Question
LiBt Is soluble W Matn Dul HE_Bri nal Anwvci quostion: $-d below: Youae Aiven solld mxiurc LiBr and Hg_Brz You jud Aaici aart Ulc #cp-ntion what Is thi; procos: € lled?DecinbaionFitration 31 EvaporitionEachomAltcr MUding Watct; YOU cnrelully pour 0l eho supernlint liquld The process / Cllled Dec IrttionFitelionEFUatUIExtractionAllet fltecing vour mlxturc;, which mixlure camponent will huve Oeen trapped ty (hve Olter Papcr?Wlit would vou do t0 obtain dry: separAled mixture cornanents?
LiBt Is soluble W Matn Dul HE_Bri nal Anwvci quostion: $-d below: Youae Aiven solld mxiurc LiBr and Hg_Brz You jud Aaici aart Ulc #cp-ntion what Is thi; procos: € lled? Decinbaion Fitration 31 Evaporition Eachom Altcr MUding Watct; YOU cnrelully pour 0l eho supernlint liquld The process / Cllled Dec Irttion Fitelion EFUatUI Extraction Allet fltecing vour mlxturc;, which mixlure camponent will huve Oeen trapped ty (hve Olter Papcr? Wlit would vou do t0 obtain dry: separAled mixture cornanents?
Answers
Selcct the correcr srarcment $(s)$ (a) BaSO $_{4}$ is soluble in water. (b) $\mathrm{Ba}(\mathrm{O} \|)_{2}$ is soluble in warer. (c) $\mathrm{MgSO}_{i}$ is soluble in warcr. (d) $\mathrm{CaF}_{2}$ is soluble in water.
In this problem, the nature of the compound age. The nature of the compound E chromium three cell fate chromium three self fate, e t. J, green colored water, solid walls of stance, water soluble substance. So according to the option, according to the option option siege, correct here. Option C. H. Correct answer for this problem.
So here. As for the given question, let us right. The chemical the extent the first one will be L three, L C N three. Yes. B. And it's four words. This will give product luohu, all three less three and S four Seal. No, LOH three. This will react and it's four poet and we'll give a product of this. No, really. There is no reaction in between these two. No LCL tree will react with EPNA three and it will be very productive the the ages here plus Ln 03 Hole three. And this is the white participate. This is by basically so it is a fact that the eco solution of an organic compound is so this is the required in organic. This is at and obscenity is correct actually be L. C.
To classify whether a compound is water soluble or not. We need to follow the rule of having five or fewer carbons per total oxygen and nitrogen count. So if we look at Diable either a very common organic solvent, it has one, two, three, four carbons and one oxygen, meaning that this is potentially water soluble. Less than five carbons per that one oxygen and it is slightly miss a bowl with water. One, two, three, four, five This is pen Tane. It doesn't have any oxygen or nitrogen Sze. Therefore, this is really not soluble at all in water final compound here This Amine has one, two, three, four, five, six, seven, eight nine ten eleven twelve carbons per one Nitrogen Eso This really is not going to be water soluble either, just following this rule.
In this problem I am writing the reaction for. So just look at it carefully. The U. S. 1/4 Into five page 2. When heated at 110° integrated. It will change in to see us a four As to percentage of lost water here is equal tool Called by five multiplication 100 which is equal to 80%. Now I can write DDX an edge to see us so forth. Plus four K. I will give eight K two S. +04 Plus c. U two i 2 plus I too. In further reaction I can write see us of full Plus two KCN. We're changing to c. u. CN two plus. Get us a fall and to see you CN hold to we're changing to see you too. CN hold two plus c. n. All too. Now the final reaction can be written ahead. See You too. CN All 2-plus 6 K C. N. Will give who get to the see you C. N. Food to option C. It corrected.