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# Comoljiu DertIhiouch & ii to folkn: (5,y) p84s 0l deia pomnts 5), (8,7),(5,6} (7,8), ond (8 91Piuoaie saiter pol Qi Ihese deie pintsCompuia0.888 (Round Iiua dao...

## Question

###### Comoljiu DertIhiouch & ii to folkn: (5,y) p84s 0l deia pomnts 5), (8,7),(5,6} (7,8), ond (8 91Piuoaie saiter pol Qi Ihese deie pintsCompuia0.888 (Round Iiua daoinalpacusnueced |Comquie DoRoungUnien decime diacesneeded )Enler your answer Ihe answer box and Ihen click Check Answe

comoljiu Dert Ihiouch & ii to folkn: (5,y) p84s 0l deia pomnts 5), (8,7),(5,6} (7,8), ond (8 91 Piuoaie saiter pol Qi Ihese deie pints Compuia 0.888 (Round Iiua daoinalpacus nueced | Comquie Do Roung Unien decime diaces needed ) Enler your answer Ihe answer box and Ihen click Check Answe  #### Similar Solved Questions

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30.0 cm 36.0 Use the figure with two lenses for questions #I0 and #I 1 withvalues fi +20.0cm and f=-25.0 cm: 10. What is the location of the final image? Object What is the magnification of the final image relative t0 the original objeet?...
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##### Calculate the flux of the field F across the closed plane curve â‚¬ 6) F = xi + yj; the curve â‚¬ is the circle (X - 1)2 + (y - 2)2 = 81
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##### 15.Solve the system of linear equations using the Augmented Matrix technique from Sec: 4.2 aka Gauss Jordan Elimination ). Show supporting algebra. You may use your calculator to check your work. 10 pts_X + 3x2 =-14 2x, +512 =-22
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##### Question 11 (5 points)Enter a number rounded to one decimal if necessary:You corrected 15 tests and your substitute helped you finish for your class of 29 students. The mean for the tests You corrected was 81.3 and the mean for the entire class turned out to be 84.6Your substitute calculated that the mean for the tests she corrected was
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##### Find the crlcal values 4=4/2 ard 174/2 for 9 90% confidence levelsampi size ol n = 20.1-0/2 (Raund Ia threo declinal placos 03 neuded; ) 4/2 0 (Raund t0 thma decimal placos a5 neadod )
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##### How much heat (in kJ) will be absorbed by a 71.5 g piece ofaluminum (specific heat = 0.930 J/gï½¥Â°C) as it changes temperaturefrom 23.0Â°C to 67.0Â°C?
How much heat (in kJ) will be absorbed by a 71.5 g piece of aluminum (specific heat = 0.930 J/gï½¥Â°C) as it changes temperature from 23.0Â°C to 67.0Â°C?...