This question asks us to convert the values of casing the values of K p or the values of K P to the values of Casey. And so therefore, parts of broken them up in the individual slides. Speaking with part, eh? Here we have sealed to and b r two going to be our C. L tells us that the equilibrium concept perspective concentration is 4.7 times 10 to the negative second at 25 degrees Celsius. So then we're gonna be converting this to KP or the equilibrium constant with respect to pressure. So that equation looks like this k p equals K. C. Times are the ideal gas constant times t the temperature raised to delta end, which is the change in the number of moles in the reaction as it's written. And so this is how you find that Delta and equals the number of moles of gas and product minus the number of moles of gas and reacted. And so if there are two moles of gas in the products and there are two moles of gas in the reactant ce one here and one here, So to total, that means the Delta and is zero. And so now we can plug in each of the pieces Casey was given to us in the question. The ideal gas constant. It's 0.8 to 06 The temperature in Kelvin is 298 and Delta is zero. And, you know, when you raise something to the zero power, this whole thing becomes one. So now KP actually just equals Casey or 4.7 times 10 to the negative. Second you go. And for B, we have s 02 and no to going to s 03 This time it gives us KP the equilibrium constant with respect to pressure at 500 degrees Celsius. And so it's similar setup. But the equation looks a little bit different to find Casey, since we're given KP, that equals KP, divided by Artie Delta and so delta and again, number of bowls a product to most of gas and products minus the number of bowls of gasoline. Actives There three here. So two months three is negative one you can plug in all of our parts. K c equals K P was given to us 48.2 divided by the ideal gas. Constant times. The temperature, which says 500 degree Celsius converted to Calvin, is 773 raised to the negative one, and this is 3.6 at times 10 to the third. That's Casey. Here we have see a seal to with six waters around it, going to see a seal to, and Water tells us KP is five points here nine times 10 to the negative, 44th and Delta end. Number of bulls in of gas and products. They're six, and there are no Mel's of gas and reactant. So Delta is going to equal six. Now we're gonna do again. Casey to KP. I'm sorry. Calculating Casey from K P. That's KP over. Artie dealt, and we can plug in all of the pieces now 5.9 times 10 and they get a 44th. Was KP given to us by the by 0.206 times the temperature it was 25 converted to Calvin to 98 raised a delta and which we just have a six and this is too 0.3 eight times 10 the negative. 52nd. That is Casey for this reaction. And finally, we have each to a liquid. Going to each to a gas tells us KP is 0.0 point 196 at 60 degrees Celsius Delta end. There's one mole of gas in the products and none in the reactors and said one minus. Here was one you. Same question we did for Parts B and C So K C equals 0.196 divided by 0.206 times the temperature now in Kelvin, 333 raised to the delta and which is one. And this is 7.17 times 10 to the negative. Third, that is Casey for this reaction.