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Answer questions 1-3 based on the probabilitydistribution table below : Be sure to show your workto verify your answer. x 0 12 3 p(x) .1 .2 .3 .41. List the value...

Question

Answer questions 1-3 based on the probabilitydistribution table below : Be sure to show your workto verify your answer. x 0 12 3 p(x) .1 .2 .3 .41. List the values that x may assume.2. What value of x will occur most often?3. What is the probability that x will be greater thanzero?

Answer questions 1-3 based on the probability distribution table below : Be sure to show your work to verify your answer. x 0 1 2 3 p(x) .1 .2 .3 .4 1. List the values that x may assume. 2. What value of x will occur most often? 3. What is the probability that x will be greater than zero?



Answers

Complete the probability distribution for the random variable $x$ . What is the probability the value of $x$ is greater than 2 ?
$$\begin{array}{|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} \\ \hline P(x) & {0.1} & {0.3} & {0.4} & {} \\ \hline\end{array}$$

Question 73. Complete the pdf and answer the questions. In order to complete this, Pdf, we need to find the missing probability because all probabilities, some to one, we need to figure out that the probabilities that were given some to 90% in order to figure out our missing piece, we just simply subtract that 90% from one. We found that our missing piece is 0.1 to complete the third column. We just need to multiply the X values with their probabilities. Zero time, 0.30 one times 0.20 point two two times 0.1 Because you're a point, too. In three time 0.4, just 1.2. We have a question, eh? Find the probability that exit is too. Because we completed our pdf, you could just look in the table and find the probability of X B. And two is 0.1. Be buying the expected value they expected. Value is the summation. Every single ex multiplied with his probability. We've already done all of the X times the probabilities in the third column. So in this case, we're just simply adding together. The four numbers in the third column expected value is 1.6

For this question, we're asked to use the a numerical integration routine on a graphing calculator. So to find the probability and we have through that, we need to find uh so it's between negative 11 negative two and two and the negative three and three. And the function that we're using is from Problem 17. Which is this normal probability density function where are sigma is one and are moving zero. So this is what the curve looks like. So let's start with part A. So I'll just write A. Is equal to and we're looking for probability that X is between negative one and one. So which means you're doing integration from negative one, the positive one of our probability density function, You should get 0.68. Now part C we're basically doing the same thing, but this time we want to go from negative to positive, but it's still the same function And this is now 95.45 And the last one. Park si We're doing integration from negative three positive three For our probability density function, and this ends up being 0.9973. So what these mean is that? Um so the the area under this entire curve is equal to one. So the probability that it falls between negative one and one 0.682, seven, or 68 .27 and so on.

Mhm. The probability that the random variable Is greater than or equal to two Equals the probability that it equals two Plus the probability that it was three plus the probability that it calls for and they're psychos point to first point to plus point to Rich People's .6. Be careful and its expectation. He calls the son of the value of the outside times. Its probability, Which he goes one times .4 plus joe times point to Plus three times point to Plus four times point to okay. And this equals 0.4 plus 0.4 plus 0.6 plus 0.8 where she goes two points to

So you want to grab the probability distribution for the function to X plus one over 15. So two X plus one over 15 for the first thing we have to do is just substituted 12 and three and get those answers. Thio two times one plus one over 15 two times two plus one over 15 and two times story plus one over 15. So that will give me 3/15 5 15 and seventh if teats. Now, these can be reduced. But for this video, we're not gonna do that. So down here, 123 And I'm just gonna leave this in 15th just for simplicity. So then, if we grab each of those one Chris Craft to about there to about there and three years to about there and there's the graph of the probability distribution


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