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Reprexentation (0) for pronane Representations Snowsthe carbons all in straight no and (c) chow the curbons (orming atructure the molecule IQ0 angle. Ia the actual ...

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Reprexentation (0) for pronane Representations Snowsthe carbons all in straight no and (c) chow the curbons (orming atructure the molecule IQ0 angle. Ia the actual represented by your model in either of these Tugemente What _ the uctual angle lormed by the Lhree trhung" Knom _ (Iyou dun"t look back at question #14)Dnt LlLDI Btructura larmulu thathave different names chloropropane wnero one of propane'8 hydrogens replaced by chlorine. Next to the structural formulas Ininm thc compo

Reprexentation (0) for pronane Representations Snowsthe carbons all in straight no and (c) chow the curbons (orming atructure the molecule IQ0 angle. Ia the actual represented by your model in either of these Tugemente What _ the uctual angle lormed by the Lhree trhung" Knom _ (Iyou dun"t look back at question #14) Dnt LlLDI Btructura larmulu thathave different names chloropropane wnero one of propane'8 hydrogens replaced by chlorine. Next to the structural formulas Ininm thc compounds 3 H CEh Compounds that have different looking structurc and different name have the gamC lecular formula are called ;tructural jcnmera. How many atructural isomera are there for chloropropane? On the following full structural formula put circles uround ull the equivalent hydrogens of one kind, squares around all the equivalent hydrogens of another kind, How mun kindi of equivalent hydrogens are thcre propane?



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When 2-bromo-3,3-dimethylbutane is treated with $K^{+-}OC(CH_3)_3$, a single product $\textbf{T}$ having molecular formula $C_6H_{12}$ is formed. When 3,3-dimethyl-2-butanol is treated with $H_2S0_4$, the major product $\textbf{U}$ has the same molecular formula. Given the following $^1H$ NMR data, what are the structures of $\textbf{T}$ and $\textbf{U}$? Explain in detail the splitting patterns observed for the three split signals in $\textbf{T}$. $^1H$ NMR of $\textbf{T}$: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, $J = 10$, 1.7 Hz), 4.93 (doublet of doublets, 1 H, $J = 18$, 1.7 Hz), and 5.83 (doublet of doublets, 1 H, J = 18, 10 Hz) ppm 1$^H$ NMR of $\textbf{U}$: 1.60 (singlet) ppm

