5

Design a reasonable synthesis for the following:HO"Note:can use onlyinorganic reagentsYour Answer:please answer the following question based on pericyclic, rad...

Question

Design a reasonable synthesis for the following:HO"Note:can use onlyinorganic reagentsYour Answer:please answer the following question based on pericyclic, radical, or polymerization principles Design an appropriate synthesis (a series of steps with respective reagents to go from the reactants to the products )

Design a reasonable synthesis for the following: HO" Note:can use onlyinorganic reagents Your Answer: please answer the following question based on pericyclic, radical, or polymerization principles Design an appropriate synthesis (a series of steps with respective reagents to go from the reactants to the products )



Answers

Provide the reagents necessary for the following synthesis. (EQUATION CAN'T COPY)

So continuing on with our work with Aldo hides in key tones. So what we have in the common functional group is C o What changes is through our groups which can be protons, hydrogen or other carbons where we have to to all groups we have I liked your Philip Carbon. We also have our oxygen atom which has a partial negative charge associated with it. So jumping straight into this reaction we have PCC is are highly selective re agent on. We can use insolvent such a ch two c l two so we can oxidize the primary and secondary alcohols to generate carbon al compounds to for example, we have here Hey, Joe pcc c H two see how to we then generate the following. I'll do hide So the reaction of alcohol hides with lethal magnesium bromide gives on alcohol a swell. So in this reaction, we'll use the material that we had just before in the presence off ch three c h two MGB are e t 20 followed by NH four Seattle Andi water each tour. We don't generate the following So now we have an alcohol instead off and all the hide So then PCC can oxidize the primary and secondary alcohols to our Carbonell compounds. So again we take the above material PCC presence of ch two c l two on What we generate is the following final step. We have the key. Turner's reacted with a grin yard re agent which allows us to add on our hydrocarbon chain that is missing here on we can transform our ketone into our alcohol group in the final step using the following re agents MGB all that is our green Yard re agent in the e t 20 solvent, then followed by and h l C L on h 20 is our final step NH four c l and H 20 allows us to carry out that final chemical transformation. Nothing has changed. Our cyclo hexane or that we have altered is our substitue INTs. And now instead, off that Keith and we haven't o h group, followed by two hydrocarbon chains to generate our final product

Yeah. Now the region's required for the synthesis because he quenches used to be identified. So let us right the sequences. What? May 19. What? Okay, Okay, you glasses. Well, it's been winning an idea. Mhm random. This needs rest and physical creation. Beautiful. See? It's your dream. Yeah, it ncnp This is far away envious. And but I'll take mhm on early. Right it is. Do you do it with minus? All right. All cities mutually in authority. Well, this sequence stop. Lessons will result in the mentality had formation, which is but what did he do? I have it up on inside your pinky toe. Okay? Yeah. Mhm The group Mhm Mhm. You? Uh huh. Mhm. Mhm night. Yeah. Explore. Right work. Yeah, yeah. See everyone see? Yes, sir. Now, this conversion can be run. This is our organization with how's he doing? So we can write discrimination us Um mhm condensation with being Yes, the annual He is two minus and cst. Right? So this we give the Alfa Beta exaggerator Oh, he told on treatment of this victory I owning Thanks Onda always minus Yeah Mhm Yes. Mhm a Kabul circus in the terminal position. Okay, mhm. Mhm. Okay, um the O h mhm belly bombs The Nazi or ex fancy annual Because the reaction has gone toe. Yeah, right. Yeah. More. Yes. I think this is treated with associate to and then eternal. Yeah, the sodium Saudis committed to do as exhilarated. Yeah, Yeah. Or minus. Or here. Oh, or C a associative video. OOCL I know this is testified Vicki McKenna. I still fired Nothing. Nothing eternal c to explain. Lloyds. So people. Okay, Okay. Everything. Seafood or me? This is what are disappointing money.

