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Quetkn 0115Step 10r1assloniponometric functlon of & single number;erence Identitlesrewvrite the fcllowing...

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Quetkn 0115Step 10r1assloniponometric functlon of & single number;erence Identitlesrewvrite the fcllowing

Quetkn 0115Step 10r1 asslon iponometric functlon of & single number; erence Identitles rewvrite the fcllowing



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The corrcer number of unpairod clectrons in $\mathrm{Fc}^{21}$, $\mathrm{Mn}^{21}, \mathrm{Cr}^{7}, \mathrm{~V}^{31}$ and $\mathrm{Cu}$ will $\mathrm{bc}$, rcspcctively (a) $5,4,3,0,1$ (b) $4,5,3,0,1$ (c) $5,4,2,1,1$ (d) $4,5,3,1,1$

In this problem, I'm doing the diagram of ACSI or F. Or so. Just look at it carefully. Here is the central letter maxi here. They were born. Oh, he had F. As as as and in this side of the ridge, a lone pair, so only one long pair is present here. Therefore, I'm writing it here, one loan here. Therefore, according to the problem, option B is correct here. Therefore ups and be is he connect and said for this problem.

As we all know that XE 03 as one lone pierre on XC act, um also X c o F for as one lone pair on XC at them, and XCF six has also won lone pair on XC at them. Therefore, according to the option, often see each correct answer for this problem. I hope you understand the solution of this problem.

Begin by placing your numbers in order from smallest to largest. Our smallest number is just us or minimum. So here are minimum is, too. Our largest number is less our maximum, so here are maximum is nine. Next. Let's identify the median now. The median is our middle number. Since we have 11 numbers here, our exact middle number will be five. In other words, it's going to the six number that comes in our sequence. So here's your media. Find Q one and Q two split off your remaining numbers into those that are to the left of the median and those that are to the right. Next, cross them out until you get to a center number of each Here. We crossed them out until we get to four. This is our Q one. Again, we're treating each of these halves like its own set of data over here. When we cross out to get to the median of this half, we get seven. Now we need to put everything in order. Are five number summary goes our minimum, which he said was to Q one, which he said was four median, which we said was five que three, which we said was seven and then our maximum, which we said was nine

Begin by placing your numbers in order from smallest to largest, our smallest number, thus or minimum, and our largest number is thus or maximum. Next, identify your median. Since we have 11 numbers here, the six number will be your median. In our case, this is seven. Now look at the numbers that are to the left of our medium. We have five numbers here. Treat this as its own data set, nor to find the median of this data. When we cross out, we see that our median is four. This the medium of our lower half makes our first quartile. Now do the same to your upper section your upper half. In other words, those to the right of the median. Cross out until you get to a median number. In this case eight. The median of the upper half is Q three. Now we need to put these in order. Our minimum comes first, followed by a first quartile, followed by a median, followed by our third quartile, followed by our maximum. And there's your five number summary


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