Let's examine the differences and similarities of the final and Tito forms of acetyl acetone. So first off is the final form and the key to form residence. And what is that by that is really what's changed. First we start with something that kind of looks like this group, and we end with this you. So what happened? Well, what happened was this hydrogen got taken by this lone pair, or the electrons from the stubble bond took that hydrogen, and this hydrogen gave those electrons to make a double bond, as shown right here. Is that residence? As a matter of fact, it's not exactly residence. It works similar to residents, but it's not the movement of solely electrons. It's also the movement of Adams and and electrons, and this is something that is specifically called Tato Merisel to Taameri ism, and this works with een ALS and enemies. So, like instead of an oxygen, if it was a nitrogen and mold, it works in those situations where you have a double bond adjacent to an alcohol or anami. Really Electra Negative Adams, next to an al cane, is not a very stable form, and it would want nothing more than to get rid of that for so we never really see an eternal form in nature. We only see a key total for because of that. Now let's talk about hybridization. What would the hybridization of each Adam be? Well, this carbon forms four bonds, so that's SP three. This carbon forms three bonds. That's SP to this oxygen has two lone pairs and to bonds, that is S P three. This carbon makes three bonds SP to this carbon makes three bones SP to the oxygen makes one bond and two lone pairs. So SB two on this carbon is S p two and are key to form. Well, this Communist the exact same as the previous example. So it's as p three. This carbon still makes him those three bonds sp two. This carbon makes three or four bonds. So now it's sp three. The oxygen in the Carbonell is that speak to this carbon has Pete too. This oxygen would be sp two, and this carbon is S p 30 landholders. This carbon was also SP three. Okay, so that is going to be the hybridization of each Adam. And if you know this. What changes in the hybridization is well, this Adam becomes goes from SP two s p three and this oxygen goes from SP three toe sp two and those are the two differences of there. Which is also why it's out residents because residents is three adjacent SP two Adams and we're starting with two SP twos and then SP three going to to SP twos and NSP three. So it's not residents because those electrons are not in the p orbital entirely. If we had to draw residents structures for the ion, what we would have is well, if it reacts with an eye on or in an ion are an O. H group. It would react to form this compound which looks very similar to what we had before. Except now it looks like there's just some deep rogue nation somewhere, right? And the way we can know this is well, we have a ch three group bonded to a C bonded to an O, bonded to another, see, So either this is a double bond, which is probably the case, and we bonded to a C, which is fun toe H, which is bonded to and there's bone into another. See Oh, C H three. So really, we have a negative here, which is not really a good thing to have. And if we had a negative charge in a carbon eel group, what happened is well, residents, because now that is an SP to hybridize orbital. Because negative charges always exist in the P orbital. It's now we can't residence. So one possible structure would be donating those electrons to this l king. This carbon donates its electrons where I'm sorry this out this negative charge would donate its electrons to those carbon so it would make it Carbonell and this oxygen would go up. And we get one resident structure which looks something like I'm went to draw the online structures or I'll just draw was right amount. So we'd have one Rosen structure as this molecule and alternatively, well, it could have gone the opposite direction, which is the same way. So really, the only alternative resident structure is if it went the same or the opposite direction and made this resident structure. Then we had this molecule. So those are three different residents structures, and another question that could arise is icis trans acceleration possible between, you know and Tito well, in the key to group, we don't have an out keep so right off the bat, we can say no, says Trans, is not possible for that. For the final group, it's not that obvious. And the reason is there are two bulky groups. We have a CH three group and a C O H group on one side of an out key, and on the other side of the arcane we have a hydrogen and then a key tone group, so that's perfectly fine. But the side that has two groups, we don't know what citizen Trans is. In fact, when it comes to Al Keane's, when you have more than two groups on one side of an Al Kane, there's a whole different naming system. We can use this trans I summers afford it. There's an entirely different naming system for stereo centers and that's E and Z. But we don't need to worry about that. So therefore, says Trans I summaries. I I saw more ism is not possible. What about polarity? Would the final form bi polar? Because the key toe for Miss Symmetrical it is a symmetrical molecule. Well, not entirely, but its polar in the sense that it'll pull electrons that direction. But what about Dean Elgar? Is that polar? Well, yes, because you have oxygen's on one side. It's gonna pull those electrons right. It is a polar molecule. But where do the positive and negative charges lie? Which oxygen is more native? And for that, let's draw this molecule again. Take a look at this. You know, for what? Where is a lecture? Negativity going to pull those electrons? It's something obvious, but it's gonna pull to this oxygen more than it pulls to this oxygen there still in that negative there. But this net negative is much, much bigger, and that's because of the double bond. The double bomb is kind of like a extra little pull kind of thing. It's like if you're playing tug of war and the rest of the molecule is playing tug of war with one hand. But this oxygen is playing with two hands, so it's grabbing on with an extra like pull so it pulls those electrons even stronger. So this has the biggest neck negative, but this oxygen still has a negative charge and this hydrogen also gives electrons to it. But where's the positives? And the biggest positive is going to be right around here, right at the top of the molecule. It's going to pull or push, or it's not exactly going to push or pull. It's just going to have those electrons and drained from it, and it will lead to that kind of di poll moment.

Hi every month. So we'll brain here element then percentage than atomic ratio, then simplest atomic ratio I and lashed all numbers. So 11 days you can say carbon. So percentages 45 58 Atomic ratio can be gullibility by dividing percentage competition Develop atomic mass. So 40 point p eight a month. 12 Nothing but 3.38. Okay, the next seventies intrusion that is two point, not four. So two point not for divided by one will get two point not four. Then my approach and 9.46. You had a by 14 will get 140.67 then chlorine. Yeah, 47 point 92. You are directed to free point For you you get 1.30 for you smallest atomic ratio 0.67. And that's why 3.38 upon 0.67. He lives in place to atomic ratio by my nod for and two point not for upon point. 67 will get three point 044 then 0.67 upon 0.67 11.30 for you upon 0.67. 2.1 for you. So you know point not for this correctly rounded as they for you, then erosion as a three. Then my approaching has one on glory. Nous duke No. Since stings the simplest atomic ratio of simple Eshed atomic that a shelf carbon is too heterogeneous. Took my erogenous to chlorine IANs We can say file is to three is toe one is toe to and therefore the formula of the components the law off the components See for you H green young theory in Seattle from the spectroscopic data 7.66 trip plated Jason 26 holes indicate that the CH, which is coupled toe to ch, actually signal coupling on board the chemical sector at 7.31 Delta 7.66 Bill That shows that you play daisy called to 7.68 cents. Okay. And some 0.31 basic all toe. 7.68 said this indicates the structure as a to six dyke Laura. Very lean. Sure. 26 night. Laurel. Be reading number six. Died Chlor off building on this Fred Ocean. It shows it replayed at 7.66 This is some 0.30 on this. Also, some 0.31 then next Chinese compound. Oh, be, uh, you know, 8.64. That late 8.64. Double edged. A complain constantly is 2.1, I'd said. And eight points. 25 replayed The coupling constant off 2.18 shade indicates that 8.64 It's, uh, contribution towards the nitrogen. Yeah, okay. On. And there is to erosion actors in nitrogen that shows at 8.64 the middle hydrogen shows a 0.20 for you. And therefore, the structure of the compound is three for you Die, Clara. Period in three for you, three for you. Okay, Di chloral period in. Then see struck Cherries. Okay. You know, in a lot of data at 8.17, the build of late complete God Stunt three on 0.38 ST This indicate vision. Algae like coupling. Then a 0.13 again develop late. There is it called nine on day three. It said than some 0.68 doubled up. Played this he called tau 9.38 Said this immigrants to find out Laura building structure for you by chloral period in structure. God, take my night Global period in sculpture. So first of all, when brought the structure look mhm, Yes, Yes. Okay. Yeah. Okay. Right. Do for you. Yes. Um okay. Okay. This Sunday do then the seeds flying. You see? It's who for you Di Gloria building. So this illusion it will send a 0.70. This is the same 0.6 state. This is a 0.23. Thanks.

