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(10%) For van der Waals gas, Tr = a/VZ. Assuming that this relation applies calculate AUn for the isothermal expansion of argon gas from an initial volume of 1.00 d...

Question

(10%) For van der Waals gas, Tr = a/VZ. Assuming that this relation applies calculate AUn for the isothermal expansion of argon gas from an initial volume of 1.00 dm" to 30.00 dm" at 298 K What are the values of q and w? For argon; the van der Waals constant are a = 1.33dm6 atm mol-= b =3.87 X 10-2 dm3 mol -

(10%) For van der Waals gas, Tr = a/VZ. Assuming that this relation applies calculate AUn for the isothermal expansion of argon gas from an initial volume of 1.00 dm" to 30.00 dm" at 298 K What are the values of q and w? For argon; the van der Waals constant are a = 1.33dm6 atm mol-= b =3.87 X 10-2 dm3 mol -



Answers

For one mole of a van der Waal's gas when $b=0$ and $T=300 \mathrm{~K}$, the $P V$ vs, $1 / V$ plot is shown below. The value of the van der Waal's constant $a\left(\right.$ atm. liter $\left.^{2} \mathrm{~mol}^{-2}\right)$ is : $\mid / V$ (mol liter ${ }^{-1}$ ) (a) $1.0$ (b) $1.5$ (c) $4.5$ (d) $3.0$

Hello friends Here it is given number off votes off organ guests 0.1 off organ Adams in a advocated chamber off 50 centimeter cube volume that is 50 into 10 to the power minus 6 m, cubed at temperature. Contradictory searches that is to 93. Calvin the get it is undergoing. I saw a thermal expansion so volume becomes 200 centimeter cube that is 210 to the power minus six meter cube. What is the final pressure? Fine. Final pressure and in second part we have to drop TV group. Let us see it first. We'll find initial pressure. Initial pressure can be calculated by using ideal gas equation using ideal gas equation. Previous called to an Arctic So initial pressure P one is called tow N R t. One. Upon re one number off votes are given 10.1 Gas constant 8.31 Temperature is 93 Kelvin upon volume 50 into 10 to the power minus six. So it is to be 4.87 10 to the power six Paschal No, for ideal gets to follow. I suitable process for ideal gets following. I saw thermal process We to be two is cult. Oh, even even so, Peter is cult toe. We went in tow. We went upon veto even is full 0.87 10 to the power six Paschal be Vonage 15 to 10 to the par minus six on pit with B two is 202 10 to the power minus six. So it would be 1.2, but six into 24 6 particle. So this is a final pressure. No PV gruff. Yeah, in Paschal Volume and Centimeter Cube zero 100. 200. They're so thanks for watching it.

Okay, so first let's look up the value of the for argon And we'll see that that is .03 22. So we're told that this number this be Equals four times the volume of one mole. Okay, so the volume of one mall Is going to be 00805 L. So then we're told that we want to be one mall at STP, Well one more of any gas at STP has a volume of 22.41 leaders. So if we want a fraction, we'll just take zero 85 liters And we'll divide it by 20 to 4 one And we'll get the fraction of 3, 6 times 10 of the -4. Or if you prefer, you can multiply by 100 and report that as a percentage. Okay, so over 100 atmospheres, let's go ahead and calculate our pressure. You can use Charles's law or the ideal gas law. I'll just go ahead and plug in here. We still have one mall .08-1 And we're at 273 And our pressure is 100. So you'll see that this is just gonna be one, of the 22, 4 1. So 2- 4 1 leaders. So our fraction now .00805 l Divided by .2241 leaders. That's going to give us a fraction of 036 or again, if you want it to be a percentage, it would be 3, 6% of the the volume

Opening Chapter 18 Problem 41. So it says for oxygen gas. The best fit for the vandals equation. Have constants of a 1.14 Newton meter to the four over Mole Square and be equaling 3.2 times 10 to the negative fifth meters. Keep Permal who? So what we want to do is determine the pressure for one more zero degrees in 0.7 leaders cool. So for part, a wants us to use Vanderbilt's equation for this. Using these constance so of animals equation is p equals r t over Be over in minus B minus a over B over and square. So we plug all this in and aside, Units we should get past gals are unit out. So this is 8.314 Jules per mole, helping times 273 common and R V over end. It's just one bowl, so we just need to convert 10.7 leaders two cubic meters. So that is 0.7 times 10 to the negative three cubic meters and formal. We can subtract off 3.2 times, 10 to the negative five. You get your Super Bowl in the second term here is 0.14 years. Four over Mole squared and this is divided by 07 points to the negative three. You rescued formal square. Awesome. So we just gotta plug all these numbers into our calculator and this will be 3.1 times 10 to the six Haskell's. Yeah, Cool. So now let's calculate this using the ideal Gasol that says p equal in our tea over V. So this one's gonna be simpler. This is just one more times are constant gas comes eight point through you won four duels for more Kelvin times 273 Kelvin all over. 0.7 times 10 to the negative three cubic meters. So when we have all this plugged in to our calculator, we should see this comes out to be similar but slightly different. We have 3.2 comes tend to the six past caps. So disagrees slightly Besim order of magnitude, So seems like it checks out

So as we know that as we no debt, the formula for T B is equal to a by how to be everybody are being simplifying it further, I can write evaluate 149 by 0.0, if 1 to 0.0 812, multiplication .04. Which 1? So on solving it, I get the value of TB equal to 453.7 Kelvin. So approximate value of TV is equal to or 5 4 Calvin. So according to the option option, see each correct answer for this problem.


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