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At time t = 0 second, a student release an object from rest atthe top of a tall building. At the time t0, a second object isdropped from the same point. Ignoring th...

Question

At time t = 0 second, a student release an object from rest atthe top of a tall building. At the time t0, a second object isdropped from the same point. Ignoring the effect of air resistanceon the two objects, what is the ratio for the speeds for the twoobjects to have a vertical separation l=4.0 meter when the delaytime is t0 = 0.78 seconds? a) ratio of speeds is 3 b) ratio ofspeeds is 5 c) ratio of speeds is 7 d) ratio of speeds is 9 e) noneof the above

At time t = 0 second, a student release an object from rest at the top of a tall building. At the time t0, a second object is dropped from the same point. Ignoring the effect of air resistance on the two objects, what is the ratio for the speeds for the two objects to have a vertical separation l=4.0 meter when the delay time is t0 = 0.78 seconds? a) ratio of speeds is 3 b) ratio of speeds is 5 c) ratio of speeds is 7 d) ratio of speeds is 9 e) none of the above



Answers

Two bodies are thrown vertically upwards from walls of heights $2.2 \mathrm{~m}$ and $1.05 \mathrm{~m}$ respectively, with an initial velocity of $10 \mathrm{~m} \mathrm{~s}^{-1}$. The ratio of their times of flight is $\left(\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2}\right)$ (a) $\frac{22}{21}$ (b) $\frac{12}{11}$ (c) $\frac{44}{23}$ (d) $\frac{13}{11}$

In this situation, it is given that the ball is dropped from rest from the top of a 40 m building and a second ball is strong downward. One second letter. So let this is the building and the ball is dropped from this building from rest, so its initial velocity is zero After one second another ball is brought. Let it initial velocities human, which we have to find. And the height of the building is given to us, that is 40 m. Oh for the first part we have given data that is for first of all, initial velocity, U. Is zero and displacement as is 40 m. So first of all, I am calculating the time taken by this vegetable to reach the bottom of the building, so by equation of motion as equals to U. T. Plus half duty square over here. S. S. 40. This is your A plus half into 10 into peace. Where from here we get the time T. That is 2.828 seconds. So this is the time taken by the first ball to reach the bottom of the building. Now it is told that second ball is dropped after one second, so second ball is thrown after one second and it will reach the ground at the same time. So it has to cover the same distance in 1.828 seconds. So for second world time is 2.828 minus one, That is 1.828 seconds. So it has to cover the distance in 1.828 seconds, for which we have to find its initial velocity. So, from equation of motion as is equal to U. T. Last half. Gt square here. S. Is 40. You will have to find these. 1.828 That's half G sten. And please, 1.828 whole square from here we get initial velocity Youtube. That is one that is 12.7 m per second. So the 50 velocity of the second ball by which it is dropped. So this is the answer of our question. Fuck! Now! In the second part we have to find the issue of the speed of the throne ball to the speed of the other when they hit the ground. So first of all we have to calculate the velocity of these balls when they hit the ground. So first of all, and calculating the final velocity of first of all. Mhm. Or which I am using equation of motion, which this B equals two. You plus gT. Now put all the data in this equation so initial velocity U. Is zero plus then into time taking this 2.828 So here we can. Final velocity that is the one is equals to 28.28 m per second. This is the velocity of first of all by which it hits the ground. Similarly for second ball again using the equation of motion, we two is equal to youtube plus jean two T. Here we do. Is the velocity of the second ball by which it hits the ground. You too, is this initial velocity which we had already calculated? That is 12.7? Yes, this is 10 into nine point sorry, turning to this is time, which is 1.828 After following this, we get we do that is 30.98 meter per second. So this is the velocity of the second ball by which it hits the ground. Now we have to find the ratio of these two. So we even by way too is equals two. We have to find the two by everyone, so we do 30.98 device. This is 28.28 so this issue becomes 1.1. But this is the final answer of this fusion. Thank you.

Okay a ball is thrown downward so its initial speed is V. Sub zero. Um But that is a negative number from a height eight. Okay what is the speed just before it hits the ground? Um V squared is V zero squared um Plus two G. H. So V is going to equal the square root of V zero squared plus two G. H. B. How long is that gonna take? Well um V equals V. Zero um minus G. T. So try and thinking about my signs here. Um I don't think I'm gonna go with this as being a negative number. So V is going to be a greater the positive direction is downward so it will be greater than V. Zero. So that would be plus GT. So now uh t is going to be V minus V zero over G. See. Mhm. What would they be if it was thrown upward? Um interesting. Well if it was thrown upward then in part a it would have to reach zero first and then come back down. Um But wait a minute the speed would be the same same. Um Here uh T is going to be, well let's let's go back to this V. Is going to equal the opposite of V. Zero plus GT. And so time would be Mhm. The plus V. Zero over G. Okay good. Um Mhm. And V. Is a squared of V. Zero squared plus two D. H. Okay so she should be the same as A. And D. Should be greater Then be thank you for watching.

So here we have the first object. This is thrown five meters per second downwards and we have the second object. We have 10 meters per second upwards. No acceleration is always down and so we can say that then the change in the velocity would be equal to the acceleration multiplied. By the time interval. This would be negative 9.8 meters per second squared multiplied by two seconds, equaling than negative 19 0.6 meters per second. Both objects experience the same change in velocity. However, here we can say that the first object after the two seconds would then be going 24.6 meters per second downwards while the second object would be traveling upwards and then reach in Apex and then travel downwards. So the second object would then be traveling 9.6 meters per second downwards. So if that's the case, the change in speed for the second object is from 10 meters per second against speed is the magnitude, so it doesn't matter if it's traveling upwards or downwards to 9.6, so 0.4 and then for the first would be five meters per second to 24.6. So 19.6. And so we can say that. Then the answer. A the first object experience a experiences a greater ah, change in speed. Both objects again experience the same change in velocity. That is the end of the solution. Thank you for watching.

Distance traveled by anybody in free fall at any instant. And at second This will be equals two. A divided by two multiplied with two and -1. There is the acceleration and is the time. So we need to find out the distance table by a body falling freely from raised in 1st, 2nd and 3rd seconds. So any schools too? One, two and three. So we need to determine the issue of S. One is to is to is to S. Three. So as one, Bill V equals two A divided by two Multiplied with two multiplied well 1 -1. Similarly as two will be equals two. Innovated by two. Two multiplied were 2 -1. And those three will be equals two anybody ever to To multiple to 3 -1. This is equals two, 1800 or two. This is equals two. Here divided by two and this is equal to why were divided where to. So we can easily say that ratio of S. One to S. Two to S. Three. Yeah, This will be equals two. This will be equal to one is two threes 25 please. So let us take the option. So option B is correct. We'll soon be is correct.


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