I think the problem are you having I I entreat They got it. Where? Call it. I'm t toe form and I you know, a survey in a fashion in which growing it's Eric. Terrible boy it is. First, let's see how little doggie I mean aside. One second you're here, e and and way have connected to the responses. Yeah. No, this everyone telecoms. So there's the or, um Do we go from here? Oh. Oh, you don't care no longer here the neutral here. I know because it leads to the council here so that it forms I and we live on. Hmm. Super body. Mm. Can you look bad? So this is at a touch. They should have pocketing dies. I mean, this is still kind of possible talent if you carry on everything else. So this is a formal charge, which right? I know, right? Yeah. You calculate the former charge whether you using the bomb. Them? Uh huh. What we have to do is use a formula. Were formal charges equal to the number of valence electrons. Formal charges equals number off balance electors. Yeah. Minus number of morning returns by two. Number off bonding atones I to oh, minus number off your border. Electro no one wanted it. How did this team, the sectors I and that were born in everyone end infrastructure. You have anyone in two on entry? Oh, it's like right here and develop the count's Yeah, and and with one therapeutical In the first case, the public are indeed Dr A. This is a This is B right in eight. Hello, Eileen. The public art will be zero mhm. You can make you get a little and one zero and to that's one on entry Witness were and we need it equals zero and months. It's minus one and two. That's one on the so that effectively, the anyone carries the partial negative jobs. If you did it in one, Kelly said, Partially ridiculous. Okay. And therefore the I will be getting a factual positing touch. So the polarization off I entry we can consider, as in this direction I helped up plus on n three Delta Miles e. Just look at the mechanism of reaction in which we can write the mechanism and the same question as additional occurs with blooming. See, It's too mhm. It's everyone t It's too. Yeah, This will bomb I Okay. And three. Yeah, that reform. See? Extreme C x two See it? I see it to file the capacity on empty, but the negative Now, the entry attack from the back side that on it opens up here. You know, we're gonna go question CSP c x two c h and three. Yeah, on. See it too. I Yeah, Yeah. Okay. Yeah.

Where is this problem? Were given three compounds 12 and three. We were given the number of model metal compounds formed when a medical group is added to some section of the remaining carbons on this strike or a Benzie. So we know that there's, Ah, a couple different I summers trickle coral, benzene. And so, in order to determine which one's kind of form, he's model metal compounds that might be best to kind of just trial what they might look like and then assigned them the numbers so far for a strike or a benzene, what his first extinct might be to draw all the Koreans on the same side. Another one might be drug two of them on the same side and then placed the last one on this carpet. And then another one might be to spread all the Koreans out across. So in the structure, if we were to add a metal, how many compounds with warm in response? Well, if we were to Adam Ethel to the last one, we can only add it in one place because adding it in other places, it was still generate the same compound. So if we read Adam. Ethel. Only one model metal compound would form from the last one making this, uh, let her I So that we look at the next one. Where can we add methyl groups? Get add one at this junction and have a different compound. We can add one at this junction and have a different compound can. We had one at this junction and have a different compound. The one that we're comparing it against is adding here we can We will have three different ones. So we give it to the three and give it a letter treat and just her. We cannot, um Ethel here, you can add a methyl here, but we can't add it here because it would be the same as adding it to this adjacent one. So it would be let her too.


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