Okay. So we're we want to create the falling compounds using an intramuscular reaction. And the first day of the structure. So we can get this by reacting in alcohol with a carbon cast iron because the oxygen the alcohol is going to the south car broke down and we can get a carbon Callahan from in our scheme grafting with other HPR Hcl. So we have 1234 56 carbons And carbon six within a primary alcohol. Carbon three would have been not keen stretched to the ethel. So you're reacting with, are there Hcl HBr? We got a card account on and the auction is going to attack it. So this is carbon six and this is through You're separated by four carbons. You're still hopping around here. Urban is gonna be pertinent it their products and H. P. R. That's it for B. We have the structure so we can only create one ring through these reactions. So it must have started from Benzene And we have a five carbon chain attached to one of these carbons 1, 2, 3, 4, 5. So it's going to be carbon four has and that's what our shirt and this is where the carbon capture is going to be. It's a double bond is going to attack it. And we got our products. Okay, So we were keen and if we react this with and alcohol, it just started from Benson again. Then if we have five carbon chain with an uncle hale out of here, it's going to house actually edged the foreground machine. So it is if we attack the acapella, we'll get cycle ac scene. But we can also treat this with NBS and peroxide overheat because we have in our little carbon cat on So with peroxide, we'll get to meet on the little carbon, which could be either here or here and then treating this with a strong base like sodium hydroxide. We're gonna replace, bring me with ohh And then while the dehydration reaction, so rafting sulfuric acid overheat. We'll get our products. So the loss of water, It's A three D. Riding a car bustling acid. So this is similar to um this is similar to be okay. So we can also um react cartoons with benzene to get cox that I on their treating that with alcohol. And then we can turn the alcohol into carbon stock acid by reacting with a strong oxidizing agent. So first getting the five carbon chain, I mean the four carbon chain and freedom Allah harder. Actually, I'm sorry. We can just react this with a kitten or nasty chloride. Its first going to give us hell cox that i on. And then this is going to reform to expel chlorine. So once this tax the carbon carbon we'll get our products give e. We have structure. This is balanced to a three Carbon chain with primary Elkin. So this is similar to a were acting alcohol with a car broke down. So it's gonna be 1, 2, 3, 4, 5, 67 And we have alcohol and carbon seven, Carbon four is attached to. If three carbon Jan, it's carbon four. Did you get that? 123? And we would have had a carbon cast iron here. Or we actually would have had a. Now keene. I reacted with HBR gives carbon cast iron right here. The auction is going to attack it. Does he react with HBR hcl, get this, it's gonna attack it and we'll get our products f f. This three carbon alcohol, So 1, 2, 3, 4, 5, 6, 7. And then carbon one has the alcohol as well. Carbon four would have been a carpet pattern from anarchy in So we actually, we can get to reactions here because we have the two alcohols. So this oxygen could attack the carbon Catalan so we could protect the one so that it doesn't attack the carbon Catalan. If we use TMS, catch your metal cyclone, so get the structure, we'll get our products, they're treating this with an acid. Give us the original structure. It will give us the products.

