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Segment ol winc total length 2,0 m Tomed nlo Dcmac Dat cring Tnc mjonctic fiela atthe center Ofthc loopHEEmner94 225.18 HI 06, 151,65 MT 0 6 1065 pT 0.4.99.63 pT 21...

Question

Segment ol winc total length 2,0 m Tomed nlo Dcmac Dat cring Tnc mjonctic fiela atthe center Ofthc loopHEEmner94 225.18 HI 06, 151,65 MT 0 6 1065 pT 0.4.99.63 pT 21.22pT

segment ol winc total length 2,0 m Tomed nlo Dcmac Dat cring Tnc mjonctic fiela atthe center Ofthc loop HEEmner 94 225.18 HI 06, 151,65 MT 0 6 1065 pT 0.4.99.63 pT 21.22pT



Answers

Use the segments from Exercise I to construct a line segment with length $2 A B+2 E F-C D$.

Okay, So in the given question, we are told to draw a line segment E. F. Of length 24.8 centimeters by using a ruler. Right? So the ninth segment E. F. This after length 24 eight centimeters. Right? So to do this, we'll take a ruler and mark the first point. We just e on one end of the ruler, right? So we'll market over here. So from this point it will count till 24.8 on the ruler. So here we can see that there are measures of one centimeter two centimeter up to 30 centimeters. So we'll go up to 24. And in between 24 25 we can see that there are lion lines. Right? So the first line denotes the measure 24.1. 2nd 1 is the 24.2, then 24.345678. So this point over here, but do not. the measured 24.8 from the first marked point over here, which is the right, So this would be the point F. Now what we need to do is to join this Land sick and join these points to get the required line segment, so let's join this point, right? So can join this point, And we will get the required line E.F., which is of the measure 24 2.8 cm. So this is how we use a ruler to draw a line segment of the specified length. So I hope you understood the method. Thank you.

Hi. We're looking a question 32 asked us to find the value of CF and to find CF, we need to do a little bit of jaggery and the're, um we have, um, see age they tell us is to and that's one leg of our triangle. The other leg is H F, which, if you did question 30 you know the answer. If you didn't do question 30 you can look H f and D H have to be equal, so it would be 6.71 and that's equal to see a squared. And so we can just do the math. And if you prefer to cost the F X or something, that's fine. Two squared is for 6.71 squared is 45 0.2 for one, so that's equal to CF squared. And then when you add those together, you get 49 0.2 for one is equal to CF squared, then take the square root, and so C F equals 7.0 17 Depending upon your teacher, they might say that seven is an acceptable answer and let's around. Other teachers want you to be more precise, so you can call it seven if that's what your teacher would accept or you can say at 7.17

For this problem, you're given to line segments e f in which he which is equal to one come before an F is equal to five comma one that's our first line segment on our 2nd 1 is G H. Which G is equal to minus three, Comma one and R H is equal to one comma six. Okay, so we have these two line segments and were asked which if they're congruence and if not, which one is greater? So let's find out. Start with our last segment yet Let's find the distance right of the line segment that connects E to F. And for that, all we have to do is find the part news of the right triangle, right triangle that described these two points. So we have r h here. We have the hypothesis of the triangle and our side. A is just going to be today over here, and this would be our side is going to be equal to the difference between the ex components of the points. That's for which is five minus one. There be is going to be equal to the difference of the white component of the two points. Well, sorry. It's actually inverted if you consider the Y axis over here and her X axis this way and should be inverted. But it actually doesn't matter because we're just gonna plug it on the Pythagorean theorem and it is symmetrical in some sense. So we have four. You going A and B equals four minus one, which is three. And so by the fact that we're here and we have eight squared equals four square, which 16 plus three squared, which is nine. Medicals 25 we take the square root of 25 in the square root of a squared and get a cheap ALS five. So we have a cheek. UAL's five here and that's the distance between the NF. And now let's do the same thing for GH. All right, so let's just go directly to the Pythagorean theorem. We have the distance where the difference between minus three and one now before writes a four squared plus. The difference between these two just five squared equals a squared that's 16 plus 25 people. We'll just take the square root of that that should be equal to H. And so this is actually 41 he's square with a 41. It's definitely larger than the square roots of 25 so we can tell that gh It's actually a longer line segment than yet, and they're not congruent.

Hi. We're looking at Question 30 and they tell us that this is a nice ass Elise triangle. So this is actually a pretty quick, easy question on they ask us for h f. And because it's a nice sauce Elise triangle. We know that HF is going to be equal to H. D. Because of the fact that it's I saw sleaze. The to the left and right side are mirror images of each other. So sends H D. In the diagram. It tells us that that's equal to 6.71 a. Jeff is also going to be equal to 6.71 and that's all there is to it.


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