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Glucose, C6H12O6, is a sugarthat occurs in fruits. It is also known as "blood sugar" because itis found in blood and is the body’s main source of e...

Question

Glucose, C6H12O6, is a sugarthat occurs in fruits. It is also known as "blood sugar" because itis found in blood and is the body’s main source of energy. What isthe molality of a solutioncontaining 5.63 g of glucose dissolvedin 20.7 g of water?.

Glucose, C6H12O6, is a sugar that occurs in fruits. It is also known as "blood sugar" because it is found in blood and is the body’s main source of energy. What is the molality of a solution containing 5.63 g of glucose dissolved in 20.7 g of water?.



Answers

Calculate the molality of a solution containing $257 \mathrm{g}$ glucose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ dissolved in 1.62 L of water. (Assume a density of $1.00 \mathrm{g} / \mathrm{mL}$ for water.)

And the problem. 73. We have to determine the freezing point. I'm joined. All glucose solution with a certain amount of the cost is often it. Um first, uh, how's it would determine the shift of the freezing for him. Um, on the boiling point, there's something cold, huh? Vines, Halsell Back half equation, which is Delta t. Uh, which is? The freezing point shift is equal to the morality. All the solution multiplied by a specific solvent factor. Okay. Freezing and the same or similarly, The shift of the boiling point you need be is defined by Malala t times boiling point factor and kay up and can't be our specific for each solvent on. And this problem we're working with water. So we know that chaos changed. Age too equals two 1.86 degrees Celsius. All right, morality. You let our baby is for again. The watcher I look is equal to I want to degree senses firm a lot of the unit, so no. No way. The factors are knowing the morality. We can easily calculate the ship. Um, so we're given a mass off pulling calls that's dissolved in their water, which is 55.8 grass. You were also given, um, NASA more solvent. Total mass of water equals 455 graphs. Suddenly let that into the Malala inflation, which are all for the remind you off. Well, sweetie equals amount off salute divided by mass solvent. Not the solution is very important. Uh, now we have here recalculate the mass of this loose into the amount of absolute by dividing that less buy them. Muller this What for? Glucose. We have 55.8 grams, divided by 180 0.156 girls for mall. That, um, will give us. Let me shortly calculate that 55 point eight divided by 1 80 0.1 by six. That will give us all 0.3. Um, one falls. Now we can put that into our first equation. Um, here. So we have opening 31 no. Divided by mass of the water, which we usually have two foot. And your grants, the whole 0.455 kill the grounds. In this case, go killer graphs is equal to 0.68 small. Her kilograms more. Oh, boy. 68 morality units. Okay, so Now the only thing that's left to do is to calculate the freezing one shift and the boiling for tripped for the given morality of the solution. So let's do that. Does ah T as, uh, is equal to all 0.68 morality times are long points and six excesses Morality constant, which will give us, uh oh, yeah. I'm sorry. It's actually a minus and which will give us a shift off miners 1.27 Ah, which was simultaneous degree Celsius. So what? You simultaneously that freezing point? Because usually the water is prisoner zero will just subtract. Um, we're just gonna go to minus 1.2. Silence. Freezing temperature. So reckless versus zero point with your senses of pure water. Um, let's do the same for the delta T B. So 46 8 a lot of TV times o wind. All right. 12 Celsius Morality. Well result in a shape off full points, um, 349 degree Celsius. So, as a result, we will have a chef stuff. TB is normally for water. 100 degree sells is somewhere. Well, um, adds old 0.349 degrees to that which will give us on you sure? 100 a point 349 degrees Celsius. So these are our shifts in boiling temperature and freezing temperature according to the mantle.

