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Sccte: of1pt20 ol 25 (19 complete}Ha scon: 61.396, 15.4 0l 25 ptsBus Econ 9.4.17TutonngQuestion HelpHis estimated Ihal 2,3% 0 (ho quanz heaitrs produced penbcertain...

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Sccte: of1pt20 ol 25 (19 complete}Ha scon: 61.396, 15.4 0l 25 ptsBus Econ 9.4.17TutonngQuestion HelpHis estimated Ihal 2,3% 0 (ho quanz heaitrs produced penbcertain plant aro dotectivo. Supposc ths plant produced DQQ such healers last month Find probabilities that arona thoso hoalers. tha following numbors were pcitcint ComoiisMchaLpnioounhanntenee nchnnnomna cmAoh clhhnlineaet 2atAniaundutiNkamilSuIhFetnarihan 173The probability that tower than 173 pants ar0 deteclive (Pound four decimal places

Sccte: of1pt 20 ol 25 (19 complete} Ha scon: 61.396, 15.4 0l 25 pts Bus Econ 9.4.17 Tutonng Question Help His estimated Ihal 2,3% 0 (ho quanz heaitrs produced penb certain plant aro dotectivo. Supposc ths plant produced DQQ such healers last month Find probabilities that arona thoso hoalers. tha following numbors were pcitcint Comoiis MchaLpnioounhanntenee nchnnnomna cmAoh clhhnlineaet 2atAniaundutiNkamilSuIh Fetnarihan 173 The probability that tower than 173 pants ar0 deteclive (Pound four decimal places needed ) Enter Vcr ansuer the answre box ang inen click Check Answer part remaining Clear AlI Check Answer



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In Exercises 29 and $30,$ find the probabilities and indicate when the "5\% guideline for cumbersome calculations" is used. Medical Helicopters In a study of helicopter usage and patient survival, results were obtained from 47,637 patients transported by helicopter and 111,874 patients transported by ground (based on data from "Association Between Helicopter vs Ground Emergency Medical Services and Survival for Adults with Major Trauma," by Galvagno et al., Journal of the American Medical Association, Vol. 307, No. 15). a. If 1 of the 159,511 patients in the study is randomly selected, what is the probability that the subject was transported by helicopter? b. If 5 of the subjects in the study are randomly selected without replacement, what is the probability that all of them were transported by helicopter?

In this study, it was given that 47,637 patients were transported by helicopter on 11 or 111,874 patients were transported by ground. The total is 15951 When the total is 159511 the total is 159 511 The first question is, if one patient is selected randomly. Second, what is the probability that the subject was transported by a helicopter? So this is nothing but 47,000 47,637 637 The These are more favorable outcomes upon total number of outcomes. And what does this turn out to be? This turns out to be 0.299 This is the probability 0.29 nine. This is my party. The second one is Barbie is a five of the subjects in the study a randomly selected without replacement. This is important without replacement. What is the probability that all of them were transported by helicopter? Okay, because this is without replacement. We can say that all of these are independent wait with or without replacement. Okay, without replacement. All right. So all of these are dependent. If they have without replacement, it is. All of these are dependent. So part B is going to be Let's take first patient. What is the probability off him or her being transferred by helicopter transported by helicopter? It is going to be this 159511 Now looking for the second patient. Second patient is 176 three 17636 Why? Because we have said the first patient aside, we're considering that he was transported by the helicopter and now we're setting him aside. So this reduces by one and this reduces by one also. 159510 This carries on still five terms. 76543 So this is going to be 47633 upon 159 five zero, seventh. This is the probability that I want. And what is just turning out to be This will be 0.239 This will be 0.239 This is the probability that I want

Number 10. A factory is located close to a city high school. The manager claims that the plant smokestacks and an average of no more than £350 of pollution per day. Someone to write that down as the null hypothesis, so no more. We're just gonna say equal to 350 as an ap stats project. That class plans a one sided hypothesis test with a critical value of £375 suppose that a standard deviation in daily pollution poundage is known to be 100 and £50 and the true mean is £385. So we have the true mean to be 3 85 with the standard deviation of 1 50. If the sample size is 100 days, what is the probability that the class will mistakenly fail to reject the factory managers false claim. So the alternative hypothesis would naturally be greater than 3 50 but we have the true meaning of 3 85% innovation, 1 50 with a sample size of 100. What is the probability that the class will mistakenly fail to reject the factory managers false claims? So mistakenly failing to reject is a type to error here. So for this class, they are going to reject past 3 75 which means they are going to fail to reject if it's less than 3 75. So let's find the probability that see is less than this test at 3 75 minus the true mean, in this case at 3 85 divided by the standard deviation 1 50 divided by route 100. Alright. Doing few calculations here. We get the probability that Z is less than negative 0.67 We can look on our chart or we can look on the um to 83 or 84 calculator using the normal CDF command. So drawing the picture to kind of get a look of what we're I'm going to type in. We have this negative 0.67 We want to find the probability of being to the left of it. Well, the lower regions where you start shading, technically that's a negative infinity will write it as negative 999 Upper bound is where we stop shading, which is negative 67 We're on a Z. Um standard normal curve. So I mean is zero center deviation is one. We plug this in and we get 0.2 five and looking at all of our answer choices. The answer choice that represents that is option B.

In this case there are 47,637 patients are transferred by helicopter, and 188 of them left the treatment center against medical advice, which means that the other 47,004 and 49 did not leave against medical advice. A 40 off such subjects transported by helicopter, randomly selected without replacement, which means if there without replacement, they are not mutually exclusive or they're not independent. What is the probability that none of them left the treatment center against medical advice? Which means that if I am to write this, if I'm right, this probability taking 1% of the time this will be for the first person this will for the second person, and this will go all the way up to 14 terms now this can become very cumbersome. So in this case, I can use this 5% guideline for cumbersome calculations, and I can consider these to be mutually exclusive or independent events, and I can write this as raised to 40 and this calculation turns out to be zero point 850 point. This turns out to be 0.85 close to 0.85 and this is the probability that I want

Hi. We're looking at questions 79. If all occupations are equally likely for a certain individual, what is the Probably that here she will have an occupation with lower than average T h I s. Hopefully you had to do question 78. Or you can look up the answer to that to find, because that tells us that our average e h I s was 81.3. So that makes this question very similar to most of the rest of the questions in this section. We're going to go to our table at 3.12 and are favorable outcomes are going to be our bars there below 81.3. So if we look, our occupation of manager, executive or officials used to be 81.5 eso not that barb. Any of the other ones, they're shorter would all satisfy what we're looking for. And so there are seven of those. It would be service, transportation, manufacturer, production, sales, clerical or office installation and repair and construction reminding. And then we're gonna divide by our total possible outcomes, which is all 14 of the occupations. So the probability that your VHS be lower than average is zero point size. Thank you.


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