Okay, This problem is asking us to synthesize thes products from my starting materials. So let's go ahead and start with the very 1st 1 So this very 1st 1 I recognize that I have a broken here. And then I formed an l came here. So the thing about that all keen is it's not particularly substituted, right. We only have to Hodgins associated with this carbon on the O'Kane. And then we have this carbon associated with this carbon on the key. So it's only a mono substitute, okay. And generally, with the formation of Hawking's in elimination or actions, I form the most substitute. Okey. So when I formed right here is not a very subsidy scheme. And we know that because my bro minutes attached to this carbon get If we're direct this with sodium hydroxide, for example of most likely forming cocaine right here, that would be a dice up signal came that would be the major product. So when you want to form a at least have a reaction that incorporate this model subsidy scheme and generate, that is as a favorable reaction. So also, judging by the fact that the last couple pages in the textbook at the last couple problems have been dealing with health and eliminations. I'm gonna do exactly that. I'm gonna wreck this compound with extra connected to 123 method groups fit. And by doing that, this next Gen will perform a substitution reaction. It will go ahead and attack that carbon, replacing that bro me. OK, it's just a substitution reaction. So what that does is it forms this ch three safe to ch two. And instead of that broken cakes to my carbon, I now have next gin with 123 method groups with a positive charge of nitrogen kit. And then, of course, I have the remainder of my compound street. Okay, so now I'm at my Hoffman inflammation point because I can just react this compound with silver oxide in water and that's going toe form a high drops that I am to be, ironically bonded with this compound right here. So let's go ahead and act out with silver Roc side A G 20 and water. That's conformed, they say. Was that compound the only difference being that my hydroxide is now ironically bonded to it? Okay, so let's go ahead. And to put that and then one would do is at a hydroxide ion right here. Okay, now I'll have to do is utilize heat. He is going to facilitate the Hoffman elimination reaction in which I d protein ate the carbon with the most Hodgins in the beta position. So this election right now, we can consider that Adam number zero. And then, um, here we have Alfa carbons, which are one away from that and then one away from that awful carbon right here and right here are my beta Karpin's. So this hydroxide is gonna go ahead and deep pregnant the carbon with the most number of hydrogen, which is this one and that will form my product. Okay, what about this one? So this one, Same exact thing. We recognize that we have a natural compound and we have this basically stretched out carbon train. Right now, that carbon chain is in the formation of a rain. We want to stretch it out in order to form that linear structure. So what I've been doing is recognized that I already have my 1234 carbons. And in my product, I also have 1234 apartments. So what I need to do is get rid of this nitrogen hoops is get rid of this nitrogen and in the process makes him double bonds. Okay, so what I'm gonna do is react this with C h three I in excess. Okay. And I'm gonna do that in basic conditions. It's OK to see or three. Okay, that will form it. This product, that should be a four carbon compound. Okay. And then I just had to methyl groups to it with a positive charge. Okay, so the purpose of doing that is to for my ammonium, so that can proceed with Hoffman elimination. Okay, so what I'm gonna do now is reacted with a g 20 and water, and I'll just do this on state. Same step with heat, and that's gonna form this. It's gonna go ahead. And deep protein ate my beta carbon, which is this one. So take off the hadron, move the electrons onto this bond and move the electrons onto that nitrogen to form in this compound where I have my O Keane here. The remainder my compound. So should be like should be over here. I'll just reach all this. So there's my talking. Here's my compound. And then the connection to my next year with 12 methyl groups. Okay, Right now, this what I just right here is not the same as this. I still need to get rid of that extra, because I still need a double about here. I still need to get rid of this nitrogen. So what I'm gonna do is same exact thing that I did before. I'm gonna racket with ch three I in excess, or just see FBI in general to make another method group there to have a positive charge. And then we can proceed with another Hoffman elimination. So that could take off you 100 on that to make an O Keane there. Right? So what I'm gonna do is ch three. I that's gonna add a methyl group to see history. I So I have now is the same thing just with an extra method group. So that means that I have a positive charge on the nitrogen and then using a G to wealth. So we're oxide in water with heat. I'm gonna go ahead and take off this 100 moving the electrons onto here and then moving on the electrons on that I just didn't as a leaving group, and then I should form my product, okay?


