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Draw the correct structure of 5-amino-3 ~methylcyclohex-3-en- T-one: Select Draw Rings More...

Question

Draw the correct structure of 5-amino-3 ~methylcyclohex-3-en- T-one: Select Draw Rings More

Draw the correct structure of 5-amino-3 ~methylcyclohex-3-en- T-one: Select Draw Rings More



Answers

Draw correct structures, by making a single change, for any that are incorrect:

Okay, so in this first, we're looking at molecules. So Sony, with part aim. Basically, what we can do is we can just count the number of bonds for each carbon Picture it all for, uh and it looks like all of them are So we're good to go on that one. Sit for part B. We're looking at the molecule. I would notice that this carbon right here has five bonds. So there's a few different solutions to kind of fix that. What I'm gonna do, uh, is just kind of choose to ah, get rid of one of these muscle groups. Nothing you could do is I just get a double bond and keep with the monthly groups. There's a growth about answers. That's a going down to see. I would notice that this carbon right here has five bombs, three from the double bond, one from the next carbon and one from the hydrogen. Lawson. Now, how you solve that is just simply get rid of the hydrogen right now. I will bring the total bond number back to four on. Then we're going to go

They will. Mr draws many president structures as we can for each of the following species. So let's go ahead and start with a So now remember, for resident structures we can Onley move electrons and we can't create new bonds. So let's see what we can kind of do. Well, the only carbons that are really are Adams RSP to in this are going to be a long this area right here. So this is a law in place. We could really do residents since that other carbon is sp three. So what we can do is move this to their And in doing that, though, this carbon is going toe have five bonds to it, which it won't like. So then we would want to pop that up like that and that oxygen would gain an extra lone pair. So let's go ahead and draw that out. And I'm just gonna draw the bottom line for this. So you have a carbon. You don't need that. So it would look like this. But now there's a double bond going from the carbon to that carbon and then a single bond to the oxygen. But now it's going toe have three lone pairs and a negative charge. So this is going to be the resident structure, and it doesn't look like we have any other resident structures we conform for a. So let's go ahead and move on to be So let's first go ahead and identify. Well, where can we do residents for this? Kind of like what we did over there? Well, anywhere we have, like, a double bond positive charge or negative charge are lone pairs. I should say we'll be able to. So it's just those carbs right there. So let's go ahead and first move this lone pair Teoh here. But in doing that now, those are not to there to this bond right here. But in doing that, this carbon now is gonna have five bonds because even though we didn't draw it, that carbon, so has hydrogen on it. And I don't know why in the structure they give, they have those hydrogen is over there. So I'm just gonna go ahead and Raissi's cause, uh, no reason, toe Draw those out. Really? All right, but so we go ahead and do that. And so we get our first resident structure, which is going to be. So we have the double ball. There are sharp forgot toe pop this up to there so we would have the lone pair here. Now we still have our double bond on the bottom there and bowl. We could move this some pair here to form the double bond, but then that carbon has too many bonds. So we can pop that double bun up, too, right there, and doing that is going to give us of the top double. Bond hasn't changed. Now we have a double bought on the side there, and then we have our lone pair on the very bottom, and that looks to be all of the different residence structures that we could for for this one. Now let's go ahead and go to the next set. So in this case, notice that this looks pretty symmetric in the sense of all. It's just nitrogen is attached with two hydrogen ins, so it would make sense, maybe for our first reason structure to move the double bond to the nitrogen. And then we would move. One of the lone pairs from the nitrogen is down like this here and inform a double bugged, so we'd have nitrogen, nitrogen, nitrogen. All of them have to hide regions on them. And now this one over here is gonna have a lone pair are top one. We give away the loving pair so it can have a double bond. And then this one on the side still has its low pair. Now, notice how this message in over here on the right accepted essentially just electron. So it should go from positive to neutral. But this top one now, it was neutral, but it gave away one of its electrons, so it would be positively charged. Now, let's just repeat it for this other nitrogen. And that should be all of the rest of structure. So we've moved that there, pop this up. And so we're going to have the May, Trajan. Nitrogen and nitrogen still all have to hydrogen, but three to. And now the top two are going to have lone pairs. But the one on the left has that double bunked. So just like before, this nitrogen gave away an electron. So should be positively charged now. And that nitrogen on top essentially gained an electron, so should go from positive to neutral, and that would be all of the residence structures for that one. Now, what about over here? So that's a positive charge on that carbon there. Well, the only thing we can really do cause this carbon over here is sp three. So we can't really get that in with the residents in any way. So what we can do instead is move one of the zone Paris from the sulfur to that carbon there. So doing that, we'd have. So it's the sulfur. We have a carbon on the left, and then we have a carbon with a double bond on the right, and this sulfur should still have one lone pair. So that would be one of the resident structures. And there's really nothing else we can really do for this when it looks like. And then for our last one, we can pretty much repeat what we just did for this one. We have some carbon cat ion right here, and then we just have some double bonds right next to it, so we could just keep moving them down. So let's do that. So we're going to start by moving this double bond over to here. And in doing that, we're going to get so actual Let me draw this Backman out for So it's 123456 123456 So we have a double bond on the end, then single bond and then another double bond, actually, so that double bond gets moved to that carbon and then notice. So if we were to compare this So before we had the double bond here were I have it dashed in green. Well, that means this carbon lost a bond, so that means it should have a positive charge on it now and then we could just move this bond one more over, and that's going to give us a double bond here, a double bond there, and then we have our double. But on the very end since this carbon was giving away its bond, so it should go from neutral to positive. And then, since this carbon here was gaining a bond, it should go from positive to neutral. So those should be all of the resident structures for these species here

