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An electron microscope is designed to resolve objects as small as 0.22 nm_ What energy electrons (in eV) must be used in this instrument?...

Question

An electron microscope is designed to resolve objects as small as 0.22 nm_ What energy electrons (in eV) must be used in this instrument?

An electron microscope is designed to resolve objects as small as 0.22 nm_ What energy electrons (in eV) must be used in this instrument?



Answers

An electron microscope employs a beam of electrons to obtain an image of an object. What energy must be imparted to each electron of the beam to obtain a wavelength of $10.0 \mathrm{pm}$ ? Obtain the energy in electron volts (eV) $\left(1 \mathrm{eV}=1.602 \times 10^{-19} \mathrm{~J}\right)$

Solving this problem here we have given we've landed 0.25 and then changing the unit. I just multiplied by this value, which is equal to 2.5 multiplication than to the par -10 m. Now from the bottle is weird and I can be formulated by envy on simplification. I can devalue period at by I'm linda. So just putting the value here, I can write the value ph 6.626 multiplication and 10 to the par -34 jules. Second bye 9.11 multiplication, 10 to the power -31 Kg Multiplication, multiplication, 10 to the power -10 m. Which one simplification. I finally get the speed of Philip tonnage 2.91 multiplication, 10 to the past six m per second as our final answer for this problem.

Hello, friends. Here it is, given Elektronik microscope having the resolving power approximately equal toe baby lint off electron. If it is to be 1.1 and took 10 to the power minus 11 m, they have toe. Find the accelerating potential off electron. If it is to be a photo, what will be the energy off photo that we have to fight? Not to see it as we know that, babe. Length off. Excellent ing electrons. According to Deep Broccoli's hypothesis, wavelength is given by 12.27 Uh huh. Angus strong upon root off. Excellent ing potential. So from here, accelerating potential, you will get 12.27 square upon. We have let the square in both. We will get the answer. Substitute the well. 12.27 square Bev length is 1.1 into 10 to the power minus 11 m. So we have to write in Angus strong. Multiply by. Sorry. Divide by 10 to the power minus 10. So it becomes in Angus Trump. So on solving it it is to be 1.5 and tow. Tend to the powerful electron book. Sorry, Bolt. So this is the answer off part A. In part, we we have toe find the energy off photo Having the prevalent so energy off photon is to find us 12400 electron bolt upon babe length and Angus Trump So 12400 upon 124000.11 So it is to be 1.5 in tow. 10 to the about five electron bowl. That's all for it. Thanks for watching it.

The bubbles will blend of electron and electron accelerated to a potential difference. Be notice given by claimed A is equal to edge by under the hood to M E. E be known. So the value of the note can be written edge square by um E capital E. Named a square. So I will just put the value in this exhibition. So the expression can be written ahead. We're not is equal to 6.626 multiplication. And 10 to the power -24 jules. Again only square by to multiplication. 9.1 multiplication. And to the power minus 31 kg multiplication, 1.6 multiplication. And to the power minus 19 column multiplication 190.4 nm. Holy square. On solving it further, I can write the value of the note physical too 6.626 multiplication 10 to the Paul -34 jewels. Again all the square by to multiplication. 9.1 multiplication 10 to the par minus 31 kg multiplication, 1.6 multiplication 10 to the par minus 19 column multiplication 0.4 nm. Multiplication tend to depart minus nine m, but n. M. Police choir on simplification I get the value of being not equal to 94 to be as the answer.

From the hygiene. Spal uncertain entity principle. I can write to express an edge day legs. Multiplication. Delpy is greater than equal to death. By who. So the value of DLP can be written like this. Which on solving it further I can write the value of DLP is greater than equal to 1.055 multiplication. Then to depart -24 jewels again by To multiplication .1 and then multiplication and tend to the par minus nine m for nm which is equal to five point 275 multiplication, 10 to depart -25 K. G meter per second. Now the minimum kinetic and as required is given by Came in. Mom is equal to Delpy by um Here Delpy holy square Which is equal to five 275 multiplication. Then to depart -25 K. G. Meter purse again. Holy squared bye To multiplication 9.11 multiplication than to depart, managed 31 kitty on solving it further, I can ride the value of k minimum is equal to 1.5 to 7, multiplication, 10 to the power minus 19 2. Changing the unit, I just multiplied by this value. Return simplification. I get the value came in my image 0.95 e. p. So rounding of approximate value is one EP.


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