Okay. It's when this question were concerned with the gain and decibels produced by a stethoscope. So let's write down the given so we can discuss how to do the problem. Um, so and we know that sound is transmitted 100 times is effectively I'm curious what that corresponds to mathematically 100 times power. What? I'll just write down 100 times question mark and come back to it. Um, and then we went to gain, um, if the gathering areas 15 centimeters squared. So I'll call that a one and, um and then it concentrates on to an ear drum to air drums, 0.9 centimeters squared, and I'll put at times too. Um, and the efficiency is 40%. So right now, I'm just gonna put this information aside. They think you can sort of, um, you can work with this information and so, uh, basically, we can assume that the power stays the same. Actually, I guess we want to assume that the efficiency is 40%. The power stays the same, though. Um, well, I guess we could say there's an initial power, and then the final power is only 40% of the initial power. And so you can say that I is p over a And so, um, we can get what? So we can have the intensity at the, um, sort of intake of the stethoscope, and then we can have enough it your drum, and so we don't really know the power. Um, so we could, but we can say an initial intensity is initial power over initial area. Final intensity is final power, which we can say is reduced by 40% of the original surrounded by area. Um, let me sync up my area one and two. So I call this all one. I'll call this all too. Okay, so too is at the years. And then one is at the opening of the stethoscope. So 111222 And we're concerned with, um, the game produced So, um, being, uh, is 10 db multiplied by 10 long 10 of I two over. I won. Okay, so now we can start plating in so we can do 10 10 db times a factor of log. I too. So that's gonna be P two were a two and I one is P one over a one and um P two is point for p one. So we can replace this with 10.4 and then a one over a two. Um, weaken. We just need to put everything into a calculator at this point? I guess so. They wanted to in a two are given. So we want to do, um 10 c Yes, 10 times the log. Oh, four times 15. And then we wanted to find all of that by when we have to remember that there's two of the area, so two times 20.9. So go ahead and put times two. And to see what we get, we get that the enhancement is by a factor of 5.23 db.