Let's draws many residents structures as possible for the following species. For a with H 3 cc double bond. Oh, mhm ch two minus. We have some lone pairs resonance structure here. This goes in here. This double bond comes out here, you would have h 3 cc oh, minus double bond ch two for be God's six member ring. Double bond, double bond. And he minus charge here. Mhm Electrons? Yeah. Mhm. No, a trans Each h and H And there are two resonant structures. This is good here. Still upon Go here. One resident structure is structure here. Um, hear, hear! Minus charge and another resident structure. Things could go here. This could go here. 34 six member rain double bonds here minus charge here minus charges here. So that would be the resident structures for B for C. We have hte to n see and h two double bond and H two plus on that we can things electrons here. Hand double bond comes over here. I had a resident structure is each to end plus double bond, see, and H to own pair, single bond and H two lone pair. And then this double bond can come in here and this can come out here. Another resident structure will be see double Bond and H two plus H to end lone pair and H two lone pair. One more resonant structure is possible where this will come up here. And we could have carbon with plus charge. NH two blown pair H two n one pair and h to the lone pair. So therefore, resident structures possible there for D have a church, three C s, c h two plus charge balloon piers, and this can come in here. Resident structure will be H three C s lone pair Double bond, C H two. This is a plus charge here and last. The resident structure for E Sure, we have 12345 Double bonds here plus charge here. Resonant structure. 12345 Double bond. Double bond plus charge Here on this could go in here and you have 12345 double bond, double bond and a plus charge would be here. So here's our resident structures for each of the following organic molecules

