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Find matrix X such that AX= B_^ [;#k-[::-] Find matrix X such that AX = B3 Select the correct choice below and, if necessary; fill in the answer box t0 complete you...

Question

Find matrix X such that AX= B_^ [;#k-[::-] Find matrix X such that AX = B3 Select the correct choice below and, if necessary; fill in the answer box t0 complete your choice_0 A. X=The matrix i5 not invertible and therefore there i5 no matrix X

Find matrix X such that AX= B_ ^ [;#k-[::-] Find matrix X such that AX = B3 Select the correct choice below and, if necessary; fill in the answer box t0 complete your choice_ 0 A. X= The matrix i5 not invertible and therefore there i5 no matrix X



Answers

In each of the following, find matrices $A, x$, and $b$ such that the given system of linear equations can be expressed as the single matrix equation $A x=b$. $\left.\begin{array}{r}2 x_{1}-3 x_{2}+5 x_{3}=7 \\ \text { (a) } 9 x_{1}-x_{2}+x_{3}=-1 \\ x_{1}+5 x_{2}+4 x_{3}=0\end{array}\right\}$

Okay, so we've been asked to find matrices A. X. And be such that the given system of linear equations can be expressed as the single matrix equation A. X equals B. So in the matrix equation X equals B. A. Is a matrix of coefficients. So they will look something like this. The three coefficients of the first equation which will call a one A. Two and A three. For now The coherence of the second equation which will call B1, You too and B. Three. And then the coefficients of the third equation, which will call C1, C two and C. Three. So what will these be equivalent to? So our first coefficient of our first equation. This will correspond this so that will just be too over there. Then this will correspond to this, That will be -3. Since it's a minus sign over there, this will correspond to this, This will be five. And we'll continue doing that for the Matrix B one correspond to nine. You too will correspond to -1. The three will correspond to positive one X one As you can see has no coefficient. So that means that they will just be a one for c. one And you see a five positive 5 for c. two And then you see a positive four for c. three. So that is your matrix A. Then your matrix X. We'll just be however many X values there are in each matrix equation. So that will just be X one, X two and X three. Since you see there are three unknowns in each part of the equation. So that's what your ex will be. And then lastly your B is the solution component. So for each equation there will be one number corresponding to what the solution of each equation is. B. The equivalent to. Well the first equation As a solution of seven, The second equation has a solution of negative one, and the third equation has a solution of zero, and those are your a x n B values corresponding two matrix equation.

Okay, so we've been asked to find matrices A. X. And be such that the given system of linear equations can be expressed as the single matrix equation A. X equals B. So in the matrix equation X equals B. A. Is a matrix of coefficients. So they will look something like this. The three coefficients of the first equation which will call a one A. Two and A three. For now The coherence of the second equation which will call B1, You too and B. Three. And then the coefficients of the third equation, which will call C1, C two and C. Three. So what will these be equivalent to? So our first coefficient of our first equation. This will correspond this so that will just be too over there. Then this will correspond to this, That will be -3. Since it's a minus sign over there, this will correspond to this, This will be five. And we'll continue doing that for the Matrix B one correspond to nine. You too will correspond to -1. The three will correspond to positive one X one As you can see has no coefficient. So that means that they will just be a one for c. one And you see a five positive 5 for c. two And then you see a positive four for c. three. So that is your matrix A. Then your matrix X. We'll just be however many X values there are in each matrix equation. So that will just be X one, X two and X three. Since you see there are three unknowns in each part of the equation. So that's what your ex will be. And then lastly your B is the solution component. So for each equation there will be one number corresponding to what the solution of each equation is. B. The equivalent to. Well the first equation As a solution of seven, The second equation has a solution of negative one, and the third equation has a solution of zero, and those are your a x n B values corresponding two matrix equation.

Okay, so we've been asked to find matrices A. X. And be such that the given system of linear equations can be expressed as the single matrix equation A. X equals B. So in the matrix equation X equals B. A. Is a matrix of coefficients. So they will look something like this. The three coefficients of the first equation which will call a one A. Two and A three. For now The coherence of the second equation which will call B1, You too and B. Three. And then the coefficients of the third equation, which will call C1, C two and C. Three. So what will these be equivalent to? So our first coefficient of our first equation. This will correspond this so that will just be too over there. Then this will correspond to this, That will be -3. Since it's a minus sign over there, this will correspond to this, This will be five. And we'll continue doing that for the Matrix B one correspond to nine. You too will correspond to -1. The three will correspond to positive one X one As you can see has no coefficient. So that means that they will just be a one for c. one And you see a five positive 5 for c. two And then you see a positive four for c. three. So that is your matrix A. Then your matrix X. We'll just be however many X values there are in each matrix equation. So that will just be X one, X two and X three. Since you see there are three unknowns in each part of the equation. So that's what your ex will be. And then lastly your B is the solution component. So for each equation there will be one number corresponding to what the solution of each equation is. B. The equivalent to. Well the first equation As a solution of seven, The second equation has a solution of negative one, and the third equation has a solution of zero, and those are your a x n B values corresponding two matrix equation.


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