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Question 15 (8 points) Find the unknown emf; €?T36V 403n206Av-4V~ 4VT -12 V12 V-16 V...

Question

Question 15 (8 points) Find the unknown emf; €?T36V 403n206Av-4V~ 4VT -12 V12 V-16 V

Question 15 (8 points) Find the unknown emf; €? T36V 40 3n 20 6Av -4V ~ 4V T -12 V 12 V -16 V



Answers

Find the unknown emf and the unknown currents in the circuit.

Hi in the given problem here there is a multi loop circuit. The first group is having A resistance of 6.000. And it is carrying a current 1.00 and p here in upward direction, it is also carrying a battery is also having a battery of unknown MF. So this is first to the middle branch is having A resistance 4.00 own the current I passing through it and a battery Of'em 425V. Finally the second loop is closed by And then the resistance having a value of 10. The value of this resistance is not given to us. We have to find it. This is our to unknown resistance. And the current passing through this resistance has been given as 10 Ampere. So here the E M F. And the resistance. These two are unknown. Which we have to find naming of the loop B. See the E. F. First of all, we will apply. Get jobs current law at the junction. C. So using get jobs current law at the junction. See Here the currents of one ampere and 10 mps are entering. So these will be edit to give the current I passing to the middle branch. So this current I comes out to be 11.0. And here now we will apply. Get jobs blue rule in the close to loop E. The see F. A. Here in this first loop. If we apply. So using the sign convention for the potential drop and the IMF of this luke, This potential rob six into one will be taking place in clockwise direction. So positive then for into why that is also positive. This E M f will be sending its current in counterclockwise direction. So will be taken as a negative while 1 25 will be sending its current in clockwise direction, so will be taken as positive. And the rule says algebraic sum of all the potential robs is equal to algebraic sum of all the mm so it becomes six into one plus four, I is equal to -10, which is unknown Plus 125, so this minus epsilon is equal to 6-plus 4 into 11. We have already found the value of this current I And -025. So here it comes out to be -75. Bold Or we can say there's a known EMF is 75V. One of the answers for this problem. Now we have to find resistance and non resistance in the second law. So now applying get jobs low rule in the closed loop. See D E fc If you look for the sign conventions here. Also, this is then into our and do clockwise counterclockwise. So will be taken as negative This I into four. That is also counter clock by so again negative 125 world. This is also negative. So here it becomes minus. For I my understanding to our Is equal to -125. Now we know the value of this, taking this negative common four into 11 plus and our It's going to -125, canceling this minus sign, It becomes 44 plus 10. R. is equal 225. So finally 10 are is equal to 125 -44, which is a. Even so finally this unknown resistance is 8.1 Home. Second answer for this given problem. Thank you.

Mhm to find the unknown current. So that's the current that is going through the full registered equals. I won. Yeah, and current flowing to the five on register is I. So we have I equals I want minus 0.5 ampere. So zero it waas e minus one home times I wan plus 1.2 volts minus four home times. I won minus two own time. 0.5 amp It's the other loop law that so this is one of them. The second one will be Siddle equals E or Josh. Five times I, minus one voltage minus two times 0.5 amp on the third will be zero equals e minus 1.1 divulge plus five times I now solving this, we find it's quick, I It was 0.195 AM and got in through the photo of register, which is I wan. It was 0.245 ampere to the right or from the right. So this is right toe left on the current strains. The five registries Yeah, bottom toe up and the e M F E equals 0.13

Current in this branch is one AM current in this AM piece 10 amp in this direction. So the current in the central bronze should be 21 and then the ones again, one amp and again. And now that's right. Car shops, law and they slope. We would have okay that he's, uh, 1 25 volt in this direction. So if we go in this direction first, a potential gain the 1 25 fold minus the second undone battery. What's then the potential drop six home dying swan. Um, minus the put in shares. Drop four, sometimes 21 equals zero. So that gives e equals 1 25 minus six minus 84 35 votes. So we found what is E. Now let's do loop in this direction in the second case after this to it in the opposite direction last week in this direction. So voltage gain is 1 25 Yeah, minus 10. Them times are minus four times 21 equals zero. We get 10 are Hi. It was 1 25 minus 84. It was 25 plus 16 ease. 41 home. So our it was 4.1. Oh, okay. There was a mistake over here. This should be either. Evan, I am. So that should be either. Evan. So four days there in these 44 So 1 25 minus 50 comes out to be 75 volt and similar. The this is four times 11 equals 44. Wondered for minutes 44 equals 81 home. So 81/10 8 point run off.

