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There are two types of these – dominant/recessive andincomplete codominant problems. First, I want you to create atable that lists each variable in BOTH equ...

Question

There are two types of these – dominant/recessive andincomplete codominant problems. First, I want you to create atable that lists each variable in BOTH equations ANDexplains/defines what that variable represents. Then, I wantyou to solve the following 2 problems (one dominant/recessive oneincomplete/codominant).A population of humans has 18% that are dominant for widow’speaks (genotype W?). Use this information to solve for allparts of the HWE.B. A population of humans have 13% who have

There are two types of these – dominant/recessive and incomplete codominant problems. First, I want you to create a table that lists each variable in BOTH equations AND explains/defines what that variable represents. Then, I want you to solve the following 2 problems (one dominant/recessive one incomplete/codominant). A population of humans has 18% that are dominant for widow’s peaks (genotype W?). Use this information to solve for all parts of the HWE. B. A population of humans have 13% who have no webbing between their fingers or toes (D^w D^w), 37% with some webbing (D^W D^w) and the rest have significant webbing between their digits (D^W D^W). Use this to solve for all aspects of the HWE.



Answers

There are two types of these – dominant/recessive and incomplete codominant problems.
First, I want you to create a table that lists each variable in BOTH equations AND explains/defines what that variable represents.
Then, I want you to solve the following 2 problems (one dominant/recessive one incomplete/codominant). A population of humans has 18% that are dominant for widow’s peaks (genotype W?).
Use this information to solve for all parts of the HWE. B. A population of humans have 13% who have no webbing between their fingers or toes (D^w D^w), 37% with some webbing (D^W D^w) and the rest have significant webbing between their digits (D^W D^W).
Use this to solve for all aspects of the HWE.

So this question asks for the Gina Tippett frequencies resulting from four different meetings. And to do this, we need to know how to use and fill in a pun it square. And I'm actually going to start with the last meeting, which is deep and that is big. A little a they be little b crossed with the same thing. So to parents that are hetero, I guess in both Julio's, So to fill in the pundit square, we first have to figure out what, um ah Leo combinations each parent can make so, parent, one can make big a big beat. Take a little B little a big B, a little, a little bit parent to. Since it's the same, genotype can produce the same. You create a grid, and these are Leal's that we have written down. Right now, we're just created by seeing which a leal's the parents carry and which combination you can make from each trait. So taking one wheel from one trait, which is a one wheel from the other trait, which is B to fill in the pundit square, you just combine the two, apparently, also, you combine this and this into that square. Next, you would combine thes two, do a square and so on. Go back to blue. Mhm! Oh, so if you go through and look at this Planet Square, once it's completed, you'll see I'll circle and unique colors each genotype that is the same hope.

The progeny d do this in the goods that these have a different field day does the female. Hence we can conclude that on the three ds are on them X chromosome No, The diagram Attic representation of the chromosomes off the female president is shown in this diagram. Now the map distances between genes can be calculated in the following week. So the distance we dream is it on why it could be number off three continents If I did by torture Jenny in 200 wasn't that would be 70 divided by 1000 multiplied by 100% which is seven units now The distance between Ex ends it. We will do this in a similar fashion and it will be 60 divided by thousands in 200% which is six map units. No, the whole efficient oh coincidence is that you needed, as observed, double cross over, divided by expected double cross over which is one divided by 4.2, which is 0.238 So we can say that core efficient off coincidence is 0.23

