5

[3a+6b-c 6a-2b-2c :a,b,cinR ~9a+56 +3c ~Jatbrc...

Question

[3a+6b-c 6a-2b-2c :a,b,cinR ~9a+56 +3c ~Jatbrc

[3a+6b-c 6a-2b-2c :a,b,cinR ~9a+56 +3c ~Jatbrc



Answers

$$\begin{array}{lrrrr} \hline 13.3 & 9.0 & 11.1 & 9.1 & 8.4 \\ 15.6 & 8.1 & 8.3 & 13.0 & 17.1 \\ 16.3 & 13.5 & 8.0 & 15.1 & 5.8 \\ \hline \end{array}$$

For this problem, we need to add. So in order to add, we would be sure to go from our right column to our left, just in case we have any numbers that we need to carry over. So we start with the far right, which is six plus seven plus two plus one plus three. This gives us 19 and because this number is greater than nine would need to carry over our one. So we're gonna go ahead and place are nine here and our one up here. And we need to make sure that we add this done with our next column. So now we would do this column. We have one plus eight plus nine plus zero plus four plus four. This gives us a total of 28. So that gives us to look 26. So again, Greer, the nine. We would add our six under here and then carry over the to exit out of this column. We have to put zero plus six plus three plus four plus eight. This gives us 23 again place. Our three here carry our to. Now we do this next column, but we have to plus three must four put seven plus three plus nine. This gives us a total of 23. Sorry 28. Again, It would place our eight here K R. Two. It's in every cell of our final column. We have two plus two plus four plus six plus eight plus one. This gives us a total of 23. And because this is our final column, we don't need to worry about carrying over any number. So we just write in our 23. This gives us our final answer of 238,369.

In this question were being asked to add. So keep in mind that when we add, we go from or right, call him to our left, just in case you have any numbers that we need to carry over. So we were start here in our far right column, you would add seven plus two plus six plus eight plus zero. This gives us 23 now, since some Berries greater than nine, we need to make sure that we carry over this too. So you would put our three down here and who would k over our two and that we need to make sure that we added to and to our next call him. So we have to plus nine plus three plus two plus zero post one. That's as that to 17. Same thing. We would place our seven down here and carry over our one. Let me. So where next call him. We have one plus zero plus four plus one was five plus three, which adds up to 14. That's right in our seven here. I said to take this for right in our form and again carry over our one. Next we saw this column. We have one plus four plus three plus seven plus four plus eight, which adds up to 27 again place. Our seven here carry over our chill every so our final column, which is two plus five plus three plus nine plus six plus seven. This adds up to 32. And since this is our final call home, we do not need to carry over our three. So we just write in our 32. This gives us our final answer, which is 327,473.

We're going to determine if these two lines are parallel, perpendicular or neither. So looking at these two equations, neither one is in slope intercept form, so we can't tell what the slope is yet. So we're going to change them both into slope intercept form by isolating Why. So with the first equation, we need to divide both sides by five 10. Divided by five is too three divided by five is 3/5. So we have two plus 3/5 X equals y. And I'm going to rewrite that as why equals 3/5 X Plus two and with second equation tau isolate Why I'm going to start by subtracting five x from both sides. So three y equals negative five X plus one and then I'll divide both sides by three. So why equals negative 5/3 X plus 1/3? Now we can see the slope of each equation for the first equation. The slope is 3/5 for the second equation, the slope is negative. 5/3 3/5 and negative 5/3 are opposite reciprocal. Lt's so that means that the lines are perpendicular

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.


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