5

Verify the Midpoint Formula. (Hint: You must show that the formula gives the coordinates of a point on the line through the given endpoints and that the point is eq...

Question

Verify the Midpoint Formula. (Hint: You must show that the formula gives the coordinates of a point on the line through the given endpoints and that the point is equidistant from the endpoints.)

Verify the Midpoint Formula. (Hint: You must show that the formula gives the coordinates of a point on the line through the given endpoints and that the point is equidistant from the endpoints.)



Answers

Verify the Midpoint Formula. (Hint: You must show that the formula gives the coordinates of a point on the line through the given endpoints and that the point is equidistant from the endpoints.)

Wants us to find the midpoint of the line segment with the endpoints negative Tuesday around in 62 I want to do that. We use the midpoint formula, which just says that some of the X values it's about about to give you the X coordinate of the midpoint and the sum of the Y values to body about two. We could be the white coordinator of the midpoint case of my ex. According to the mid point will be negative two plus six, which is four Ford, about about two is two. The White coordinates zero plus two is to write about two is one. It's the mid point of this line segment would be the point to wanting thank you very.

This one wants us to find the midpoint of the line segment with then points at negative to two and then to negative 10. After we find the midpoint, there's some more work to be done. The first thing we'll do is use the midpoint formula. Just says that some of the X values negative two plus two about it meant to It was the X coordinate of our, uh, Ms and some of the wide I used to plus negative 10 over to give us the white corner of our midpoint. Yes, of the X coordinate is negative two plus two, which is 00 Divide about 20 two plus negative. 10 is negative. Eight negative eight. About about two negative for okay, The last step. It wants us to show, um, the midpoint the same distance from from each point. So we use the distance formula. So for my first point, made it a square root of the difference between zero and two, which is two squared, plus the difference between negative for into, which is six. Okay, so two squared plus six squared. That's just going to the square root of 40. That's the distance from the mid point to the first point and the second point. The difference from 0 to 2 is two squared in the distance from are the difference between negative 10 and 46 Again to skirt was six squared a skirt of 40. Since these two are equal, that means the distance between those people the distances between the midpoint. The end points will be equal. Thank you very much.

This problem wants us to find the midpoint on the line segment with then points at 26 and 42 In order to do that. Emily is the midpoint. Foreman just says that some of our exercise two plus four over to give us the middle of the X coordinate of our midpoint and some of our y value six plus two over to give us the light cordon of the midpoint. Okay, on. So that coordinate will be two plus for over two is six ever to which is three six plus two is a 8/2 is four. Next he wants money is the distance for Mo to show that the midpoint is the same distance from 26234 is it is from for two, 234 So the distance formula, uh, just says, um, the difference in our excess square, it's the difference between two and three is one and the difference between six and forest too. So one squared plus two squared is just equal to five. This is just the distance will be the square root of five. And then for our second point from 4 to 2 to 3 to 4. The difference between four and three is one again, and the difference between two and four is two again to the distance from the mid point to the second point, we'll also be Route five. Therefore, the distances are the same. Thank you very much.

It's prom wants us to find the midpoint on the line segment, which his end points are negative. Six is a girl and negative 10. Negative, too, and then use the distance formula to show that the distances are the same. So the midpoint formula and says, If we if we add the X coordinates negative six plus negative 10 that is not looking for a connective 10. Ah, over too will give us the exporting of our mid point. Some of the Y values Give us the divided about table. Give us the white coordinate of our point. Negative. Six. Post negative tennis. Negative 16 to write about two is negative. Zero plus negative, too divided, but two's negative one. It's not a midpoint should be at the point. Negative eight. Negative one. The distance formula now just using it to do the distance between our midpoint in our first point. The distance between negative six and negative eight is, too. So are a difference in excess is too so two squared, plus the difference in our Y values. Negative one from zero is just one squared, two squared plus one squared is just gonna be the square root of five kid for a second point. The difference between 10 and negative 10 and negative eight is two again. It's really too squared. Plus two. The difference between the lie values difference between negative and negative one is one again and two square post one squared will give us a return of route five again. So these do distances are infront equal. Thank you very much.


