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Draw additional resonance structures for each anion....

Question

Draw additional resonance structures for each anion.

Draw additional resonance structures for each anion.



Answers

Draw additional resonance structures for each anion.

Let's begin by drawing the resident structures of this cat. I am so the first one that's pretty easy to see is to push a pie bond to satisfy the positive charge on this carbon. So the only way to draw resident structures is to push pylons or loan pairs of electrons so we can push one of these two pylons over and in to satisfy that positive charge. If we do that, push one pylon or long period of time and you conform a new resident structure. You could always push more than one pie bonder long pair to get a new one. But when you're asked to draw many, it's easiest just to push one arrow at a time. As long as you aren't breaking the octet rule. So what? It's this resident structure give us well, that now pushes the positive. It moves the positive charge to this carbon. The positive charged in itself moved. The electrons moved, but that's what gives us this structure. We can now satisfy the positive charge here, either by pushing this one pair back and giving us the resident structure we started with, or we can push from thie external olefin or the external double bond could be pushed in. And that gives us a new resident structure, and that resonance structure still has a positive charge. All of them will have positive charges throughout. Um, the next one we can draw is a little bit harder to see. But Egypt, these pylons could be moved to the opposite positions in the ring. You'LL see this a little bit later on. When you talk about aromatic systems, you can draw the other calculate structure. That's what that's called. So we didn't actually move anything with a positive charge, but we did move every pie bond in the ring to a different position. This is technically a different resident structure. We can now do the opposite of what we did here and push these electrons back out. That makes it different residence form, and we put a positive charge on the top Carbon. We haven't had a charge on that carbon yet, so that's a new residence for him. So here are the four other resident structures we could draw without adding any more charge. Therefore, the overall hybrid if we look so let's just look at this carbon here. It has a double bond double bond here it has a single here. It has a single. So in the overall residence form, this bond is going to be somewhere between a double bond in a single bond. Let's look at this one single, single, single, double single. So, again, this carbon carbon bond is going to be somewhere between a devil in a single bond. Do that with every atom to figure out what the overall residents hybrids gonna look like. And in this case, heh, every single Adam within the ring is going to be somewhere between a single and a double bond. So we typically kind of draw this almost in a circle fashion. We also have to add in the portion outside of the ring because we did push those electrons into the ring at one point in time. So that is somewhere between a single and a double bond. And then overall, there is some positive character

This is the answer to Chapter 11. Problem number nine, fromthe Smith Organic chemistry textbook. And this problem asks us to draw an additional resident structure for each cat eye on. Um And so one thing to notice here is that each of these cat ions um, each of these carbo cat ions is bound to a new electro negative Adam with a loan pair or more than one lone pair to spare. I mean, so all that we have to do is add uh, the electrons from one of these lone pairs into the bond between the carbon and the hetero Adam. Ah, and that will seat this positive charge on the Electra native Hetero Adam. Um, yeah. And so that's Ah, that's the resident structure. So for a that looks like this. So our chlorine eyes now down to two lone pairs, and it has a positive charge on it. So for be, it's gonna be the oxygen. So lone pair from the oxygen add in there to give us this structure. And now the positive charge is seated on the oxygen. The oxygen's down to one lone pair. Ah, and then similarly, for see, the nitrogen is lone pair can add in to the carbon nitrogen bond, which will take us to you. Here and now are the hoops. Can't forget the hydrogen. Never forget your hydrogen is on your nitrogen. Sze Um it is a pet peeve of every chemistry teacher and every chemistry grad student greater exam greater that I've ever met, including myself. Don't Don't forget, your hydrogen is on nitrogen sze. Um And so the positive charge is now seated on the nitrogen and the nitrogen, uh, no longer has a loan pair. Um and so these are all good resident structures. Um, it's always best to try to seat your charges on electro negative, Adams. And so chlorine, oxygen and nitrogen are all much more electro negative and carbon. So these air good residents structures. Um, And again, the key to doing this is to add in the lone pair of these adjacent Electra native Adams. Um, And that shifts the positive charge to the hetero Adam. And that's the answer to Chapter 11. Problem number nine

This is the answer to Chapter 17. Problem number 11 fromthe Smith Organic chemistry textbook. Ah, and this problem asks us to draw the four residents structures for anther scene. So, uh, here's the first structure. Um, And to get to next one, uh, we'll just move electrons around. And so our second structure is gonna look like this with double bonds here, here and here now. Okay, Um and so to get to our third structure, we'll move electrons like this, But this time, instead of just moving around the ring, uh, this double bond will move, uh, to the next ring. Um, and the double bonds and the next drink will move. And so our third structure is gonna look like this. Yeah. So the middle ring now has three bonds in it. Um, and our last structure is going to move one of those three bonds in the middle ring to the third ring. So our last structure looks like this. Okay. And that's Ah, the four residents structures for anther scene. Um, and again, we derived all four of them by just taking our starting structure, moving the three double bonds around that first ring. Um and then moving one to the next drink and moving bonds Middle ring around on, then moving one from the middle ring to third ring. Ah, and moving other bonds around to accommodate that. And that's the answer to Chapter 17 problem number 11.

Hello, everyone. Today we're doing Chapter 17 Problem eighteen's from assets to Jonah's seven resident structures of Tripoli. Um, carry on. So what we have here is a Triple A Mayan, but now it's has a positive charge is Carbon only has three bonds. So it's a Carvel. Katyn, begin with. And we know what resident structures will you distinguish between resident structured A double headed arrows. Resident structure is just the movement of electrons. You know, I'm really breaking any bond. You're making me, Bond. Just moving the the electrons around pretty much so we see here we have this pie bond that couldn't be moved down here. And if you were to move that high bond Now we see that we have that pie. Bonds all drawing blue moved down here. We have original ply bonds here and here and now the cartel count and also moved up here. So is one president structure the same time? This pylon over here to move over there. We'll do this in green, actually. So now we have another resident structure from the Carvel catching up here, and only that we can move around this coral cod and these pipe on electrons you more. So we're here. And I remember we serve the couple pennant directly on the bottom. Most bottom carbon. But if you were to repeat this process, move this pile on over here. You see, we actually don't end up with Carl Cat and that original carbon quite yet. We can still go around the ring. So now the karma canniness or the new Bip I want is down there on the couple Caddy on. They're right here on this car, so we still keep going. You can move now. This pipe on over here, We have a crime on here. I want here now. We decided. Pipe on there. So we get the car, Karen, up here, which is different than any structure, John. Stuff's far. You can jump one more resident structure to move that pie bond. Over here, we get the cover, Catherine, this carbon. And now, finally, if I were to move this pipe one over here and I would end up with my original compound again. We have seven resident structures for this molecule here.


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