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A chemist finds that 30.82 gof nitrogen will react with 17.60 , $35.20,70.40,$ or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxyg...

Question

A chemist finds that 30.82 gof nitrogen will react with 17.60 , $35.20,70.40,$ or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram ofnitrogen in each compound. (b) How do the numbers in part (a) support Dalton's atomic theory?

A chemist finds that 30.82 gof nitrogen will react with 17.60 , $35.20,70.40,$ or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of nitrogen in each compound. (b) How do the numbers in part (a) support Dalton's atomic theory?



Answers

A chemist finds that 30.82 gof nitrogen will react with 17.60 , $35.20,70.40,$ or 88.00 g of oxygen to form four different compounds. (a) Calculate the mass of oxygen per gram of
nitrogen in each compound. (b) How do the numbers in part (a) support Dalton's atomic theory?

We're gonna be solving problem number 1 13 of trolls, chemistry, structure and properties. And this is problem. I'm a 1 13 of Chapter one, and in this question we're told that the ratio of oxygen to nitrogen in one or two is 2.29 and the ratio off chlorine to nitrogen in an F three is 4.7. I've just indicated sub scripts here, three and 22 ribs and how many oxygen's we have that's contributed to this ratio and harmony Florence. We have that's contributing to this ratio, and that's just in the chemical form of the husband presented in the question. And we're told to find the ratio of oxygen to Florian, you have to sew in the sample. We're gonna have two florins and one oxygen given by the chemical from all of the species of interest here will have to. So one thing to see in this problem is that in the information that has been provided, nitrogen is present in more samples. So if we decide to just right a simple mathematical expression, where for the sample and or two we divide that issue over the sample and if three This is basically two point 29 divided by four point 07 And this would be the issue off because nitrogenous one and it's common in these two species is there. That's insignificant here. But this would be the ratio off oxygen to Florin by two oxygen's and three florins. Okay. And you can see here we're told to find the ratio off one oxygen and two florins. Right? So if this is represented to oxygen in other too, find that ratio. Oh, innards, find a ratio of one oxygen. We just have to multiply anyway, it by 1/2 right, we'll divide by two. And if this is representing three Florence. But we want final results too. Have to Florence. Essentially, you have to multiply the numerator by two. Oh, so you do know 1,000,000 by two or three. Essentially, this is representing three, so we have to divide by three and multiply by two. And that's essentially more to blind by 2/3. So when you solve this, you would see that the final results get zero point for two to know the sick fixed 366 So that is the ratio off oxygen to flooring in. We'll have to. That's your point 4 to 2

To calculate the moles of N 02 that are created when the quantity of each, then when each quantity of N 205 reacts, we simply need a balanced chemical reaction to use the coefficients as conversion factors. The balanced chemical reaction is provided suggesting we produce four moles of CO two for every two moles of N 205 So if we have 2.5 moles of N 205 with a 4 to 2 relationship will produce five moles of CO two. We have 6.8 moles of N 205 With the 4 to 2 relationship will produce 13.6 moles of CO two. And if we have 15.2 g of N 205 we first need to convert that into moles by dividing by the molar mass of N 205 Then we have moles into a five. Will use the 4 to 2 more relationship and get 0.169 moles too. And last of all, if we have 2.87 kg of N 205 will go from kilograms two g and then grams to moles. Using the molar mass and 205 which is the massive two moles nitrogen and five moles oxygen summed up well, then use the 4 to 2 more relationship to get 31 9 moles of CO two.

To calculate the moles of N 02 that are created when the quantity of each, then when each quantity of N 205 reacts, we simply need a balanced chemical reaction to use the coefficients as conversion factors. The balanced chemical reaction is provided suggesting we produce four moles of CO two for every two moles of N 205 So if we have 2.5 moles of N 205 with a 4 to 2 relationship will produce five moles of CO two. We have 6.8 moles of N 205 With the 4 to 2 relationship will produce 13.6 moles of CO two. And if we have 15.2 g of N 205 we first need to convert that into moles by dividing by the molar mass of N 205 Then we have moles into a five. Will use the 4 to 2 more relationship and get 0.169 moles too. And last of all, if we have 2.87 kg of N 205 will go from kilograms two g and then grams to moles using the molar mass and 205 which is the massive two moles nitrogen and five moles oxygen summed up well, then use the 4 to 2 more relationship to get 31 9 moles of CO two looked slight correction I had as the molar mass, 180 it's actually 100 and 8.1. So that's going to change these two last answers. 2.281 moles, N 02 and 53.1 moles in 02

Hello. This is an issue command and I welcome you to my class. So I have been given discussion to calculate the mass percentage of nitrogen in the following compound. The first compound is and or two. Right, so feel. So first of all we have to calculate their total myself and autumn As we know the mass of nitrogen is 14 ground and the mass of the study program. So the total mass will be 14 plus 32. That is 46 ground. So in order to calculate the percentage of night prison in a note to we'll have to give the mass off nitrogen divided by the total mass of compound mm in 200. Right? So it will become 14 by 46 in 200. It is nothing but 14 by 14 6. Okay. So it will come around 13.43 percent is right. So moving to the next question in this case the given compound is from this animal. So in order to include the mass percent is off percentage mass of not reason. It is the mass of not bruised and divided by Marcel's molecular wants to be precise. Uh huh. I know in two 100. So that will become 14 divided by myself and no is 14 plus 16 has been on the master of oxygen is 16 rounds so it will become to Tehran. So it will be eventually 14 bus 13, Which is nothing that is seven by 15 in things and did So it will become nearly 46 points 66%. I believe This is correct. Let now let's move to the third option. 3rd question. So in this given I have been in this question. So it is the annual too. Right. So percent is masked a molecular myself. I know two is 14 plus that did it, it is 46% is last person pays off. Nitrogen will become 14 by 46 Imprint 100. It will become 30 point 43%. Right, So we'll be the next question given compound is a channel So total Molecular myself A Channel 3 1 is for a reason 14 is for nitrogen And this is 48 what oxygen water. So it will become 63 round. So in order to find the percentage mask off, Not risen in a channel three, it will become massive, nitrogen divided by molecular massive. That's one in 3 in 200. So it will become 14 divided by 63 and 200. Which is This which is 22.22%. Thank you.


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