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Wrahie coLor A=it Rrtaronant oni d' FatM Tch4seer140t 97a57inFaeaon nelftitoC 0l t Uaclet lnn (07m (~motn Maan AnaAnttitt Llenghder umtMnalme Fertdnutden...

Question

Wrahie coLor A=it Rrtaronant oni d' FatM Tch4seer140t 97a57inFaeaon nelftitoC 0l t Uaclet lnn (07m (~motn Maan AnaAnttitt Llenghder umtMnalme Fertdnutden

Wrahie coLor A=it Rrtaronant oni d' Fat M Tch 4seer 140t 97a57in Faeaon nelftito C 0l t Uaclet lnn (07m (~motn Maan AnaAnttitt Llenghder umtMnalme Fertdnutden



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A ccrrain pale grocn subsrancc, (A) becomes dark brown on axkting $\mathrm{NaNO}_{2}$ in prcscncc of dil. $11, \mathrm{SO}_{4}$ irs aqucous solurion gives prccipitarcs wirh (1) $\mathrm{BaCl}_{2}$ and (II) $\mathrm{NaO}] 1$ The larrer NaO1 I in scparare resrs. The larter prccipitare (B), gradually changcs colour from grcen ro brown, on cxposure to air. Whar is A? (a) NiSO $_{1}$ (b) $\mathrm{FeSO}_{+}$ (c) CuSO $_{4}$ (d) $\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$

Now in this part we are asked to find out the yellow respect. You'll notice right the sequence of the reactions of the year being N no three or two. This upon hating will produce. Yeah, mm. No, this is a fun reaction were diluted. Well you the the L two. No, we have video on reaction with alimony, um ammonium carbonate, ammonia carbonate. This will produce, he is C. 03 This is uh now this upon reaction will dilute at cl will produce S E L two B S C L two. Upon reaction with potassium promenade this will produce E A R Bs er of or no B S C R. O. For upon reaction with dilute sulfuric acid, it is a source of work. It will produce B. A. S. Awful. So this is Yeah, this is the better answer. E. S. 04 Yeah. So far is there direct And and this is this is the final product. But we're asked to find out the yellow pre speed. So this is the yellow principle. Hello, is it the B A c R 04? P a c R O Forest to Yellow Pre spirits. So let's check out the options. We see. Obscenity is going to Son. He is going to B S c R 04 is uh, yellow precipitate.

In this problem, I can write DDX in it see http CH two C 00 H. This compound in pageants of Cl two A red P. That to be dad reaction. It will give the compound edge, see http C h C L C. O AT and this compound in perchance of alcoholic kO edge. The hydro chlorination happened here and the compound formed the CH two double 1 C h c o egg. Therefore, according to the option of indeed correct option, the is correct answer. I hope you understand the solution.

Is the pair of its salts is expected to have same collect in their freshly prepared a quick solution. Okay, So We have VOCL two and secondly, see you theory Cuz here to have plus twisted VOCI do have plus four step. So having a chronic conclusion that is reliever you could have 39 so one electron and period they are colorful In the rest of the molecule. CUCL two 26 to be named three d 6 half full electron pair would have won the compared so they will not have them. Hello, the same and electron will have same color here is the correct option.

In this problem, the salt Maybe K I add the salt age. Okay. I add potassium Qattan as potassium as potassium, get diane as potassium katyn in parts, in parts a violet in parts they violet colored to board X bead aged. Also. From this question, we can say that the correct answer will only be K I two Option A it corrected.


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