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In each reaction box, place the best reagent and conditions from the list below:2) 3)4)Answer Bank(CH,) 2 CHBrPCCNaBH4H,O,HzotKMnO4BH; THFH,NCH(CH;) 2, pH 5,Hz, PdC...

Question

In each reaction box, place the best reagent and conditions from the list below:2) 3)4)Answer Bank(CH,) 2 CHBrPCCNaBH4H,O,HzotKMnO4BH; THFH,NCH(CH;) 2, pH 5,Hz, PdCH;BrHN(CHz" CH;)2' pH 5, Hz, PdNaNH2HzOz, NaOH,HzOCrOz, HzotCH;NHzPd, HzNH;

In each reaction box, place the best reagent and conditions from the list below: 2) 3) 4) Answer Bank (CH,) 2 CHBr PCC NaBH4 H,O,Hzot KMnO4 BH; THF H,NCH(CH;) 2, pH 5,Hz, Pd CH;Br HN(CHz" CH;)2' pH 5, Hz, Pd NaNH2 HzOz, NaOH,HzO CrOz, Hzot CH;NHz Pd, Hz NH;



Answers

Choose the best reagent to carry out the following sequence of reaction $\begin{array}{ll}\text { (a) Acetylene/ } \mathrm{NaNH}_{2} / \mathrm{NH}_{3} \mathrm{H}_{2} / \mathrm{Pd} & \mathrm{OsO}_{4} / \mathrm{NaHSO}_{3}\end{array}$ (b) Acetylene/NaNH $_{2} / \mathrm{NH}_{3} \mathrm{H}_{2} /$ Lindlar's catalyst $\quad \mathrm{BH}_{3} / \mathrm{NaOH} / \mathrm{H}_{2} \mathrm{O}_{2}$ (c) Pentyne/ $\mathrm{NaNH}_{2} / \mathrm{NH}_{3} \mathrm{Li} / \mathrm{NH}_{3}$ $\mathrm{MnO}_{4}$ $\begin{array}{ll}\text { (d) Pentyne/NaNH }_{2} / \mathrm{NH}_{3} \mathrm{H}_{2} / \text { Lindlar's catalyst } & \mathrm{OsO}_{4} / \mathrm{NaHSO}_{3}\end{array}$

And problem, 9.23 were told to start with five that kind and react with the region's given for each part and give the products in part. A. We're reducing the triple bond to a couple bond with hydrogen and delimar Catalyst, and this will give us, uh, double bond and sis position. So now we have trance. We have sis five that keen. Now let's look at Part B and part B. The lithium is going to donate electrons and ammonia is going to donate Proton, and this is how we will reduce this triple bond. Teoh a double bond. The double bond will be in transposition, and a double bond is on carbon five. So now we have Trans, too. If Trans five that came, that came. And just remember that the landmark Alice always gives you assist Double bond and that within ammonia will always give you trans. And now, for part C, we have one equivalent of Romain and we are reacting this with our five deck kind. So this will give us a trans molecule with roaming on each side of the double bond. So here we have Trans 56 Deborah M. 06 checking the king in Part D were reacting five deck kind with more rain and peroxide in the base. This would normally give the non Markov nick off product, but since each side has the same substitution for the carbons, it will not matter whether it's my comic off or non my company cough, and this reaction will only give one product. Because of the location of the triple bond, we are going to have a key tone on carbon five. Now let's look at Part E. Part E. We have the regions that would normally give the McCartney cough product, But again, we're going to get the same product as Part D because of the location of the triple bond. Now, in part F, we're reducing with excess hydrogen and using a palladium catalyst with carbon, Harman normally tends to maximize the surface area in part F. We are going to reduce the triple bond all the way to a single bond and just have decade as our final product. And this is the final answer to this problem

In this problem, the reaction will be happened. Something like this. Just look at it carefully. This compound in Belgian, so BCC in right CH two CL two will produce the product badge. This compound will produce the productive this compound. So according to the option in this problem, obstinacy it. Correct answer option C. H. Got it. Dancer for this problem.

Hi everyone. So in this question they ask of which of the following region can worse. One built into eternal in greater scale. So one is or three's RNS Toby's H plus esto then sees one XZ or two CCS three dice esto to an NBA follow H minus B one B H three K H. A. Pesto to H +202 H minus. So in this case you know options he is correct. So one built in to be done in greatest need is formed due to the re agent first Z. 026 years three twice uh water and second in aviation or H minus. Love. This can be easily a chill. It can be okay. Oh thank. Mhm. Bye. You think? Mhm. Oxy marquis aeration. Oxy regulation. Be more regulation. Yeah. Yeah manipulation. If mark conical product is near ready. If marconi called of course. Oh. Mhm product is necessary. Nice. This study. Thanks a lot.

Question is complete. Each of these reactions by filling in the blanks predicted whether it's reaction is product, favor or react in favor. And explain your reasoning of the So we are going to discuss how can we identify which direction will favor in the given reactions. So in the first part of the question we have less. We are minus equilibrium. And that's three plus SBR Okay. So what is the missing regent? Missing Regent will be and it's four plus iron. Right. Because this attribute Danek it's X plus and ammonia will gain that X plus and convert into ammonium I to identify the direction we have to observe that which has I speak a venue. So here this is answered And here this is Esther NH four plus I am have very high pick a venue but as we are has very less He gave a look. So reaction will favor in react and side in the tank side. Because of peak evil league of ammonium iron is very very high. Inbee Park we help acidic plus C and minus. If this ascetic acid released its X plus then we will get at CNN plus acetate. I now observe carefully. This is Esther here and this is the answer. So which has the highest peak value at sea and have high, pick a value. Then pick a value of ascetic acid. So three equilibrium will go in product side in product side. Okay in Cpac we help plus at school equilibrium and at three plus over two minus this porch minus will abstract edge plus from ammonia. So this is a city and we will get here. NH two minus iron and vegetable in this reaction is acid here. So we know that PK value of ammonia is higher than pick a value of water. So reaction will go in product side in product say because he gave value of ammonia is higher than became a value of water. Okay.


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