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TUTOR Nomenclature of EthersWhat is the common name of the following compound? CHSCHz -CH,SubmitShow Alkyl Group and Alkane Base Names Show Tutor...

Question

TUTOR Nomenclature of EthersWhat is the common name of the following compound? CHSCHz -CH,SubmitShow Alkyl Group and Alkane Base Names Show Tutor

TUTOR Nomenclature of Ethers What is the common name of the following compound? CHSCHz -CH, Submit Show Alkyl Group and Alkane Base Names Show Tutor



Answers

Give the IUPAC name for the following ethers.

Yes, sir. Problem nine. We are on our you pack naming. Okay, so we have this molecular model in here, and we're supposed to name it. So the first up is still find the longest Jane we could find. Okay, so just by looking at it, all right, I think this should be the longest jane in this in the structure, right? And then we'll have those. We'll have those two branch points right here, okay? And so we're gonna have to count our carbons. And we are gonna come from where the closest branch point is. So say, um, so versus left or right. It looks like the branch point the first branch point is closer to the left. So we are gonna count, starting from the left kick. So let me raise everything we have so far and count from the left. So we have one two, three for 56 Okay, so we're only counting the carbons an hour main chain. Okay, Since we have six carbons, that's gonna have the the prefix hex right hooks. And since they're old single bonds, that's gonna be a vaccine. Okay. And then on carbon, too. We have the ch regroup. So we have two metal, right? That's a method group. And then we have another method group on carbon three. Right, So that's three metal. Okay, so now that we have all the information we need, you could go ahead and combine all of these information. Okay, so we're going to start with the numbers. We have two. Three. And since we have two metal groups, that's gonna give us a dime, Ethel. Okay, Dime Ethel. So 23 dime. Ethel Hexi. Okay, so that s the name for this molecule.

For part A Let's give the you pack name for the following ethers. For one we have meth. Oxy ethane. Yeah. For two we have. Mhm. A fox ESPN okay. For three we have four meth oxy oxen, octane. Mhm. Okay. Four we have one S. Opera poxy yeah. Dream of a beauty. Mhm. Before course five we have one. Yeah. Dash pra poxy few team. And for six. Mhm. Yeah. Two. Yeah. I saw. Yeah. Pro poxy heck scene. Yeah. Yeah. For part B. Mhm. Uh huh. Yeah. Do these ethers have common names? So for part B. Mhm. Yeah. Mhm. All of these eaters. Yeah. Have common names. Yeah. And let's identify those common names in part C. So the common name for one is ethel vessel. Either. Okay. For two we have di ethyl ether for three. Do you have level? Yeah. Gonna back at $4 octel either. Yeah. For four. The common name is beautiful proposal ether. Mhm. Okay. Five. Oh sorry. No this is incorrect. For four should be isopropyl stash three muscles. There was one beautiful either And five is beautiful purple ether. Yeah. Yeah. Okay. and common name for six is isopropyl. Yeah. Mhm. Yeah. Who heck? Cell? Yeah. Either. Mhm.

Hi this problem is from organic chemistry where we are given some of the structures of organic compounds. We have to identify the compounds which are final and also we have to give the I. P. C. Name for each of the given compounds. Finals are the compounds where benzene ring has hydraulic still responded to it that is always responded to it. So out of the given five structures we can see the structures see structurally and structure Sheehab hydroxy group bonded to it. Also the structures substituted some other places. So structures see structure D. And structure E. Uh finals ah substituted. Now we will write the iPCC name of the given compounds. In the first component. We can see the result chain of two carbon atoms. Where at time number one there is a doctor who cabin number two has financial bonded to it so we can write the name of compound as two. Fine. I'll eternal. Then we have the next compound where there is a psycho exhilarating having hydroxy group as well as Mitchell responded to its different carbon atom. So we can name the compound on the basis of numbering and the compound will be named as to metal final. Then we have a third compound where to the benzene ring, two carbons are substituted and both are having hydroxy group founded to them. So we can name the compound as derivative of final and write the name as to hydroxy final. Then the next compound is having the benzene ring With a hydroxy group at one position and two cyclone exile rings at other cabinet terms. So we can name this compound as two three bye psychlo exile final. And the last compound itself is having benzene ring with an orchestra bonded to it. So we can name this compound directly as final. So these are the names of the compounds whose structures are given here and C. D. And E structures are a kind of final and they are substituted with some other groups

Problems and we are naming molecules. So we are given thes molecules A, B and C. So let's go ahead and start with a right And again, the first up is just to find the longest chain, um, in the Monaco. So this looks like this would be our longest chain. And that should be our, um um function group or the branch point could. So, since this would be our branch point, um and we have this, we have this double bond right here. We need to count, um, from the carbon where our double bond would be closest. So, as you can see, it's closer to the right. So we'll be counting from the right case. So let me embrace everything we have so far, and I'll go ahead and count from the right. So we got one, two, three forget. So we have four carbons in our main Jane. So that gives us, um, have you beauty, right? And since we have this double bond, we have a beauty mean have a beauty, and that double bond is also on carbon one. Right? So we're gonna have one beauty, and finally we have that muscle group on carbon three. So we got three metal for it. Okay, so last up here is to combine all the information we have. So we got three. Oops. Three metal, one beauty. Okay, so that should be our answer for party. So let's go to part B. Now again. First step is to find the longest Jane possible. And I think this this looks like, um, the longest train we could find, right? And that ch three right? There is just gonna be our branch point. Okay? So, again, we're counting from where this double bond would be closest. And I think it's kind of hard to see right now, so I'll go ahead and just count from both sides and we'll see where we hit. Um, that double bond first. So I was constantly right. They got one, two, three, four, 567 and counting from the left. I got one, two, three, four fine. 67 Okay, So, based on our counting system here, we see that if we count with, um, orange counting from the left, we hit the double bond once we get to carbon four. But if we come from the right and follow our pink numbering here. We hit the double bind once we get to carbon three. Okay, So because of that, we're going to go ahead with the bank. So we're counting. We're counting from the right. Okay, so I'll delete our orange numbering here. This is carbon for Okay. So since we have seven carbons, we're gonna have the prefix help, right? Have. And because we have a double bond, we have a hep teen, and that double bond starts on carbon three. Right? Right there. Carbon three. We're gonna have a 3 15 Okay? And lastly, we have that metal group sticking out of carbon four. Right. This this is carbon for right here, and it's connected to carbon four. So we have four method for mental. Okay, So, again, last up, this, too, is to combine all the information we have. All right, so we got four for metal form Ethel. Three. Help teen. Okay, so that should be our answer for part B. The last one here. We got part, See? And again, you just have to find the longest chain possible. Okay? And of course, that longest Jane has to include our triple bond. Okay, so we start here, and you could either go up or go straight across, and it looks like this would be the longest train. Okay? And I think that this one is pretty clear where the the triple bond is closest, its closest on on the left side. So we're counting from the left. So let's go ahead and count our carbons on our main change. We got one, two, three, four if I six okay, since we have six, that's going to give. Um, that's gonna give us a prefix of hex. Right? Got hex. And since we have a triple bond, we got hex sign, okay? And that triple bond starts with carbon one. So we got one heck sign. And finally, we have this, um, Ethel group sticking out of carbon three. So we're gonna have three. Ethel. Okay, so last up here is to combine all the information we got, and I'm gonna write it lower because we're We're running out of space over there, So it's once out of three Essel, one hex sign. Okay,


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