Question, and I value to look at the table as we go through this. I'm not gonna redraw the table. I'm just gonna go through this very quickly. Um, and, uh, make a few comments and a few notes as we go along the way here. But there's a lot to cover. So, um, when you look at these questions, you have to write whether they're in Hardy Weinberg or not. So the 1st 1 you could see everybody has a big A alil. So P is one. Hugh is zero. So there it's already where? Equilibrium? Because you wouldn't expect there to be any headers, I guess. Er, almost like it's recessive. Um, for the 2nd 1 the answer's no. It's non in Hardy Weinberg equilibrium. And the reason is that there headers, I guess turn, you'd expect when they, uh, mate and have offspring that some of those offspring would be. Homer Side gets for three answers. Yes, it is in hardy Wonder equilibrium and again, for the same reason is Number one is for four. It's not in Hardy Weinberg equilibrium, and you can simply do the basic math year to get P and Q. It's a little bit tedious, but not terrible for five. Again, not in Hardy Weinberg equilibrium. And if you look at those numbers, we would expect there to be more headers. I goods. And we're not getting that. Um, so again, these numbers here with people, he 375 and 0.6 to 5. All right, uh, for six. Um, this was also yes. As I lose track on my notes, this one was in Hardy Weinberg younger. And and you can win in their in equilibrium All you have to do to get the peace accused Take the square root of, ah, say the on the percentage proportion of him is, I guess, recesses. That'll give you Q And then you could just solve for P. So that's pretty straightforward. For seven. This is not in Hardy Weinberg equilibrium. You look at it. It's just such a strange set of numbers. I'm something is going on, um, and solving for it, you're gonna have half the Leo's will be, Uh ah. Big A and half will be little a eight is. Yes, it isn't Hardy Weinberg equilibrium. And again, it's easy when there are anywhere in your columbarium because you just have to take the square root. Let's say the number of from his, I guess in proportion of home a psychic processes to get the values, um, nine is yes, and it's simply the reverse of the number eight. So that's pretty straightforward. And then, finally, Number 10 has a tiny numbers involved with it, but it isn't Hardy Weinberg equilibrium, and that's plain 993 and playing 007 So that's a and B here. And in the questions, um, see is asking about unquestioned six. Um, remember the formulas here, and this is the mutation over selection formula of the balance. And then the selection coefficient equation, which is s equals one minus w and were given mu is five times 10 to the nine s six. So that's the mutation rate. And then we can solve for Q. Um, because where we have Q from the the questions were 4.9 times 10 to the minus fifth. Something like that, um, that we just have to play the sort of it equations in. That's you square. So, um so if we use this equation here, we have 4.9 times 10 to the minus fifth equals the mutation rate, which is five times 10 to the minus six. All right, it by s. And so if we saw for s, we get a value of 102 So there's some decker mint. There is selection acting against this Leo, and then we're just unplug s into this equation here. So, um, point 0.102 equals one minus w. And again, this is this equation here I'm using. Ah, And if we saw for W, we get 0.898 So that what we were shooting for in this question, and then finally d um, there's a little bit tedious, uh, and were given values or fitness of one. And then for the headers I goat. Well, you was 0.8 and then for the homeless, I guess. Recess, Ivo, it's 0.6. Um, and we're interested in trying to calculate p crime. That is the frequency of P and the following generation. Um, so they're different ways to do this, but I'm gonna use that to formula approach. First, I'm gonna calculate average fitness, and this is a formula that's in the textbook where you have P squared names. The Fitness of the Homicide, its dominant plus two p Q and the fitness of the Headers. I Go plus Q squared and the fitness of the home is that it's recessive and these air just frequencies cow times, a fitness values. And of course, that's going to give you your average fitness. And so if you plunge these numbers in and for time reasons, uh, I'm not going to, um, you end up with a value of 0.8, right? So this number goes here and then for peace squared, remember that will just be 0.5 and shoes squared would between five squared and those air those point fires come from the table about. So the average fitness is gonna re 0.8 and then we're going to use in that value, which we needed in our second equation. And again, this is from the textbook Ah, where you multiply the fitness of the homeless. I guess Tom meant going to pee and the fitness of the headers I go and divided by the average fitness that we just calculated. So keep prime equals 0.5, and again, that's from the table above, and we want to play all that by 0.5 times one. So that was the fitness of W. A. A. That's appear, plus Q. Just also 0.5, and to fitness of the um, header is I go. And that's 0.8. That's appear. And then if we divide that by the average fitness, which we just calculated his 0.8 a 0.8 and we do that math, then we get a P prime value or the P and the next generation of 25 6 I think the question asked us What the value for Q. Is that people cubicles one. We know that then the Q prime value will be zero point for for so ah, long question with a lot of work involved.

Hey, it's clear. So when you right here. So we're gonna do approve then to find first to find the maximum value of appealing. To find the critical point of the function, soapy P, you know, is equal to two p plus two Q minus two peas. Where minus two. Q Square minus two p. Q. We're gonna find the partial shelter of it is so P small peak to minus four p minus two Q. P Q. Cool to two minus four p, minus two p. Then when we equal them to zero, we get negative. I mean, positive, 1/3 comma. 1/3. We're gonna use the second derivative test equal to negative or negative, for it was equal to negative too. So we know that D X comma y sequel Thio Double X. That's double. I'm minus that. That's why from since Dean 1/3 coma 1/3 he's bigger than zero and p double p. It's smaller than zero. So the critical point is going to be a point of maximum See is going to be equal to one minus 1/3 minus 1/3 which is equal to one third. So p 1/3 comma. 1/3 this equal to our equation right here You're as equals to third


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