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A 1.2L buffer solution containing 1.73mol of protonic acid(c2H5COOH; Ka=1.3x10^-5) and 1.87mol of sodium propionate(C2H5COONa) what is the pH of this buffer after t...

Question

A 1.2L buffer solution containing 1.73mol of protonic acid(c2H5COOH; Ka=1.3x10^-5) and 1.87mol of sodium propionate(C2H5COONa) what is the pH of this buffer after the addition of0.49mol of NaOH. (Ka for propionic acid 1.3x10^-5) give answer intwo decimal places.

a 1.2L buffer solution containing 1.73mol of protonic acid (c2H5COOH; Ka=1.3x10^-5) and 1.87mol of sodium propionate (C2H5COONa) what is the pH of this buffer after the addition of 0.49mol of NaOH. (Ka for propionic acid 1.3x10^-5) give answer in two decimal places.



Answers

What is the $\mathrm{pH}$ of a buffer solution that is $0.10 \mathrm{M}$ propionic acid and $0.20 M$ sodium propionate?

While on 16.80 we have 0.10 motor of uh huh appropriate Connick acid with 0.20 Mueller of sodium, appropriate it and we want to find the ph of this buffer solution. So what we want to do is we just want to plug into our Henderson household back equation. I have written here and to find the PKK we just do negative blog of the K. A. Which I looked up from the table just 1.3 times 10 to the negative five plus the log of concentration of the conjugate base which you get from the so the appropriate made solution. Thank you. 0.20 moller divided by the concentration of the can't. You get acid which is to a 0.10 walter. So and you get that ph is 5.19 You want to 66 here. Nph You only count the six figures after the decimal. So this would be the correct answer.

So now we'll work on problem 28 from Chapter 17 and this problem. We're told that a buffer contain 0.15 moles of probiotic acid and 0.10 miles of sodium probe Propio eonni in 1.20 leaders. So I asked, What is the ph of this buffer so we can go ahead for Part one, we draw our K A, which is probiotic acid, which is 1.3 times 10 to the minus five, and then for part A. We see if a buffer so we can use the Henderson hostile black equation. So I write the P K, which is 4.89 plus the log of bass, which is 0.10 over acid, which is their 0.15 and we get a value of 4.71 Then, in part B were asked, what is the ph of the buffer after the addition of 0.1 Moles of Joh? So if we add a 0.1 moles of anyway H to this system, what's going to happen is that B base will increase by 0.1 moles in the acid will decrease by the same amount. So we put Ph Same P K plus the longer base of veracity. Now, since we had a strong base to produce more weak ass in, we have 0.11 for the bass and 0.1 for for the acid. No. Which gives us the value of 5.68 In the final part of this problem, Part C were asked, what is the ph of the buffer after the addition of 0.1 moles of H I. So we know that's your, uh h igh hydro biotic acid is a strong acid, so we're gonna have the reverse of part B. We're going to have an addition of 0.1 moles of acid, and we're going to have to take away from the base. So now, instead of 0.1 for the base, we're going 0.9 and 0.16 for the moles of acid. No, we do this calculation. We get 4.64

Some weak asset. H A personally dissociates into a minus and H three or close nest forms a buffer. If this buffer has a pH. Ah 3.35 when the concentration of H Bay is, is there a point to dollar the concentration of the mines near 0.15? Moller. We can calculate the PKK of HK using your hundreds and hostile Bach equation rear engines. You get P K A. Equals ph. Nine. It's the long, uh, the Cooper component concentration ratio, which is the combination of a minus over the concentration of H A. So we can put our numbers in here to get three point to be fine minus belong. Uh, there a 0.15 over 0.2. This is 3.35 minus negative, 0.1249 which is 3.4 seven fortnight. I say we heard 0.15 moles of any average to 0.5 leaders of this book risk Lucien. We can calculate the concentration of any which since polarity it snows over leaders so we can divine 0.15 moles by 0.5 liters get to your 0.3 Miller, any which some were the weak acid from the buffer will react with hydroxide ions for meat added any wage to form water and conjugal peace. Since hydroxide isn't strong base, it will fully react with the weak acid, which is why this is a single forward arrow, some weak. So now we can set up an ice table. Initially, we have 0.2000 more h A 0.3 Moeller o h minus from the added any wage 0.1500 Moeller a minus. Liquids are included in these calculations, so we can just ignore water here. Defend the change. This is a complete reaction, so whatever can react on the left side will. So all of this voyage minus will rear, so the change is going to be negative. 0.0 free Moeller. I think there's a 1 to 1 ratio of boy dryness, too. A j. We will react. The same amount of the A J is the O. H. Minus, so minus their appoints. Here's your three more and again since there was a one tourney ratio of voyage minus two a minus. Uh, the amount of village minus that is being reactive is going to for that amount of a minus. So the change here is plus 0.0 or three more. The equilibrium are the end is then just the initial across the channel. So here, zero point one known 70 moller for aging zero Moeller her O. H minus and 0.153 moller for a minus. We now have thes final concentrations of H A and A minus. So we console for the final pH using the Henderson Hasselbach equation again. So here we plug in our previously calculated PK. Since that doesn't change 3.4749 plus the log of accounts, the new concentration of a minus. So 0.1530 divided about the new concentration of each day. Sarah, 0.1970 some week asked. This is 3.47 for nine minus 0.1098 which is equal to 3.3651 with correct significant figures. This is 3.37 in just a double check. We started with a pH of 2.35 and ended with one of 3.37 That means the page increased, which makes sense since we added piece.

Will be sold for this question. By using a region be it is equal to minus law. Okay, a plus look. Sold. Fried by s it. So we have here to find b itch. So putting values minus look milieu off K A. Yes, he is one point tree multiply and raised to the power minus tree three. Bless. Look, let's look Moleketi of is it is, um polarity off soul is zero point 100 and as it is little going to 00 moral energy, it is equal to minus log. Get Yeah, is it will do Group point it bless. Bless you. Look, Is it a point? One digital divide by 0.0 is equal to minus You don't going three be inch will do. Who? 0.8 That's minus minus. Whose it'll going free and to be here He is really busy. Little good clean life


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