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Question 62 ptsAn ideal Bas has R 80 ft,Iba /Ibm: R and the gas undergoes nonflow; constant-pressure process from 1000" to 500" determine the work done th...

Question

Question 62 ptsAn ideal Bas has R 80 ft,Iba /Ibm: R and the gas undergoes nonflow; constant-pressure process from 1000" to 500" determine the work done the change In Internal energy; and the change In enthalpy for the process. All answers should be given in Btu/lbm535128,5[8051.5128 6113066HrJAE

Question 6 2 pts An ideal Bas has R 80 ft,Iba /Ibm: R and the gas undergoes nonflow; constant-pressure process from 1000" to 500" determine the work done the change In Internal energy; and the change In enthalpy for the process. All answers should be given in Btu/lbm 535 128,5 [80 51.5 128 6 1130 66 Hr JAE



Answers

An ideal gas has a gas constant $R=0.3 \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K}$ and a constant-volume specific heat $c_{v}=0.7 \mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K} .$ If the gas has a temperature change of $100^{\circ} \mathrm{C},$ choose the correct answer for each of the following: 1. The change in enthalpy is, in $\mathrm{kJ} / \mathrm{kg}$ $(a) 30$ $(b) 70$ $(c) 100$ $(d)$ insufficient information to determine 2. The change in internal energy is, in $\mathrm{kJ} / \mathrm{kg}$ $(a) 30$ $(b) 70$ $(c) 100$ $(d)$ insufficient information to determine 3. The work done is, in $\mathrm{kJ} / \mathrm{kg}$ $(a) 30$ $(b) 70$ $(c) 100$ $(d)$ insufficient information to determine 4. The heat transfer is, in $\mathrm{kJ} / \mathrm{kg}$ $(a) 30$ $(b) 70$ $(c) 100$ (d) insufficient information to determine 5. The change in the pressure-volume product is, in $\mathrm{kJ} / \mathrm{kg}$ $(a) 30$ (b) 70 $(c) 100$ (d) insufficient information to determine

Four per day in an isil thermal process involving an ideal gas. The work done on the gas w would be equal in the negative work in the environment. This would be equaling negative and are tee times the natural log of the final volume divided by the initial volume. And this is again I so thermal process with an ideal gas from this, when the temperature is constant, however, the ideal gas law is then pressure initial volume, initial equaling pressure, final volume, final and this is equaling anarchy when the temperature is constant and so we we we can rewrite the work done on the gas. This would be equal in the negative initial pressure initial volume multiplied by the natural log of the final volume divided by the initial volume. So this would be equaling negative 10 to the third. Pascal's multiplied by 0.500 square rather cubic meters, multiplied by the natural log of 1.25 cubic meters, divided by again 0.500 cubic meters, and we find that the work done is then equaling negative 4.58 times 10 to the fourth jewels. The fact that this is negative means that the gas is doing work on the environment. No, for part B, um, we have simply the first law of thermodynamics with a change in the internal energy is equaling the work minus rather the work, plus the heat transfer, plus the work, My apologies. And so they heat the heat transfer in this thermal isil thermal expansion. We could say Q would be equaling the change in the internal energy minus the work done. And here it's isil thermal expansion. So the property of a nice oh, thermal expansion, any isil thermal process. The change in the internal energy is gonna be zero. And so this would be equaling negative negative four point 58 times 10 to the fourth Jules. And this is giving us 4.58 times turn to the fourth jewels. So positive. So he here work is being done on the environment. Therefore, work is being done on the environment. Therefore, heat is being he is entering the system. Thermal energy is being added to the system. Uh, given that again, this is a nice so thermal process and for part C ah, we can immediately know again the change in the internal energy is zero Jules, and this is again for any I so thermal process. That is the end of the solution. Thank you for watching.

