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Help me with this problemIn the city of Quetzaltenango on the morning of February 14 thethermometer shows 1°C. If the thermal gradient is approximately 1°Cfor...

Question

Help me with this problemIn the city of Quetzaltenango on the morning of February 14 thethermometer shows 1°C. If the thermal gradient is approximately 1°Cfor every 154 meters and the city of Quetzaltenango is 2800 metersabove sea level and the capital city is 1500 meters above sea level(masl), how much would the thermometer mark in Kelvin in thecapital city?

help me with this problem In the city of Quetzaltenango on the morning of February 14 the thermometer shows 1°C. If the thermal gradient is approximately 1°C for every 154 meters and the city of Quetzaltenango is 2800 meters above sea level and the capital city is 1500 meters above sea level (masl), how much would the thermometer mark in Kelvin in the capital city?



Answers

Temperature. According to NOAA, a "standard day" is $15^{\circ} \mathrm{C}$ at sea level, and every 500 -feet elevation above sea level corresponds to a 1 ' $\mathrm{C}$ temperature drop. Assuming the relationship between temperature and elevation is linear, write an equation that models this relationship. What is the expected temperature at 2500 feet on a "standard day"?

Alrighty. So the height of the Washington Monument, which was in the sketch here as this arbitrary monument just for the problem seek is measured to be 170. Ah, 170 meters on a day where the temperature is equal to 35 degrees Celsius. All right, now what happens on a day where I got my same monument temperature. It is very cold. Negative. 10 degrees Celsius. I want to know what my height is on this day. And although the monument is made of limestone, we're gonna assume that this coefficient of thermal expansion in this case is the same as marble. And let's do our best then to, ah, final answer and round it to five significant figures. All right, so let's give it a shot. Remember, you can refer to your textbook or online if you need to find the coefficient of thermal expansion. But when? Right up here, the same one for lime. Here is the same one for marble marble. And that equals 2.5 times 10 to the negative. Six degrees Celsius to the negative one. All right, so keep that in mind. We're gonna need that at some point here in a moment. So you find the changes in length of the Washington Monument, which we're going to define as a delta l changing my length. All right. And remember that for a linear expansion, you can actually relate your change in length. Um, while deployed by the initial length times, the coefficient of the thermal expansion multiplied by the change in temperature. So let's go ahead and plugging what we know and we'll get to a solution here. So tell tell the change in length is equal to 170 being the initial length times after more expansion coefficient. That's this number up here. Well deployed by the change in temperature, which is final minus initial negative. 10 of minus initial 35. Gonna plug all that in and, uh, get a delta l equal to negative 1.9125 times 10 to the negative two meters. Now that's a change in length. We want to figure out the final length. So what we're gonna do is from a Delta l Z the length final minus length initial. And now just solve this for your length final. So it's a delta l plus length initial equals length final we know dealt l is negative 1.9125 times 10 and negative and we know our length initial is honored 70 meters, which means we get a link final off 169 0.98 meters.

So the length of the Washington Monument is 1 70 meters, and when the temperature falls from 35 years to Afghanistan in the search, yes, that change in temperature. It's simply 45 Celsius now, Alfa for Marvel. And so to be to find 510 arm in six. So the change in the length is if you want a lot for Daddy. So that's 1 70 times 2.5 into 10 5 minus six. This is for any decisions, By the way, David thanks 45 degrees Celsius on this turns out to be 191 to 5 to £10 minus six. So that's 19 millimeters, so this is about 20 millimeters. So when you take that, when you make take the difference, the answer turns out to be 1 69.98 meters simples that

These questions, we want to evaluate by how much the hide off the a few power increases when the temperature changes from Trudy resells is to 25 degrees Celsius. For that, we should consider the eighth willpower as a much simple structure which is just a line off Iran. There is 300 meters high, So in order to evaluate the temple expansion, used his equation, which tells us that the variation in the length or in this case, the height is the coast to the expansion coefficient for Ireland, which is 12 times stand to minus six times they need shell length or, in this case height, which is 300 times the variation in the temperature, which is 25 miners. Truth and then we have 12 times 300 time stand to minus six times 23. These results in 0.8 28 which we can approximate true 0.83 and finally we can write it as 8.3 times stand to minus true meters. So these is the increase in the height off a four tower when its temperature changes prone to degrees Celsius to 25 degree Celsius. And this is also the answer to this question

So we want to convert 23 F two Celsius now. Actually, one of the questions that we previously answered gives us this formula. Ah, I believe it is Question eight. So question eight says C is equal to 5/9 F minus 32. So this is already in terms of see, So all we need to do is plug in 23 into here. So we're gonna have five nights, 23 of minus 32. So be five nights and then minus nine, the nines cancel out and we'd be left with negative by degrees Celsius.


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