Similar Solved Questions

5 answers
Use Gauss-Jordan elimination to solve the following system of equations: Xl + Sx2 + X3 = CI Xz:x} = 6. X 2x2 =c} For the following cases: € = (1,-1,-1), (-1,-1,1) and (1,1,-1)
Use Gauss-Jordan elimination to solve the following system of equations: Xl + Sx2 + X3 = CI Xz:x} = 6. X 2x2 =c} For the following cases: € = (1,-1,-1), (-1,-1,1) and (1,1,-1)...
5 answers
(a) Write an iterated integral fordA over the region bounded by y=8 -, X, y=1,and x = 2 using vertical cross-sections(b) Write an iterated integral fordA over the region bounded by y = 8 -X, y = 1, and x = 2 using horizontal cross-sections_
(a) Write an iterated integral for dA over the region bounded by y=8 -, X, y=1,and x = 2 using vertical cross-sections (b) Write an iterated integral for dA over the region bounded by y = 8 -X, y = 1, and x = 2 using horizontal cross-sections_...
2 answers
Point) The matrixhas one rea eigenvalue of algebraic multiplicity(a) Find this eigenvalue. eigenvalue(b) Find basis for the associated eigenspaceAnswer:Note: To enter basis into WeBWork place the entries of each vector inside of brackets, and enter list of these vectors, separated by commas(c) Find the Geometric Multiplicity (GM) of the eigenvalue GM
point) The matrix has one rea eigenvalue of algebraic multiplicity (a) Find this eigenvalue. eigenvalue (b) Find basis for the associated eigenspace Answer: Note: To enter basis into WeBWork place the entries of each vector inside of brackets, and enter list of these vectors, separated by commas (c)...
5 answers
Given the eccentricities of conic sections with one focus at the origin along with the directrix corresponding to that focus_ Find the polar equation for each conic section: (1Opts)e =1; Y=20 = 1/4 X=22
Given the eccentricities of conic sections with one focus at the origin along with the directrix corresponding to that focus_ Find the polar equation for each conic section: (1Opts) e =1; Y=2 0 = 1/4 X=22...
5 answers
KSnd a wle placinq bx 9 NhaF Plndardhed Work Sr Leen manutchiinyt 0xsan, = ZAh'6
KSnd a wle placinq bx 9 NhaF Plndardhed Work Sr Leen manutchiinyt 0xsan, = ZAh'6...
5 answers
The following pictures show the progress of the reaction2AAzt = mint = 15 mint = 30 minIs the reaction zero order; first order; or second order?zero urderfirst ordersecond orderCalculate the rate constant Give your numeric answer in the first box and the units of the rate constane in the second box .Report your answer t0 3 signilicant digits_
The following pictures show the progress of the reaction 2A Az t = min t = 15 min t = 30 min Is the reaction zero order; first order; or second order? zero urder first order second order Calculate the rate constant Give your numeric answer in the first box and the units of the rate constane in the s...
5 answers
Pt) Let X = {1,2,3,4,5,6,7,8 and consider the functions f: X X and g: X X defined by the following tables d#dddt ~dddd Complete the table defining the function g o f:X - X. ~oxHxhu dsdid Enter your answer as list of numbers separated by commas in the same order as you would place them in the bottom row of the table
pt) Let X = {1,2,3,4,5,6,7,8 and consider the functions f: X X and g: X X defined by the following tables d#dddt ~dddd Complete the table defining the function g o f:X - X. ~oxHxhu dsdid Enter your answer as list of numbers separated by commas in the same order as you would place them in the bottom ...
5 answers
Lut E,DCIR" Be tw nonemptd Scts Whene D is closed and CanVrX Shol that [ € D {faJ mly if tbeir upport Ructisns Ge und 60 satistk 6e(r) 4 Gd(*) + xe |Rn Suf 5 47,J > 3 Je p} i.e 65 =
Lut E,DCIR" Be tw nonemptd Scts Whene D is closed and CanVrX Shol that [ € D {faJ mly if tbeir upport Ructisns Ge und 60 satistk 6e(r) 4 Gd(*) + xe |Rn Suf 5 47,J > 3 Je p} i.e 65 =...
5 answers
5. Compute the Variance and Standard Deviation of a sample of data: 7,6,2,5.
5. Compute the Variance and Standard Deviation of a sample of data: 7,6,2,5....
5 answers
