There were told that assuming we have three atoms per molecule, we want to know which of the following geometries are not being electron geometries. So we're looking at electron groups around the central. So we have three of them. We've got Tetra Hydro, which has an electron geometry with four groups are too he'd roll six electron groups and tribunal plainer free electron groups. Our 1st 1 we've got Tetra vigils. So normally we would have something in the centre bonded to four other things, meaning we definitely would not have a linear molecule with there have bonds around the centrifugal molecule because we have four things. The bond angles there about 109 degrees. So if we look at one that has three bonds, we've got one bond here. But since we got two bronze and we need four electron groups, we're gonna have toe two lone pairs. So now we've got two lone pairs around the central Adam and two bones. So we could like in a molecule like this to water. So we would have Htoo. We'd have an oxygen in the middle with two lone payers and then we have two hydrogen bonded to it. And we know that water is not a linear molecule because those loan payers push these bonds down. So instead of them being linear, 180 degrees there pushed down and the bond angle is smaller, so it's less than 180 degrees. So we would say that a Tetris usual molecule with three atoms bonded together cannot be living. So this is not Winninger. Now, for our 2nd 1 we have an octave hydra molecule. Normally, we would have six things bonded together. So we have four things bonded Equatorial Lee to the Central Adam and two things in the axial position. But in this case, we can only have three atoms that we've got two things bonded to our central Adam again, like in our first example, two things bonded to the central Adam and will make the other four groups lone pairs. So this molecule is still a this molecules about the same shape as this one, minus the fact that on our left side we have four things in equatorial position for Adams in the equatorial position, and in this case, we've got four line payers, so we've got one lone pair. Two lone pairs really impairs four lone pairs. So in this case, we do have 180 degrees between the two bonds that we have drawn in that are actually Adams. We do have 180 degrees here between this Adam this Adam, it is linear. And that's because we have thes four lone pairs going around the central atom and to the actual Adams in an axial position. So we've got one in the centre, one above it, and one directly on the opposite side. And the lone pairs are circling up. So in this case, we do have a molecule that is linear. So it's molecular geometry is linear. Now, for our 3rd 1 we have triggered all plainer, which is three electron groups. So in this case, we have the same wealth. Our original tribunal, plainer with three actual bonding groups, would be a central Adam. So we've got a central Adam here, and we've got it bonded to three different things. So normally this is what it would look like, and we have a bond angle of 120 degrees. But in this case, we've got a central atom bonded to two other things, just like in our 1st 2 examples. One thing bonded to to other things, but we need three electron groups. As of now, we only have two. So we out of one pair Now we've got three electron groups that we have a tribunal plainer electron geometry. But since we have a lone pair here, we have a bond angle that is less than 120 degrees, meaning that this cannot be a linear molecule. So this, we would also say, is not linear, and something like this would actually be bent. So we have two things that are not letting our for original question asked us out of these three with three atoms per molecule, which of these electron geometries are not linear. So we would say Tetra hydro is not linear. Octahedron is linear and trickle plainer is not linear.