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27. You want to determine the effectiveness of a new compound on increasing T cell count for individuals with compromised immune systems: You study 9 volunteers tak...

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27. You want to determine the effectiveness of a new compound on increasing T cell count for individuals with compromised immune systems: You study 9 volunteers take the average measure before treatment(Day ]) and thee average measure after 3 weeks of treatment (Day 22). Carry out a paired test for the data collected below. Alpha 0.1 Mean sd SE Day 186 107 126 123 164 408 548 324 227.9 163 Day 22 269 310 130 269 189 560 540 620 415 366.9 174.6 Difference 83 203 143 396 132 139 106.62 35.54Stal

27. You want to determine the effectiveness of a new compound on increasing T cell count for individuals with compromised immune systems: You study 9 volunteers take the average measure before treatment(Day ]) and thee average measure after 3 weeks of treatment (Day 22). Carry out a paired test for the data collected below. Alpha 0.1 Mean sd SE Day 186 107 126 123 164 408 548 324 227.9 163 Day 22 269 310 130 269 189 560 540 620 415 366.9 174.6 Difference 83 203 143 396 132 139 106.62 35.54 Stale (+ Would you Reject or Fail t0 reject Ho?



Answers

Use the following information to answer the next seven exercises: Studies are often done by pharmaceutical companies to determine the effectiveness of a treatment program. Suppose that a new AIDS antibody drug is currently under study. It is given to patients once the AIDS symptoms have revealed themselves. Of interest is the average (mean) length of time in months patients live once starting the treatment. Two researchers each follow a different set of 40 AIDS patients from the start of treatment until their deaths. The following data (in months) are collected.

Researcher A: 3; 4; 11; 15; 16; 17; 22; 44; 37; 16; 14; 24; 25; 15; 26; 27; 33; 29; 35; 44; 13; 21; 22; 10; 12; 8; 40; 32; 26; 27; 31; 34; 29; 17; 8; 24; 18; 47; 33; 34
Researcher B: 3; 14; 11; 5; 16; 17; 28; 41; 31; 18; 14; 14; 26; 25; 21; 22; 31; 2; 35; 44; 23; 21; 21; 16; 12; 18; 41; 22; 16; 25; 33; 34; 29; 13; 18; 24; 23; 42; 33; 29

Suppose that the first researcher conducted his survey by randomly choosing one state in the nation and then randomly picking 40 patients from that state. What sampling method would that researcher have used?

The type of sampling would be convenience. Since he knew all of them and the people selected were not selected randomly. There is probably some bias that would be even unknown. So you can't do a sample like that. It's gotta be his random. This could be.

For 21. We're looking for two ways. Researchers could probably get a sample of 40 so the first way would be a simple random sample. So if you late game every patient a number, say 12 all the way up to the last patient and then you randomly select 40 numbers could be with a random number generator, a random number table, a lot of different ways of doing that. Another possible way would be a stratified sample. So for a stratified sample, you could potentially put him in the two groups. They split him up in the males and females and then randomly select 20 out of each room. You could do it that you could make your groups in age groups less than 30 32 50 over 50 once again picking a certain number from each group.

Right, where will the population has mean new equals 14 From the following sample data, we want to calculate the sample mean X bar and the sample standard deviation S. To do so let's remember the definition of these terms X bar Is the some of the data divided by n or in this case 15.1, I'm a sample standard deviation S is the sum of deviations about the mean square divided by n minus one or 2.51 Next we want to implement a right tail test. That is we want to test whether or not the population mean should actually be greater than the no mean 14. With us using the sample data with a significance level alpha equals 140.1 Where we are noted that X is approximately normally distributed. So to implement this test, we have to answer the following questions in order First, what is the significance of hypotheses? We've alpha equals 0.1 H not is new equals 14 H. A. Is that I mean is greater than 14. What distribution will use computer associated test statistic? Since the population standard deviation sigma is unknown. We have to use a student's T distribution which we know is okay to use because the shape of the distribution is normal, which is both symmetrical amount shaped from this. We calculate the T stat Which is given by this formula and reduces down to 1.386 for this problem? Next compute the p interval and sketch it out so we have degree of freedom and minus 29. We use the one tailed T. Table to identify that this tea interval falls between a p interval of 10.75 point one. That is because our T statistic falls between associated T values for these p values. We can graph this as the area under the student's t distribution. To the right of our T stat 1.386 as is highlighted in yellow on the right. What can we conclude from this? Well, we can conclude that P is greater than alpha, so we have statistically insignificant findings and we fail to reject astronaut, which means that we lack sufficient evidence that suggests our population mean is greater than the No. Mean 14.

A question number 14. It was given four males. These values, which export equal to 4.719 and is equal to 4.490 four. Females, export equal to 4.349 and as equal toe or point for 102 does it. The schools is the value decreased by the mean divided by the standard Division, so milk will visit. He could do X minus X boil over US equal to five point 58 minus 4.719 over well point 490 well approximately equal to 1.7571. For females. That would equal toe X minus X board over us for equal to five points. 23 minus 44 point 349 over four point four or two, well approximately equal to 2.19 15. Since the value two points 1915 is greater than what 1.75 71 the female was. Count who's gone off 5.23 has a relatively higher count and thank you


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