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Coherent light of wavelength 500 nm passes through two slits. Inthe resulting interference pattern on a screen 4.6 m away, ifthe 9th bright fringe forms at distanc...

Question

Coherent light of wavelength 500 nm passes through two slits. Inthe resulting interference pattern on a screen 4.6 m away, ifthe 9th bright fringe forms at distance fromthe central fringe (m=0) 20mm, What is the separation of the twoslits?Express your answer for "d"in mm units.

Coherent light of wavelength 500 nm passes through two slits. In the resulting interference pattern on a screen 4.6 m away, if the 9th bright fringe forms at distance from the central fringe (m=0) 20mm, What is the separation of the two slits? Express your answer for "d" in mm units.



Answers

Light with a wavelength of 576 nm passes through two slits . If
and forms an interference pattern on a screen 8.85 m away. If
the linear distance on the screen from the central fringe to the
first bright fringe above it is $5.36 \mathrm{cm},$ what is the separation of
the slits?

Hi friends. Here it is, given the length of like used is 5 76 nanometers. Distance of testing. Sorry. Position of French from the central right 25 136 centimeter distance intestine From this rate, 8.85 meter and you are getting first ordered. Right? So atmosphere, too. But why is good too early? Turn of data. So 10 of the two you will get by upon in 10 and worse off 5136 10 to give four minus two upon 8.85 So it is to be, what, 34 70? No for bright fridge Design of theater is aiming to Linda, so these got to everyone. Upon sign of theater, they have length is given 5 76 10 to the apartments. 9 m. Say not quite three full nine. So it is a story 0.5 and 10 to the par minus 5 m. That's thanks for watching it

We have Frank Bush and X equals and Lambda as over D. So we can find from here that d equals and them the L over X and putting the numbers in. We have any quest Food them baked with 6 80 Dan omitted times. Alec was two meters divided by X equals 38 millimeter. So that comes out to be 1.4 times 10 to the negative food major.

We have does the why it was our Lambda over B. So from here we can find that the six separation is our them. Dover Del Dewie. Putting the numbers in our is 1.8 meter times webbed and 4 50 nanometer divided by Delta Ye's 4.2 millimeter. So from here we find d equals 1.93 times 10 to the minus four meter.

I have three. But, he added, is given that going like this Prevalent 4 59 0 m. What's on? Double secret on a screen? 1.8 m of it. That distance between dark friend is is 4.290 m. That is pretty, but it's 4.2 Nano meter. Sorry. Millimeter. I'm really sorry. What is that? Separation between the select DVF. Quite. It's gonna be Lambda be upon thee. They've let this 4 15 altimeter so it has to be converted. And to meet it is one point it and separation between the dark red is for quite too, you know, millimeter. So convert it on solving it you will get 1.93 Oh, 0.193 m. This is the under part. This problem. Thanks for watching it.


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