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Help with the calculation;1. make 2 mL of an approximately 5.75% (by mass) NaOCl (74.442g/mol) bleach solution. You will be provided with a 12.5% bleachsolution. Yo...

Question

Help with the calculation;1. make 2 mL of an approximately 5.75% (by mass) NaOCl (74.442g/mol) bleach solution. You will be provided with a 12.5% bleachsolution. You may assume that the densities of the two solutionsare 1 g/mL, as the precise amount is not critical.2. Make 2 mL of a 10% by mass solution of sodiumthiosulfate (158.11 g/mol).

Help with the calculation; 1. make 2 mL of an approximately 5.75% (by mass) NaOCl (74.442 g/mol) bleach solution. You will be provided with a 12.5% bleach solution. You may assume that the densities of the two solutions are 1 g/mL, as the precise amount is not critical. 2. Make 2 mL of a 10% by mass solution of sodium thiosulfate (158.11 g/mol).



Answers

Liquid chlorine bleach is really nothing more than a solution of sodium hypochlorite, $\mathrm{NaOCl}$, in water. Usually, the concentration is approximately $5.1 \% \mathrm{NaOCl}$ by weight. Use this information to calculate the approximate $\mathrm{pH}$ of a bleach solution, assuming no other solutes are in the solution except $\mathrm{NaOCl}$. (Assume the bleach has a density of $1.0 \mathrm{~g} / \mathrm{mL}$.)

Before calculating the mola parity of this solution. That is 6% sodium hypochlorite. Let's first recall what is meant by mass percent, mass percent is simply the mass of the salute sodium hypochlorite divided by the mass of the solution times 100. So if we have 6% sodium hypochlorite solution, that means we have six g sodium hypochlorite per 100 g of the solution. So let's start with this definition and convert the grams into moles and convert these grams into leaders. So we get grams for leader, which is more clarity. Yeah will convert the grams sodium hypochlorite to moles by dividing by the molar mass. Well then convert the grams of solution into mill leaders by multiplying by the density of the solution And then convert the mill leaders into leaders by multiplying by 1000. All units will cancel except for moles and leaders moles per liter is more clarity. So we get .838 molar sodium hypochlorite

In this problem, we're going to be looking at a reaction that's going to form a bleach solution and we're going to be writing a balanced chemical equation for that reaction, doing some story geometry and basic conversions. And then working with substances, substances at STP to solve for how many leaders of CL two at STP, we need to Form 1000 l of said solution. So let's start with the balanced chemical equation. It says that this solution is forming from Cl two and that is, and it's also going to react with N A ohh, which is going to form an A C. L. O. And A Ceo and water. Let's go ahead and balance this equation. We have chlorine, sodium, hydrogen and oxygen. We have two Koreans and then one of everything else. And on the other side we actually have two of everything. Which is great because that means I can just put a two in front of RNA O. H and then we're completely balanced. Moving on, we want to find the mass of N A C L O were given that the density is 1.7 g per milliliter And that we have 5.25% and a cielo by mass. So let's work that out. If we start with what we know we have, which is our density mass equals density times volume. Our density is 1.7 g per milliliter. Then let's work this out. We have one .07 g Per one million later. Multiply that by our volume, Our goal is 1000 L here. So that's our volume one leader is 1000 No leaders. And when we do all of this, those milliliters are going to cancel. These leaders are going to cancel and our answer is going to be in grams. So 1.07 times 1000 times 1000 Equals 1.07 times 10 To these six power g. Now, that's not our final answer because like I said before This is at 5.25% and a cielo by mass. So we need to go ahead and factor that in as well. And the way that we do that is we just multiply that by 5.25 Divided by 100. Which is going to give us 56175 grams of N A cielo. The next thing that we want to do is convert that grand value into moles. So 56175 g of N a cielo. And we want to convert that to mold. So we need to know the molar mass. Well we have sodium chlorine and oxygen, sodium Mueller mass is 22.99 Chlorine is 35.45 and oxygen's is 15.999. We don't have to multiply them by anything since they all only have one. So we just some those together. And when we do we get 74.44 grams per one mole. So 56175 divided by 74.44 gives us 754 0.63 malls of, sorry, N A C L O. Next we're going to Find the moles of cl two that we have by doing a story geometric ratio. So if we have if we produce 754.63 moles of N A Cielo. And we go back and look at that balanced chemical equation that we made. We see that the ratio between cl two and n A c L O is 1 to 1. So one mole of CL two is needed to produce one mole of n a c l O. So it's 1: one. That's very convenient because that just means that We have 754.63 Moles of Cl two. So now, if we want to find the volume of that at STP anything at STP is 220, Sorry, 22.4 leaders of any element, So 754.63 moles of CL two at STP one more is 22 0.4 liters, 754.63 times 22.4 l Is going to be 1.69 times 10 To the 4th power Leaders of Cl two.