So the problem 59 deals with different definitions of concentration for a given solution on dhe. First, let's write down what we know home were given an accurate slip from who calls with the mass of glucose be 28.4 graphs. They were given the masked off solvent and water, um, equal to 300 developed grounds. We also know that the total volume of solution he is, um 378,000,000 years. Okay. And were given a toss with calculating similarity and my levity. Wait percentage more fraction on dhe. More percentage. Let's go. Uh, point by point, starting with Hey, Larry, some another similarity is the fine estate amount salute divided by volume. Oh, or we will see that we're missing amount of salute. Thought we can calculate that from mass on dde smaller mass of glucose by saying come on equal to yes, provided by Moeller mess. So in this case, it will be 28.4 grass divided by 118.16 which is the more mess. Okay, um, and this results in 0.158 Small amount of salute. Okay, so we have, uh, volume of solution. We have our amount of salute. We can calculate the polarity for meth by saying 0.158 most divided by we were given a solution of male leaders. Um, but the concentration is usually, uh, usually has the units of multiple leader. So I will recalculate the milliliters into full 0.378 leaders. You put it in here. 12378 leaders. Which gives me the polarity off 0.44 seven Moeller or milk, or later however you like. Okay, so this is a lead soon onto be morality, which is defined us a month absolute, which already calculated Battersby on us. Oh, solvent in gr graphs, which very important, it's not the massive total solution. It's the massive solvent, which is in our case, given its water 355 crops. So we can just put it straight into the equation. Open bond 58 small, divided by in killer grabs. So let's convert that two kilograms. Go. 4355 You progress and okay. Okay. Bye bye. Photographs. Which gives us our morality. Oh, called going for 45 Lillian. Okay. Now you can go to see which is wait percentage. Yeah, well, just mark with Wait some touch, um w t percent. It's defined as mass divided by mass. Oh, solutions. Not the solvent, um, and multiplied by 100%. So in this case, we have everything we need to calculate it. So we're gonna just put our mass off. Goes in here 28.4, uh, grand, divided by 300. Um, 83.4. 300. Sorry. Four grounds, guys. One of its percent. When should give us the percentage of 7.1 percent. God, I'm a mess. Okay, so this is C Oh, let's move along to the next concentration. Next, we need to calculate a mole fraction, and it's defined as a model. That salute divided by a month off solution, which, in our case, we don't know the amount of solution yet. So what we need thio, um do here is calculate the total amount off story. It's d, uh, we need to calculate is the focal mole or amount of a solution. How could we do that? We actually just ads among absolute to a month off solution. So this equation can be written. This follows. So event Plus, this means we need thio recalculate the we need to calculate to the amount off, Um, ourselves. It from the masters were given, which is easily done. Amount is as we know, um, mass divided by mother ms which is for water 19 point one grounds from I'm not gonna go into detail about it. Uh, you can look up the equation. So the amount of solvent from that equation the 19 4.7 malls. So no, we can recalculate this, um, by putting in the amount of salute or 0.58 again divided by the singer that we just calculated. 1947 rolls or water, Tonto 17 plus all 0.58 And this, of course, both in more. Okay, Now we put these out is in our equation. We get something like 7.5 just then to the power off line of St and this is our mole fraction. And the last thing we need to calculate is the more percentage. Just call it this on and it's defined as amount of the salute divided by amount of solution, just representative percentage. So you can imagine that It's just a mole fraction. Uh, times 100%. So that's easy. I'm talking. Simplify it like this when we multiply the value doesn't calculate it here, which has no units because it's a fraction. Uh, we get old 0.795 percentage. No. Okay, so we calculated all of the values on DDE. Yeah, but they find all of the concentrations.

To calculate the freezing and boiling points of the solution that contains 55.8 g glucose. We first need to calculate the mill ality of glucose, so we'll convert 55.8 g glucose into molds glucose by dividing by 108 point 156 Sorry, that's 180 0.156 and then Then we will have moles of glucose if we divide that by the kilograms of the solvent, we have 455 g, which is 4550.455 kg, and we get 0.6181 moles per kilogram as our morality. Then for the final freezing point of the solution. The equation is negative 1.86 times the mill ality, which we determined in a couple previous problems, and we get negative 1.27 degrees Celsius in the equation for the final boiling point which we just determined in a video two or three problems before, this was 0.512 multiplied by the morality plus 100 and we get 100.35 degrees Celsius

The first step to calculate our freezing and boiling points are to convert what were given into the morality of our glucose solution. So we need to calculate the moles of our solid over the kilograms of solvent. So we have 55.8 grams of glucose. We use the molecular weight and find out we have 0.309 moles of glucose. Now, to calculate the kilograms of solvent, we have 455 milliliters. We're going to use our density of one gram per mil later to find that we have 0.555 kilograms of water. So we substitute that into our morality equation above and found out that our morality is 0.679 Now let's do our freezing point first. So the freezing point depression, right? Because this is a solution is going to be your morality times the constant great. So we have our 0.679 Malala times the 1.86 degrees Celsius per morality find that equals 1.262 degrees Celsius. This is the drop in our freezing point of pure water, which is zero degrees Celsius. So Syria to your Celsius minus 1.262 And that gives us our new freezing point of negative 1.26 degrees Celsius. No, we do roughly the same thing for a boiling point, but we have the temperature of a bullet. Point increases the same. It's the our morality. Times are constant, so 0.679 morality times 0.512 That's a constant for water. At that temperature, we find the Sequels point 347 degrees Celsius. Lee. Add that to the 100 degrees that I want to do degree Celsius that pure water boils at, So our final boiling point is 100.347


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