High in the given problem, there is a multi loop circuit having various sources of EMF and various resistors. This is 22. All this battery is having an unknown mm. Then the middle branch of the circuit Is having a resistance of 56 home. Then here this is another battery Providing a potential of 1.00 volt. And at last this resistance Having a value of 75 homes. The current Ivan coming out of this battery of a non mmf Current I two. Coming out of this one, volt battery. You're the terminals, A, B, C, and D and E and F. So this current, these two currents I one and I too will be combined here in the middle branch. And this value is given as 56 million mps. So, first of all, using your jobs junction rule at going to be, we come to know That I one and I two are getting combined To give 56 million anthea. Let it be question # one. Now using get jobs loop rule in the closed loop. B. See B E B. Here, this group, the lulu. And this sketch of slope proof says the algebraic sum of all the potential drops taking place in a closed book is equal to algebraic sum of all the E. M. S. And potential rob means I into Earth here. This potential drop is taking place in clockwise direction, so it will be taken as positive. and this 56 million people currently pass through 75 home also creating when more potential dropped. And that is also positive. And this value of 1.00 volt will be sending its current in clockwise direction. So this is also positive. So using these sign conventions, this equation comes out to be 56 million pier or 50 16 to 24 minus three. NPR multiplied by 56 homes. For the potential drop across 56 homes plus 75 Into I to this current is not known here. The current is I too ill earlier. Earlier, I have mentioned it to be 56 million here. But no, the current true 75 Ohm will be I to north of 56 million here And then it's equal to IMF which is 1.00 volt. So finally I get it to be 75 x two Is equal to 1.00-. There's 56, multiplied by 56 And multiplied by 10. H 1 -3. Comes out to be 3.136, Which is -2.136. So finally the value of this current I two comes out to be zero 2848. Ampere. All I can say this is -28.5 28.5 milli ampere here negative sign shows that the direction of this current I two shown here in the figure is wrong. Actually. The direction is not clockwise but anti clockwise. So as far as magnitude is concerned for this current, That is 28.5 million anthea. one of the answer for this problem. No. In order to find the value of 51 using the creation one Which says I one plus I to And here I do is 28. Along with the sign we will have to take it here Means -28.5 milli ampere is equal to 56 million Pierre. So finally Ivan is equal to 28.5 Plus 56, which comes out to be 84.5 million amperes current passing through the upper branch. So these two are the answers of the problem. Now we have to find this unknown E. M. F. Also here for which we will apply do the jobs blue, blue again in the closed loop, A. B. He have A And in this loop if you look for the sign convention of the potential drops and uh E M F. There's 50 16 to 10 Hr minus three, multiplied by 56 home. This potential rob will become negative as here for this loop, it will be taking place in counter clockwise direction and this 22 into Ivan that is also counterclockwise and this E N. F will also be sending its current in counterclockwise direction, so it will also be taken as a negative. Hence using the rules. The situation comes out to b minus 56. In to tenders for -3 in 256 -22. I won is equal to minus E. The anonymous source cancelling all these negative sign E M F. Here will come out to be For this. It is is three 136 Plus 22 Ivan, which we have already found To be 84.5 million people or into 10 hR -3 MP. Here. So here this is 3.136 plus 1.8 59 And it comes out to be 4.995 Volt. or approximately We can say this is 5.00 volt. The third answer for this given problem. So here these are the three answers, one for the unknown M. F and the two for the currents passing through the two branches of the circuit. Thank you.


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