Similar Solved Questions

1 answers
Frollem $ (3 points) Solve the given initial-vale problem and sketch tn? sclusioz for large DO NOT use Laplace transform9y gin 3t , 9(o) =V() =-[
Frollem $ (3 points) Solve the given initial-vale problem and sketch tn? sclusioz for large DO NOT use Laplace transform 9y gin 3t , 9(o) =V() =-[...
5 answers
Solve for the Laplace transfon; YO) = of the solution of the differential equation "" -2y' - 8y = e" cost +4, Y(0) =3, V() =6 DO NOT SOLVE THE DE ( There should be one fraction as the final answer with no fractions in the numerator).
Solve for the Laplace transfon; YO) = of the solution of the differential equation "" -2y' - 8y = e" cost +4, Y(0) =3, V() =6 DO NOT SOLVE THE DE ( There should be one fraction as the final answer with no fractions in the numerator)....
5 answers
Redox predominance diagram for the element berkelium (Bk} given the following 9. (a) Draw a standard reduction potentials: BK + 3e Bk (s) E' = -[.97 VBk 1 3eBk + (s) Eo =+1.64 V(b) Will berkelium metal react with water?pollution problem. In what oxidation state would you (c) Suppose berkelium becomes a water expect t0 find it in contact with natural water? .
redox predominance diagram for the element berkelium (Bk} given the following 9. (a) Draw a standard reduction potentials: BK + 3e Bk (s) E' = -[.97 V Bk 1 3e Bk + (s) Eo =+1.64 V (b) Will berkelium metal react with water? pollution problem. In what oxidation state would you (c) Suppose berkeli...
5 answers
7:58LCieji 07`4LLKUDAA-c) "1 269~Frem' obov @pmale 5.9 - 3K lini +Yc F(e) L D=4442 T
7:58 LCieji 07` 4LL KUDA A-c) "1 269~ Frem' obov @pmale 5.9 - 3 K lini + Yc F(e) L D= 44 42 T...
5 answers
(1 palni) Supposa nonn? distrlbuted random variabla wth /4 10 and & P(8 < I < 15.)1.1. Find each ol the following probabilities:P(73 < 1 < 16.5) P(5.1 < I < 17) (a P( 2 631Plr < MV) =
(1 palni) Supposa nonn? distrlbuted random variabla wth /4 10 and & P(8 < I < 15.) 1.1. Find each ol the following probabilities: P(73 < 1 < 16.5) P(5.1 < I < 17) (a P( 2 631 Plr < MV) =...
5 answers
Find the inverse of each function.gl) =- 2x -4g(n) = "+2 A) g 'Gn) =FX+5 A) g "(x)= 8 'W)-4+3 8 "W)= 3x+4 C) -9+4x D) g "()=-B) g '(n) =-g '(n) =D) g '(n)e
Find the inverse of each function. gl) =- 2x -4 g(n) = "+2 A) g 'Gn) = FX+5 A) g "(x)= 8 'W)-4+3 8 "W)= 3x+4 C) -9+4x D) g "()=- B) g '(n) =- g '(n) = D) g '(n)e...
5 answers
Two vchicles are approaching an intersection. One is $mathrm{A} 2500$ kg pickap traveling at $14.0 mathrm{~m} / mathrm{s}$ from east to west (the $-x$ directiot), and the other is a 1500 -kg sedan going from south to north (the $+y$ -diroction at $23.0 mathrm{~m} / mathrm{s}$ ). (a) Find the $x$ - and y-components of the net momentum of this system. (b) What are the magnitude and direction of the net momentum?
Two vchicles are approaching an intersection. One is $mathrm{A} 2500$ kg pickap traveling at $14.0 mathrm{~m} / mathrm{s}$ from east to west (the $-x$ directiot), and the other is a 1500 -kg sedan going from south to north (the $+y$ -diroction at $23.0 mathrm{~m} / mathrm{s}$ ). (a) Find the $x$ - a...
5 answers
Jil 1 H { 1 U L 1 H U V 1 1 1
jil 1 H { 1 U L 1 H U V 1 1 1...
5 answers
Question 16 (3 points) Which of the following is NOT true about retention factor KA? 01) KA is related to tRD 2) kA is dependent of the mobile phase flow rate03) kA is related to tmKA depends 0n the property of both mobile phase and stationary phase
Question 16 (3 points) Which of the following is NOT true about retention factor KA? 01) KA is related to tR D 2) kA is dependent of the mobile phase flow rate 03) kA is related to tm KA depends 0n the property of both mobile phase and stationary phase...
1 answers
Use long division to find the quotients and the remainders. Also, write each answer in the form $p(x)=d(x) \cdot q(x)+R(x),$ as in equation (2) in the text. $$\frac{x^{6}-64}{x-2}$$
Use long division to find the quotients and the remainders. Also, write each answer in the form $p(x)=d(x) \cdot q(x)+R(x),$ as in equation (2) in the text. $$\frac{x^{6}-64}{x-2}$$...
5 answers
Evaluate each expression. See Example 1.$$(-4)^{3}$$
Evaluate each expression. See Example 1. $$ (-4)^{3} $$...
5 answers
Question 23A red glaze on porcelain can be produced by using MnSO4: What i5 its name? manganese sulfate manganese(Il) sulfate manganese(IV) sulfate manganese disulfate manganesel) sulfate
Question 23 A red glaze on porcelain can be produced by using MnSO4: What i5 its name? manganese sulfate manganese(Il) sulfate manganese(IV) sulfate manganese disulfate manganesel) sulfate...
5 answers
Point)Give an expression for f(x) wth leading Fundamental confliclent Thcorm 2 , 0f dogree and Algebra Your Inal answar should having roots x = 6 not contain any i "&, and ~3+ 2i. f(x) 'polynomlal 0t degree - with the given roots and leading coefficiantProblom -
point) Give an expression for f(x) wth leading Fundamental confliclent Thcorm 2 , 0f dogree and Algebra Your Inal answar should having roots x = 6 not contain any i "&, and ~3+ 2i. f(x) 'polynomlal 0t degree - with the given roots and leading coefficiant Problom -...
5 answers
Yo Ls (aJis #6) (wcelev (oi ( Op trns Df 2.0 Plows_Yhvvzl Dv 1. 4o n # Luvveut M tevzuc AL+ A Coc1 , Cos] . Fws # V4axi txt6; {kis Luvnent Lou expet& (h cni(rm 22 mT Msxhchl nels . 1.96 K l Nm E: 372 wm 0 n'M F< 196 3,45 Kl w.M B N'M 6 : 4xlo ~6 Nm C : 3.2 / X/o ~4 0: 9.43 Xto N.M
Yo Ls (aJis #6) (wcelev (oi ( Op trns Df 2.0 Plows_Yhvvzl Dv 1. 4o n # Luvveut M tevzuc AL+ A Coc1 , Cos] . Fws # V4axi txt6; {kis Luvnent Lou expet& (h cni(rm 22 mT Msxhchl nels . 1.96 K l Nm E: 372 wm 0 n'M F< 196 3,45 Kl w.M B N'M 6 : 4xlo ~6 Nm C : 3.2 / X/o ~4 0: 9.43 Xto N.M...

-- 0.021023--