Question
Liquid bromine is a dark maroon/brown color. 1,2-dibromoalkanes, on the other hand, are colorless. What would it meanif you added liquid bromine to your final transfer hydrogenationproduct and the resulting mixture converted from dark maroon toclear upon heating? Explain your reasoning:
Liquid bromine is a dark maroon/brown color. 1,2-dibromo alkanes, on the other hand, are colorless. What would it mean if you added liquid bromine to your final transfer hydrogenation product and the resulting mixture converted from dark maroon to clear upon heating? Explain your reasoning:
Answers
You have a liquid that is either cyclohexene or benzene. When the liquid is exposed to dark red bromine vapor, the vapor is immediately decolorized. What is the identity of the liquid? Write an equation for the chemical reaction that has occurred.
We have to part in this caution solving with but e the presents Often Elkin can be determined by edition off blue mean form L. Kile bromide. So by addition off Al Qaeda brah Might, which gives brown color on brown color off br tow. This appear cool, so brown color. This appeared, But this does not work with aromatic hydrocarbons as this substitution off Ramin occur with the presents off f E C. L. Three. So preparation off Sarah Bloom. Oh, it'll Benzene is shown in the reaction. We have benzene. Plus it ain't right that is. See, it's three ch two seal aluminum crew, right? That gives out. See, it's to see it. Three. This compound is it's time. Benzene Plus it's sealed. Second bodies. See? It's to see it's three. We take the products off. First reaction plus bloomy in presence off F E B R. Three that gives out. See, it's too See, it's three b r. This is called Les Barrow. Blow more a tile benzene, along with information off or two brew more entitled Benzene
All right, So this question asks us about an elemental analysis of a colorless liquid, and it's given us a formula of C five age 10 and it asks us to explain how a reaction with bro mean would allow us to distinguish whether this C five h 10 molecule is a cyclo al cane or an AL Keen. So basically, they're just reacting this unknown molecule with bro mean and the and this test would allow us to know if it's a cycle Al Qaeda and Al Keen and they want us to know, explain how we would know. So we know that bro me in reacts across a double bond. So if we were to try to react, this cyclo al cane with bro mean our products would just be our cycle. Al Cane and B are too, because there's no double bond for this, bro. Mean right here to add Teoh in our cycle. Okay, so it has to just it just maintains its structure. Now, in this Al Keen, we were to react. This al keen with bro mean we see that this be our too can actually add across this double bond. So our product would look something like that's with our bro. Means added across this double bond. So now we can see that this reaction would allow us to distinguish between a cycle al cane and an Arquin. Because if this C five age 10 molecule was a cycle, Al cane we would be left with are starting material, which is that cycle Al cane right here and roaming. Whereas if this cycle al cane over here, if this, um C five age 10 molecule was actually an AL Keen, we would start out with these two reactant. Is this one Enbrau mean? And we would actually just see one molecule are we only have one product. So that's how you would know that the C five age 10 is either cyclo Caner and Al Keen. The other reaction with Brahmi
Hi. So this question is asking you to calculate the density of bro mean in grants, permitted leader, and they give you a couple measurements. So they say 586 grams of bromate occupies 188 milliliters. So first, let's just do a bit of background. So density is just simply the amount of mass per unit volume, so you can see that by its units, right grams per 1,000,000. How many grams, Aaron? One millimeter of the substance. How much is one millimetre of this substance way? So now back to the question. How can you calculate density from the from the mass and the volume, right? Density is just mass per unit volume. Right. So, um, here they give you the mass, which is 5 86 grams and they give you the unit volume. Writeth. EU jobs are not the envoy. Just the volume 186 or 88 milliliters. Right? So you they do just plug it into the equation, right? You just put mass over volume, so 586 grams over 188 milliliters, and you're going to get how many grams per milliliter. This this bet bro me in ways. So that's basically just the density, right? You can even see this by the units. You have grams over milliliters. So to get the same units, you would have to put grams over mill leaders here. So why did you just plug this into your calculator and you'll get the density of brew mean? And if you plug it incorrectly, you'll get three point 12 grams per 1,000,000 so in every middle, a liter of bro mean I have it weighs 3.12 grams. So I hope this was helpful and allowed you to learn a little more about how to calculate density, which is a very, very important concept in chemistry. Thanks for the city.
So say we were tohave. An unknown compound has the molecular formula C five h 10. So it could be a Cyclops Al cane or an Al cane. There's also a cloak I'll cane on. Now I'll cane. It looks something like this on so we can add, bro. I mean, in order to determine whether it is cyclical or not. And so are all keen would react with our bro mean and it would turn from a brown orange to a colorless color. And that is because of the presence off un saturation. We have that double bond, whereas our cyclo I'll keen would not react, and we would maintain that brown orange color.