Hey, there. Today we're doing another fun genetics problem. Okay? Eso We're looking at fruit flies as per usual. Most common thing, I would say used in any genetics problem is fruit flies because they let's actually think about that. Why are they used so much? Okay, um, the reason they're used so much is because they have really short lifespans and very distinct. They're very simple creatures that reproduce quickly, which makes genetic experiments on them. Super easy cost effective, humane. They don't really have, like, pain receptors, like my stew or anything like that. And it makes life a lot easier and you don't have to deal with. Like, for example, if you're doing in sexual things, that matters a lot less on more simple organisms, like flies. Okay, Okay. So moving on. We're talking about auto Cemal recessive genes, and they're on the chromosome three. They are separated by 20 map units, which is what the EMU stands for. On this, I've kind of written out. Basically, I'm going to go over this. I thought it would be easier and more organized if I kind of just typed it for you. Uh, that way that you can see what the answers are, but I'm going through the math. So posit any point if you want to stuff I've hand written comes from the equation itself. This is the information that we need. Basically, I would write this down always. I would write down all the information you'll think you'll need, so I would write down, uh, chromosome three and 20 map units, which I kind of wrote down right here. So this stuff is important because you're like it's just word jumble. But it is important. You know, you want to be able to look at this information and make and not get too overwhelmed because word problems air overwhelming. That's very valid. It is to Mia's well and realized that you just need to simplify the problem down into a math problem because that's all it is. It's a math problem. It's just a math problem using concepts, concepts. And that's the only time biologists really do. Math is when they have to apply biology, and you have to be able to know how to do this because in a lab typesetting you'll have some grad student or whatever working for you, right and saying you go inject or something like that, but they won't know the concepts or you'll have some computer science person doing it. They won't know the concept, so you have to be able to explain to them how to do the concepts. So even though a lot of times people are like and I don't really have to do this, it's still important to know how to do it. You have to be able to know how to do it. Yet the walk before you can run or whatever, you know what I mean? Like, you have to know how to start off before you can be a big bus. Anyway, Sorry that was a bit of a it's it's important I'm going to stick by its important. So let's move on with a So we have this combination and the re pumped convict recombination frequency between E and row is 20%. That's stated in the question. That's where I got that number and as they're separated on chromosome three, but 20 map units eso each of the re competence is then e plus row and e row plus will be 10% in each of the non re competent so e plus r oh, plus an e r O will be 40% as f sorts. Independently. Each of these will be split equally among F positive and F and Thena types of the progeny. And they're expected proportion is what is following that. So I kinda it doesn't really matter. It's best to have a system, right? So I use the same on both. Um, look at this. So e plus r oh, plus f plus, um, that's a recombination frequency. It's 20%. We know that, um, it has to be split equally among so it's 20%. Okay, does that make any sense? Uh, basically, you're doing You want to be able to share equally between ethnic positive. And so that's why it's 20%. Um, as you move down, though, it becomes 5% Which is interesting. Um, because look. Okay, so remember, we're sharing this equally e plus r o. So that's what that is right there. And then e r and then divided by two. Basically because of the how they're split equally. Anyway, I hope that helps you understand that one. It's a little complex at first, but once you get the hang of it. It's easy. I mean, you don't even need a calculator. Just divide by two e plus our. So that's that's part A That that is the finished answer. You're just dividing by two. It's it's really not that Oh, it's more concept, jewel, once you get the concept a concept down the math of super easy. So I just used Blue to indicate all the answers You're gonna want to write down all this. It gets confusing. So I have a system. I went positive and then I did. Yeah, you see? So next up we have be the calculations are the same as an A, but the Onley here, the re competence R e plus R oh, plus e r o and the non re competence R e plus R o N E r oh plus So it switches them. It's the same thing, but it switches them. So you just do the math. You figure out that those air no longer the re confidence is still 40% 10%. Just you're switching thes with these ones that are the non re competence in the last one, and so you're getting 5% 5% 5%. 5%. 20%? 20%? 20%. 20%. Anyway, I hope that helps you understand this type of problem. Um, usually these type of problems are done with something else. So you like, have a map unit problem combined with a bunch of other different things, like chi squares. Whatever. So I hope that helps you understand. Have a great day.