Hey, everybody. So in this question we have a neutralization reaction between sulfuric acid and potassium hydroxide forming assault and water. So we're giving a few known, so I'll go ahead and write those down. We know that we have 25 mills of 0.5 Mueller sulfuric acid as well as 25 mills of potassium hydroxide, which is one Mueller. We also know that the starting temperature for this reaction, called a T subzero, is equal to 23.5 degrees Celsius, and the final temperature after the reaction is over is 30.17 degrees Celsius. Now the question asks us to find the change in entropy. So that is our Delta H. With these knowns and unknowns, we can go ahead and start solving for our entropy change. So to do that, the first thing I'm going to do is convert are starting materials into their respective Moeller values. And I'm gonna use these Moeller values to find the which one of them, which one of the reactant is the limiting reacted for the reaction when forming water. So for sulfuric acid, we're starting off with 25 mills and then we're going to convert that into leaders with our conversion factor and then using the U concentration that's given to us. So for one leader, there is to your 0.5 moles of sulfuric acid that gives us a 0.125 moles for sulfuric acid now going on to potassium hydroxide. We also start with 25. Mills will convert that to leaders. So there are 1000 middle leaders and one leader and were given a concentration of one mole per leader and that yields a 0.0 25 moles for potassium hydroxide. Now that we know that we can go ahead and use these initial moral values to find how much water will be produced to try to determine the limiting reactant. So go ahead and do that. We have zero point 0125 moles of sulfuric acid and using our balanced equation from above. We know that for every one mole, both of surface sulfuric acid, it will form two moles of water. Working this out in the calculator, we find that 0.25 moles of water will form using that amount of sulfuric acid now doing the same thing, but with the potassium hydroxide. So before we calculated 0.25 moles of potassium hydroxide and then using the balanced equation, we know for every one mole of potassium hydroxide, this will form one more of water. And I went ahead and simplified the fraction since in the equation it was to over two, and I just simplified that already 2 1/1 since that's how the ratio worked out. So that also yields a zero point 0 to 5 moles of H 20 Since both of them, you did the same amount of water. We can say that both of these will yield 0.25 mils of H 20 And we can use this value when we're calculating our heat. So moving on, we can go ahead and use our heat equation to calculate the heat absorbed by the calorie bitter. To do that, we'll use our equation. Q. For the calorie emitter, is he good? EMC Delta T where m is our mass see is the heat capacity and deep delta T is the change in temperature. We have all of those values. So for the mass, I'm going to use the total volume. So we started off 25 mils of both of each reactant. So that gives me a total of 50 mills of water produced. And I'm gonna go ahead and multiply this by the density of water. So that is one gram for one mill leader and that were you in my mass from the textbook. We know that the heat capacity is 4.184 jewels programs, degrees Celsius and the change of temperature. I'll go ahead and run in the second line since I'm running out of room is the final minus the initial. So we have the final temperature 30.17 degrees, and we're going to subtract that from 23.5, plugging all of this into the calculator, we find that the Q absorbed by the calorie motor is one 1003 195 jewels, and this is the same thing as saying 1.395 killer jewels. Now that we know that the heat from the calorie meter is this, we can say that the heat for the reaction is the negative of the heat absorbed from the calorie meter. Since the reaction is releasing heat. So this is negative 1.395 killer jewels And using this number, we can finally find our change in Anthill P. So don't h is equal to our heat that we just calculated negative 1.395 killer jewels. And we're going to divide that by the moles that we calculated above for water. So that is 0.25 moles of water. Plugging that into the calculator, we find that the heat of the entropy change. Excuse me, is negative. 55 0.8 killer jewels per mol H 20 and that is our final answer.