We have to find the value of internal energy solution. For first part the bargain is given that David W. That is five. Do so, pollution is dead. It gets there's five jewel of Bergen for idealistic process. To process the angels ideas. I think. Then Delta you should be zero for idealistic process. So now Delta U. Is equal to delta. Two minus delta develop from first a lot. Now Delta you should be Jiro minus five jewels. So the internal energy should be -5. You're And the next one is you. For also a geometric process idea, particularly process Delta. You should be zero and the work done. Agent system, work done. Imagine a guest That is Delta W. is equal to 80 June. This is also a negative value. Just bergen on a system. So use thermodynamics law. That is the entire U. Is equal to the enter q minus delta W. So this is the first law of thermodynamics. First law of thermodynamics. So now Delta U. Is equal to zero minus minus 80 jewels. So this is the Delta. You should be 80 jewels.

So here we have some givens. The the final pressure is going to be half of the initial pressure, and we have rigid walls throughout this entire process, and we know that. Cue the amount of heat leaving the system would be negative for hundred and sixty five killed. Jules. We know that rigid walls signified that Delta V is going to be zero, so there's no change in volume. So for part A when it's asking for the amount of work, work can be defined as the pressure. Time's a changing volume because the change in volume A zero that means that zero jewels of work you're going to be done in this process for Part B. They're asking for the change in internal energy. So Delta you is going to be equal to Q minus. W. We know that w is going to be zero. So essentially delta you. The change in internal energy would simply be equals to the amount of heat that left to the system in this case, negative four hundred and sixty five killers. Jules. So this would be the change in internal energy for this process. And of course, the work here is going to be equal to zero. Jules, that's the end of the solution. Thank you for watching

Silver party. The work done is gonna be equaling the negative pressure. Time to change and volume. This is gonna be equaling two negative 1.50 times 10 to the fifth. Pascal's multiplied by 0.500 cubic meters, minus 1.25 cubic meters. And so the work done is gonna be equaling 21.13 times 10 to the fifth. Jules, this would be our final answer for party four carp be. We know that the change in the internal energy would be equaling the number of most times the moler. He capacity of a constant volume times the change in temperature. We have a monotone it gas so we can say that our constant air Mueller he capacity at a constant volume would be equaling the number of degrees of Freedom forum on atomic grass. Three degrees of freedom multiplied by the ideal gas constant are divided by two. And so we know that for the ideal gas law applied to a constant pressure process, the number of moles times the change in temperature would be equaling the pressure times the change in volume divided by are the ideal gas constant And so our change in our internal energy would be equaling the Moeller he capacity three are over two multiplied by the pressure times the change in volume divided by our and this is giving us 3/2 times the pressure times a change in volume. And so our change in our internal energy would be three halves times 1.50 times 10 to the fifth past scowls multiplied by 0.500 minus 1.25 units cubic meters. And this is giving us negative 1.69 times 10 to the fifth. Jules. So we this would be our answer for our change in our internal energy for part B four parts. See, we're going to use the first law of thermodynamics. Where here The change in the internal energy would be equal to put heat plus the work. So the heat would be equaling the change in the internal energy minus the work. And this would be equaling negative 1.69 times 10 to the fifth, Jules minus 1.13 times 10 to the fifth Jules. And this is giving us negative 2.82 talk weather recon do New line Negative. 2.82 times 10 to the fifth jewels. So this would be our answer for part C. And finally for party, we're We know our initial temperature is 425 Calvin. So we're trying to find our final temperature. We know PV initial equals and our tea and initial P V Final equals and r t final. We're going to divide these two equations and the spine that the final temperature is equaling the initial temperature multiplied by the final volume divided by the initial volume. So this would be equaling 425 Calvin multiplied by 0.500 cubic meters, divided by 1.25 cubic meters, and we find that the final temperature is going to be approximately 170 Kelvin. So we have to round two. This would we're rounding to three significant figures. So one approximately 170 Calvin would be our final temperature for part D. That is the end of the solution. Thank you for watching


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