Question
$11-17$ Find the directional derivative of the function at the given point in the direction of the vector $\mathbf{v}$ . $$f(x, y, z)=\sqrt{x y z}, \quad(3,2,6), \quad \mathbf{v}=\langle- 1,-2,2\rangle$$
$11-17$ Find the directional derivative of the function at the given point in the direction of the vector $\mathbf{v}$ . $$f(x, y, z)=\sqrt{x y z}, \quad(3,2,6), \quad \mathbf{v}=\langle- 1,-2,2\rangle$$
Answers
Find the directional derivative of the function at the given point in the direction of the vector $ v $.
$ f(x, y, z) = x^2y + + y^2z $,
$ (1, 2, 3) $,
$ v = \langle 2, -1, 2 \rangle $
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