Find the effective rate 0l interest corresponding lo Ihe following nominal rale ol inlerest 3% compounded semiannually The elfeclive rale IS (Round to (he nearesi hundredlh as needed )
Find the effective rate 0l interest corresponding lo Ihe following nominal rale ol inlerest 3% compounded semiannually The elfeclive rale IS (Round to (he nearesi hundredlh as needed )...
5 answers
In order to increase the kinetic energy of ejected photoelectrons, there should be an increase in(a) intensity of radiation(b) wavelength of radiation(c) frequency of radiation(d) both wavelength and intensity of radiation
In order to increase the kinetic energy of ejected photoelectrons, there should be an increase in (a) intensity of radiation (b) wavelength of radiation (c) frequency of radiation (d) both wavelength and intensity of radiation...
5 answers
Consider the the initial value problem TC +y dr + "ler"+y? +1) dy = 0 y(0) = 0Is this differential equation is exact If no find the integrating factor(b) Solve the initial value problem_
Consider the the initial value problem TC +y dr + "ler"+y? +1) dy = 0 y(0) = 0 Is this differential equation is exact If no find the integrating factor (b) Solve the initial value problem_...
1 answers
Calculate the mole fraction of solute in the following aqueous solutions: (a) $21.7 \% \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},$ by mass; (b) $0.684 \mathrm{mol} \mathrm{kg}^{-1} \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}$ (urea).
Calculate the mole fraction of solute in the following aqueous solutions: (a) $21.7 \% \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},$ by mass; (b) $0.684 \mathrm{mol} \mathrm{kg}^{-1} \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}$ (urea)....
5 answers
MEASUREMENT AND TRIANGLES Consider the triangles below:LEVEL:Explain why the two triangles are similar:Determine the lengths of missing sides xandy:10,6
MEASUREMENT AND TRIANGLES Consider the triangles below: LEVEL: Explain why the two triangles are similar: Determine the lengths of missing sides xandy: 10,6...
5 answers
Explain why Z54 is isomoprhic to Zz7 X Zzo(b) Compute (15,12) + (20,10) in 227 1L2o:Find the order of (18,6) in Zz7 Zzo:Find all abelian groups of order 540, up to isomorphism_
Explain why Z54 is isomoprhic to Zz7 X Zzo (b) Compute (15,12) + (20,10) in 227 1L2o: Find the order of (18,6) in Zz7 Zzo: Find all abelian groups of order 540, up to isomorphism_...
5 answers
Not Shdn 2.32 252)2 4ce G6 _(2..54 Whal D 2.3,5 2.3,52 23 3,52 N Sn~ 5
Not Shdn 2.32 252)2 4ce G6 _(2..54 Whal D 2.3,5 2.3,52 23 3,52 N Sn~ 5...
5 answers
Lagrange Multipliers: You are in charge of erecting a radio telescope on a newly discovered plant To minimize interference, you want to place it where the magnetic field of the planet is the weakest The planet is spherical, with a radius of 6 units. Based on a coordinate system whose origin is at the center of the planet, the strength of the magnetic field is given by M(x,V,2) =6x-v+xz+60 Where should you locate the radio telescope?
Lagrange Multipliers: You are in charge of erecting a radio telescope on a newly discovered plant To minimize interference, you want to place it where the magnetic field of the planet is the weakest The planet is spherical, with a radius of 6 units. Based on a coordinate system whose origin is at th...
5 answers
(sluz 1J* 105 M 1 QUESTION } of the (uq) + Sn(s) equilibrium - E"cell constant at 25"€ for the 0.62 vIncrease oic Increase (ne Increase the 81 QUESTION 4 1 ass V vonenuajuoj OrH" of Hz from 0.50 1 1 the concentration of Co2* from 0.010 Mto 0.40 M U atm) Incrcase (ht voitage Irom 0.010 t0 Q.OSO M 1,.0 atmn of the J7) Jiveair9 Ruinoildi
(sluz 1J* 105 M 1 QUESTION } of the (uq) + Sn(s) equilibrium - E"cell constant at 25"€ for the 0.62 v Increase oic Increase (ne Increase the 81 QUESTION 4 1 ass V vonenuajuoj OrH" of Hz from 0.50 1 1 the concentration of Co2* from 0.010 Mto 0.40 M U atm) Incrcase (ht voitage Iro...

-- 0.052011--