Gre the {elstion NJp betvcth pJir: Aacelblc rcltonahidaie conecordounc' comtulom Lrxeutatsam-m OcmsictcrIxerCH_CH CH CH CH; and CHa_ CH-CH_CHCHsBrBrC=CandH-C-...

licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

Among the given options, among the given options in this problem, among the given options in this problem, DIF six or 2 -2 TIF 6 to minus and see you, too. Sierra two added. The out of the colorless at the colorless spaces are particularly spaces, so according to the absence year option B. H. Correct answer.

Correct about this point. It is the careful minus right? So in this compound, believing them is that In the last two state, So electronics conclusion will be 58 and pairing will be possible after the hearing. It electron will look like correct. So electronic conclusion this one to be as people, there's the hybrid zero Electronic, they decided to humanity bankruptcy.

And so for the given question, we have a session, given position is Gcl too and SNCf to exist together in equal solution. The reason for this, Given ization is on heating GCS to supply times. So here we have the correct option for the given statement is the option D exertion is falls, but the reason is two. So here we will write the correct assertion for the given reason. So correct position is Gcl too, and SNC and two cannot exists cannot exist together in a glass solution. And the reason is here on heating. Yeah, Gcl too. Sublime songs. So here is false and but are is true. So the correct position is GCL to end. SNC cannot exist together in a solution.

So any problem 1 75 of chapter six compounds of P block elements to so in this question, majesty following. Uh so uh 40 xenon cetera fluoride, which is xia for So this is the structure of the non tetra fluoride as seen on having the eight valence electron. And uh out of these four are the bond peers and involved and who are the lone lone pairs? So these are the long pair of electrons. So that makes uh it's a scare planner. So it has four bond pair and too long beard. So that makes, its hybridization is basically sp three due to. Okay, so uh shape is this carefully? Okay, so next is the non hexafluoride. X. EF six. So this is the structure in which six bond pair and one lone pair. So this is distorted Octa federal. And makes its hybridization sp three D three. So it's hybridization is sp three D three and its shape is distorted of capital. So the next is ex ceo three. So this is the pyramidal shape and then we have XC offer and this is the battleship. So therefore the correct match becomes for a. That is much with the R. For be that much with the B. Foresee, that is S. And for the that is your