Question
And Cnd nonzeco stated ce Ene 4ne acrrncrz excect_Whece 5025 ~2 C3) is inderfied ~ndeckoe4h 4S adenecned 8 f( 5 R)Cs) L" 2465 03) 20 take check Khle mce €Cx) 8k-L)s/3 Sx2 +3 has_inflectio Qoints 4f
and Cnd nonzeco stated ce Ene 4ne acrrncrz excect_Whece 5025 ~2 C3) is inderfied ~ndeckoe4h 4S adenecned 8 f( 5 R)Cs) L" 2465 03) 20 take check Khle mce €Cx) 8k-L)s/3 Sx2 +3 has_inflectio Qoints 4f
Answers
In the following quesrions rwo statcmenrs (Asscrtion) (A) and Rcason (R) are givcn. Mark (a) If borh $A$ and $R$ arc corrcct and $R$ is the corcct cxplanation of $A$ (b) If both $A$ and $R$ arc corrccr bur $R$ is nor the corrcer cxplanation of $A$ (c) $\mathrm{A}$ is rruc bur $\mathrm{R}$ is false (d) $\mathrm{A}$ is false bur $\mathrm{R}$ is rruc. (c) $\mathrm{A}$ and $\mathrm{R}$ horh are false (A): $\mathrm{NO}_{3}$ is planar while $\mathrm{N} 11_{3}$ is pyramidal. (R): $\mathrm{N}$ in $\mathrm{NO}_{3}$ is $\mathrm{s} \mathrm{p}^{2}$ and in $\mathrm{N} 1 \mathrm{t}_{3}$ it is $\mathrm{sp}^{3}$ hybridiscel.
I haven't even so in this question. Amongst the following elements. So that is which is electronic configuration are given the correct increasing order of finalization energies. one is any creates 2 3 p one Second AIDS and he crashed 2 3 p three. Third is any three S 23 P two Then organ 3 10 4- four p. 3. So it's a third smaller than one, smaller than second, smaller than fourth. These poor smaller than second. Smaller than third, smaller than one sees. I smarter than three. Smaller than four. Smaller than two beads. Uh Second greater than four. Smaller than one. Smaller than three. So option. See is correct. Yeah. Of shadow. See is cut a check. Yeah that is yeah, correct. Increasing older by innovation Energy is correct. Increasing all of that off. Yeah, ionization energy is Yeah. Oh, one smaller than mhm. Three Smalling than four. Smalling than two. Okay. Yeah. Second heads. Yeah. Second hats, smaller sites. Yeah. Uh Second hats, Yeah. Highest ionization energy. Yeah. I yeste organization. A note she compared to fourth government bailed 24 because of, yeah, small atomic sites In comparison to four. Yeah. Years fault. Thanks.
But here we need to computer reaction. So it is L. two and so forth. All three 13 is too disappointed present. And the presence of Us too, This will provide product which is there wouldn't be policy. So here we need to identify abc. So let's write the reaction. The reaction will be like this area too and so forth. All three A teenage too. On here. On here and in the presence of water will give here too. L. two, s. 0. 4 3 One further hitting at 800° and figure it will give able to 43 There's three times of school. Uh huh. We can identify our product. This is Mhm. This is B. And this is C. And so we see that option A. Is that it?
In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.
As we know that as both and to end an A plus do not have, do not have any unfairly locked on any UNP aired electrons, and they are die magnetic. Hence they are die magnetic. Therefore, according to the option option B each correct both and to an an A. Plus do not have any unpaid electron, and they are die magnetic in nature.