Okay. This problem is asking us to draw out residents forms from the compounds that were given. So the 1st 1 that was given was this one. It was an eight carbon compound with three double bones and a positive charge on the right, Most carbon. So what are residents forms? Essentially, they replace positive charges by relocating them across the molecule. So this carbon has a positive charge. We do not want a puzzle charge in the carbon. We want to move it around so that I can go onto another carbon if possible. So if I were to move the electrons from the stub wound and put it onto this single bond, I will have created a new double bond by creating a new double one. I will have relieved this part this carbon of its posit charge. And I will have relocated that posit charge and put it onto this carbon. Okay, so let's clean that up and draw the effect. I'll be using a double headed arrow because double headed arrows mean that I'm going to end up with the same molecule, but just a different form. So I have my new o Keane. I have a new posit charge because I relocated it. And I have my unaffected double bonds. Okay, so next up, let's see what would happen if I were to relieve this carbon of its positive charge using the electrons from this double bond. If I do that, I will end up with a no came here and a positive charge here. That's back to where I started. So we don't want to use the electrons from that double bond. Instead, I want to use the electrons from this double bond. By doing that, I will have created in anarchy in here, relieved this carbon efforts positive charge and made a new posit charge on that carbon. Okay, so let's draw the effects of that double headed arrow signifying a new form. A carbon compound. Unaffected. Okay, unaffected. Okay, I knew it all. Cane and positive charge on this carbon. Okay. In orange. What happened? If I you relieve this carbon of its posit charge using the electrons from this double bond, I'll be back to where it started. So not those electrons, but the electrons. Next over. So easy in these electrons. I'm going to you play someone to that single bond, creating a double bond, relieving this of its posit charge and creating a new posit charge on that carbon. Okay, so the effect of that would be as such new double bond, sandal one and unaffected double bond as well. So I have my new posit charge on this carpet. Okay, What would happen if I were to relieve that posit charge using the electrons from my carbon hydrogen bonds? So this carbon has three hundreds of test strips. Each of those has electrons attached to it. But I do not have a base. If I had a base, that I could be probably one of those hundreds and relieve this posit charge making in milking. But in this problem, I'm not giving any basis. I'm just asked to draw the residence forms. So if our task, if I were to be asked a problem with that that I could relieve this posit charge even further. But I cannot. So I must use the electrons from what I'm given. What I'm given is a job on right next to it. But if I were to use those double bonds, those elections from that double one, I'll be back to where I started. So I know that I'm done. I'm done drawing my residence forms. So for my start material, have 123 new residence forms. Okay, next door. Here I have cycle Penton. I have long period attached to it. On the right. Most carbon and I have double bones Touch to it as well. Okay, so a residence form is moving. Posit charged around, and it is also moving the negative charges around. So let's try moving these lone pairs around. I'm going to move them in a clockwise direction. So let's move them onto the single bond. If I move them on to that single bond, I will have created a double bond. If I created a double one there, and this carpet has 100 attached to it and another set of another arcane. Then I know I have exceeded my octet for this carbon. So I have to move electrons around to relieve that carbon of its exceeded octet. So I'm gonna move the electrons onto this carbon. If I do that, then I'll end up with this cycle. Contain, with a new double bond, a new set of lone pairs, and my unaffected double bond. Okay, so once again, I need to move these those electrons around. So I'm gonna move them onto this single bond, moving them onto that single bond. And with the presence of the subject, this carbon has exceeded its octave. So I need to relieve that of its exceeded octet. I'm gonna move those onto this carbon. By doing that, I will end up with this cycle plantain instead of one pairs unaffected, double blind and new double bond. So remember, the goal of this is to get the electrons back to where I started, which was right here. Okay, so let's see what happens if I moved this. These, these electrons and continue the cycle ization. So by moving the electrons from this lone pair onto the single bond, I will create a new double bond. So I'm going to make the electrons from this Dubonnet move onto this carpet. Okay? The effect of that is this psycho plantain instead of one pairs unaffected double wand and new double bond. So the electrons are not where I started, so I need to keep going until I get them back to where I started. So we'll do this one in pink. So I have my own Paris. I'm going to move them, continuing the cycle ization, making a dump one there and making a set of lone pairs here. So I'm gonna continue cycle plantain, new double bond instead of on piers and unaffected. That will bond. Okay, so let's see what would happen if I continue the cycle ization even further. If I did that, I will create a new double bond and move the elections from this dough bond onto this carbon. If I did that, I would end up with lone pairs here. That's where I started. So I know I'm done. I have I have ended my cycle ization because if I continued it, I'll be back to where I started. So from my starting material, I have 1234 other different resonance forms. Okay. And last but not least, is this compound I have ch three connected to and Al Qaeda connected to a nitrogen connected to an oxygen and single bonded. Okay, so if we look back to the previous compounds, this one has a positive charge. I continue. My continued to move my posit charge around, but every time I had a positive charge, no matter what. So I always had a net positive. Whereas in this one I started with a negative charge and I ended up with a negative charge every single time. And this one, I have a positive and a negative charge. So I have a net of zero have a net neutral. That's because the negative cancers of the positive and the positive camps without the negative. So I need to make sure that in all of my residence forms I have a neutral compound, a net zero. So let's start. So I have lone pairs here. Move those around. I can get them onto this single bond to create a depth fund. If I create a double one, this nitrogen will have exceeded its octet. So I need to relieve that. I need to move electrons away from that magic. So I'm going to move them onto this carbon right here. Okay, so let's see what happened. Have I see his three? If I got rid of if I reduced my Hokkien by moving the electrons around I will have certain Al Qaeda. I will have created an Okie like that. So I don't have to continue my linear hybrid, my sp hybridization being a linear structure so I can have this. Let's be too. I'll have my next Gen. And I would have a double bond. So my oxygen and no longer has a negative charge attached to it. My nitrogen does have a positive hard attached to it. And because I'm of the electrons onto this carbon right here, this carbon has a negative charge. So the question arises. Can I go even for further than this? If I were to move the electrons from this carbon onto this double one to create a triple bond, I'll be back to where I started. So instead I need to move it the other way. But can't even do that. Can I move it onto this single bomb to create the blood? And the answer is no. Because if I did that, that my carbon will have exceeded exceeded its octet. So after this, I'm done. I have only one other residents for


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