And this question we are looking at two reactions. So the first one is yeah reaction of sodium hyper chloride with iodide ion. So you can see that reaction one, it shows the net ionic reaction between the hypochlorite ion and iodide ion. And the story geometry for reaction to we have the sodium theo sulfate reacting with the resulting iodine and the iodine is reduced. So you can see that. I have the net ionic reaction for that as well. And the stock geometry. So what we need to do is we need to find the mass of the given volume of police solution. Using the density of the bleach solution. So recall that one centimeters cube. You go to one middle leaders. So we have five mL of bleach. The density of bleach is one g familiar later. So we can use that as a conversion factor. And we get that we have five g of bleach. So now we can use toy geometry to determine the mass percent of the sodium hypochlorite. So we are given the polarity of the sodium c of sulphate solution. We also know the volume of that solution. So change the volume from mm to leaders by dividing by 1000. Moving the decimal place three places to the left. So we're going to take more clarity, multiplied by the volume and we get the moles of the sodium theo sulfate and one mole of sodium ceo sulfate. We have one more of the cco theo sulfate ion. So we can use that mole ratio to convert two moles of theo sulfate. And then you can see from Reaction to one mole of feel sulfate ion reacts with one mole of iodine. So we can also use that well Ratio to convert two moles of the iodine. So then we go back to the first reaction. So you can see from the first reaction that one mole of iodine reacts with one mole of the hypo chloride ion. So we can use that to convert two moles of hypochlorite ion in one mole of sodium hypochlorite we have one mole of hypochlorite ion. So we're going to use that mole ratio to convert to the moles of the sodium hypochlorite it. Now we need to have the mass of the sodium hypochlorite. So we're going to take the molar mass of the sodium hypochlorite and use that to convert to the mass of sodium hypochlorite. That is needed to react with the original sodium theo sulfate solution. So multiplied by the molar mass. But now that we have the mass of sodium hypochlorite we need to divide by the mass of the bleach solution. So we had five g of the bleach solution. So we divide by five And then we want the mass%. 100. We do .07 times .025. And then multiply by molar mass 74.44 Dubai by five. Yeah. Yeah. Mhm. And then you need to also multiply that by 100. And also you needed to divide by the two moles of the story um feel sulfite as well. So if you perform the calculation correctly we get 1.30% of the sodium hypochlorite in the bleach. Yeah.

Hi guys would solve problems for 10.1 30. Really? To calculate how many leaders off going and sander temperature impression will be needed, um lives through them. Problem. It is even that the myself sodium hypochlorite is off my fund to fight first days falling off the bleach solution is 1000 liter. The density also don't have authorities. Authorities. I want 107 grams per minute and that this trend of temperature and pressure falling. Mistreated 2.4 liter is that given information and no lights. Lidstrom rattle the bettors Chemical reaction for the preparation off leech from Colin on been instruction ese throwing gas on himself, right? Sweet doing oneself sodium hydroxide. And we get the leads which meant in Sudan I have a right. So Jin all right and what? Okay, so volume on sodium have folklore ID's 1000 greater than to slide by the mass Parson Danger sodium have applied, which gives us 15 evidence. Drink it down. 1000 leaders want to win with five for five 100. So these gives us Did you point Fine leader off sodium hypochlorite. Now we know And in city is he gonna do Ms or Regency Ms. Is it going to density? I want to paint volume. Let's company to the mess it is given that Virgin city off suddenly. Proprieties on point sleepers. Vampire religion We just manipulated the volume. Me cheese Did drew 0.5 leader all We can see 1.7 grand form really leader onto Broadway 2.500 by then to really leader just converting. So this corporation is going to give us 56175 Graham, no, we need to get a lead. The numbers off Morse or so Dan. Hi, Papa. Right? We know elements even masturbated. Right? Number one therefore number off nose or so Jin Hai, Poke away. He's miss. Do every morning, miss. So though. Yes, we know God created 56175 gram The more anonymous for so don't have open ideas. 74 0.44 Grandpa. More so the number of morals he's going to be 7 54.63 more Now we can see that on the one wall off. Corinne produces 11 off. So do you have a playwright? Therefore, the numbers the number of moves off clothing is the same as the number of more So so go right which we just can't related. 7 54 points 63 more no and two Standard temporal region and pressure The volume one more building these trying to do 0.4 I need you. Therefore the volume 7 54 1 60 one's going should be didn't do point Full defined by 7 54.63 Beecher between Give Us 16,903 0.7 Leader So 1,609,003 17 Leader growing is required to produce 1000 leads solution.


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