. It has been observed that the weight of a box is normally distributed with mean / and standard deviation 1.3 kilos. sample of n 13 boxes is randomly selected from the output of the machine on given day; and the weigh of each box is measured: Find nu...

-- 0.021337--