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CH3HOCH3OHHo-CH3Which of the following is/ are chiral?B andAonlyAandand D0 B only...

Question

CH3HOCH3OHHo-CH3Which of the following is/ are chiral?B andAonlyAandand D0 B only

CH3 HO CH3 OH Ho- CH3 Which of the following is/ are chiral? B and Aonly Aand and D 0 B only



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Which organic structure among the following is not an isomer of the compound? $\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}=\mathrm{CHCH}_{2} \mathrm{CH}_{3}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$ (d) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CO}-\mathrm{CH}_{2} \mathrm{CH}_{3}$

So for questions for its asking which of the following compounds has a carbon that is asymmetric. So what that means is that the compound has a Cairo carbon and a Cairo carbon is a carbon that has four unique groups. So, I've already gone ahead and drawn all of the compounds as they were seen in the textbook. And we'll stay with them with question A. So, if we look at this carbon here, it is attached to an ethyl group, a methyl group, a chlorine and also hydrogen that's not shown. So, since this carbon has four unique groups attached to it, it is a Cairo carbon and therefore it's an asymmetric carbon, so A is asymmetric has an asymmetric carbon. B. This card was attached to three hydrogen, so it won't be Cairo this one has two hydrogen, so it won't be Cairo because of the staff for unique groups. So, if you look at this carbon here, it's attached to one ethyl group, but it is attached to to medical groups. and these two groups are identical. So it cannot have four unique groups. So B is not Cairo. So it does not have an asymmetric Carmen moving on to see this compound here. If we look at this carbon, it is attached to a methyl group, an ethyl group and also appropriate group. So three carbon chain in a bromine. So all of these four groups are unique. Therefore, this is an asymmetric carbon part D. This carbon is attached to 123 hydrogen. So this can't be asymmetric. This carbon is attached to hydrogen, so it can't be asymmetric because it cannot have 14 8 groups. So D. Is not and it does not have an asymmetric carbon. For E. If we look at this carbon here, yeah, is not Cairo because it is attached to two ethnic groups. Those groups are the same. So it cannot be attached to four unique groups. So E. Is not an asymmetric carbon. And, lastly, for F, if you look at this carbon here, it is attached to this carbon carbon double bond. Those ethnic groups is attached to a methyl group and N. H. Two and also hydrogen. That's not drawn. These four groups are unique, so therefore F has an asymmetric carbon. So the answer will be a see and, uh.

Cassidy Reza's aimed at covering some of the basics of chemistry, starting with subjects such as periodic trends and chemical properties, all of which underpinned the more advanced levels of chemistry. So what we're looking at today a stereo chemistry now where we will be deciding if we can assist Trans item is possible for the following structures. So the first example we have is one beauty. So this doesn't have any CIS. Trans is a MERS. Our next example we have to beauty and it has one sis and one trans Isom it so we'll draw that out now. So we have thesis to you, Teen, um, also up the trans. So for the next example, we have two missile protein and it doesn't have any sister Anzai summaries. Um, again, this is because two hydrogen atoms, one on the carbon atoms and in the double bond. So the next example we have is one chloral to beauty, so it has one trans. I smelt 16 chicken will draw out here. So Sis Iceman's have to similar or higher priority groups on the same side. So, for example, we have a chlorine on this beat style chain on the same side while I was with Trans. They're on opposite sides on. We have restricted rotation about the double bond due to the confirmation all locking that is generated from the bonded P orbital's that are in a pie relationship.

Hello. The question is which of the following compounds cancel both jim and civilization medicine. And also for the medicine. So in the first option with respect to this suitable bonding this molecule cancel G. I. Because hydrogen here hydrogen here all the groups, boundary groups are the thing and it can so also trigger consumerism and also Brooklyn medicine. This all fits will go here and just all born. This one will go here will go ahead. So we will get this comes home. Yes, for me. Yeah, we'll come watch and here. Okay well thanks so for this correct option and that the option with respect to the suitable bone cancelled and this molecule with respect to this energy molecule, it can also so how this alpha X will go here in this moment will come here. So CS three CS double home you ch theater and George this one. Right. So it is also correct. And that's the option with respect to the center. It cannot so deal this will be incorrect with respect to this molecule. Mm. Yeah. Yeah. This molecule will not stop. Problem. That is um because it do not have any fire. Yeah.

I look, motion is which of the following canceled. Your article is from brazil. So we know that so geometrical nationalism groupings would defend editor both bonded center. So this center have same groups. That means it cannot so deal the center help different groups hydrothermal and time higher prison any time there's like begins. So this center has also different grouping hydrogen, hydrogen. It cancelled. It will not soggy because buddha age groups are saying So we and the c cancel G8.


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