Hi there. In this question, we are looking at three genes that have three independently sorting a Leal's. We have one gene that can have the illegal capital A or little A. We have another that could be capital B or a little B, and we have a third that could be capital C or lower case C. Typically, the usual convention is that the capital letter represents the dominant alil of the two, and the lower case represents the recessive eso. We're talking about gamete formation here. Remember, In gamete formation, a cell goes from to end to help Lloyd or one end. So it goes from deployed to Hap Lloyd, meaning it has half the genetic material. And when these Ulliel segregate, there is independent segregation, meaning that the A's will segregate independently of the bees which are independent of the seas. So we can get several different combinations of gametes as we look at these illegals. So let's see what we in fact can have. So we are looking for what GAM is will be produced. So I will put this over here as a column. Thank you. This somewhat like a table. So in letter a we have Helios Capital, a capital a capital B, capital B and Capital C Capital C. The GAM eats need to have one of the a Leal's one of the bill eels and one of the seal eels. Well, in this particular combination, all of these are homos, I guess. Dominant. So we look at the A's. The only option is a capital A, regardless wittily Elice selected. The same is true for the B and the same is true for the sea. So the Onley gam eat that would be produced from this genotype would be capital a capital B capital C. Let's go on to let her be and let her be. We have the genotype capital a little a capital B capital B, a capital C little C. So for the A, we have two options. We can either have a capital a Lille or lower case A for the b A will. There is again only one option, just the capital B. And for see, we could have capital C or lower case C. So this is going to give us more possible combinations because we can have capital A with a Capital B in a Capital C or we can have capital A with the Capital B and lower case C. So let's go ahead and get those written out here. So, capital, a capital B capital C we could have capital a capital B or K C. And then we could do the same thing with the lower case A. So we can have lower case a capital B capital C or lower case A capital B, lower case C. So that gives us four possible A Leal's Yeah, for part B, whereas in part A, we only had one option. Let's move on to let her see the Gino type we are given and let her see is capital a little A capital B Capital B and lower case C lower case C. The the illegals for the A are the only ones that are different. B is homo zegas for Capital B and C, his home a zegas for lower case C. So that means we could have capital A with Capital B and lower case C or we could have lower case A with Capital B and lower case C. Those are the only two possible combinations we could get. So those of the gammy possibilities. All right, And then finally letter d letter. Dee's a little bit longer because each of these is hetero zegas Have capital a kept little a capital be little B capital C little c. All right, so we're gonna have a few more combinations here. Let's see if we can get all of them. So Capital A could go together with Capital B and capital C capital egg. Go with Capital B in lower case C capital A can go with lower case B and capital C Capital A can go with lower case B and little C. Alright, so that takes care of thes combinations. Let's look at little A. So we had capital A with being little. See, we had capital A with little B and pixie. We had capital A with little bee in little C. Yeah. All right, e. Believe those air all the combinations we can have for Capital A. Let's look at lower case. A lower case. A can have all of these same possible combinations with B and C. It's a little a big be big C little a big B, little c a little a little b Capital C and little a, um, little B little c que. All right, so we see that we have eight possible gametes here. And that makes sense. Because if we have two options for that one and two options for that one and two options for that one two times two times two or to cube equals eight. So eight possible combinations for those illegals in the gametes. All right, that concludes this question. Thank you so much for watching.