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Q Compite +he lct Iioe" 73 Yp Jypty-102. Corsidef tbe furhan if X<I fc) {6-1 5-Zx if x2| Dozs Nrct 71 fixl exist? If So, Wntt iS IF not UY not?...

Question

Q Compite +he lct Iioe" 73 Yp Jypty-102. Corsidef tbe furhan if X<I fc) {6-1 5-Zx if x2| Dozs Nrct 71 fixl exist? If So, Wntt iS IF not UY not?

Q Compite +he lct Iioe" 73 Yp Jypty-1 02. Corsidef tbe furhan if X<I fc) {6-1 5-Zx if x2| Dozs Nrct 71 fixl exist? If So, Wntt iS IF not UY not?



Answers

If $a<b,$ then $e^{a}<e^{b}$

Yeah, For this problem, we want to first find the second derivative of s with respect to pee. So in this case, P is our variable t is treated as a constant. So to find the second derivative, we need to first find the first derivative. So as prime with respect to pee is going to equal to he times t because we are using the power rule for bringing this exponents down in front. And, um then we're just subtracting the exploded by one. So that's how we get to pee and then t is just are constant. And so the first derivative is two times p times t. But we want to find the second derivative with respect to pee. Hey, and that is just going to equal to t ain't because t is treated just like a constant. So this is the same thing as finding the derivative, for example, of five X, which would just be five. Okay, so the second derivative with respect to P is to t for part B. We want to find the second derivative with respect to t. So this time T is are variable and P is a constant, so the first derivative of s with respect to t it is just going to be p squared. Hey, because, um, tea is just being raised to the first power in our original equation. So if the first derivative with respect to t is just p squared, the second derivative with respect to T is zero because P is a constant. So peace, where would also be a constant and the derivative of a constant is zero? Yes. The second derivative with respect to T would be zero. Yeah.

This is a problem. Number 76 effects is given as X minus one. Hold square. If you drop graph, It looks like a parabola with protects one comma zero and we can say See, this is differential everywhere, including this point. Because at this point, tangent is X equal to zero. So it is? Yeah, terrible everywhere. Thank you so much.

In this problem, I can write the value of Q square is equal to P. R. According to the given question. So from here I can write the value of our is equal to people US. You by two. On further simplification, I can write two. Q Square is equal to be square plus BQ. That is the equation. So from that aggression I can write therefore B squared, jewish squared BQ are in ap are in a P so option is correct. Two option is correct answer. Op's unease, correct answer.

The prediction of existence can mostly be done by using molecular orbital theory. So for molecular orbital theory, the most important part of like the orbital theory for predicting essentially stability is bond order, which is equal to the number of bonding electrons. Mine is the number of anti bonding electrons divided by two. So in this case and this is referring to a balanced life trans. So for helium helium has two valence electrons. And both of those valence electrons are located in the one S orbital. Mhm. Mhm. So for the one s orbital, essentially the atomic orbital is combined to form molecular orbital us. So you have basically sigma bonding and sigma anti bombing. And with helium two plus you only have three valence electron since you lose one electron due to organization. So you have two electrons and bombing or both while you have one electronic anti bonding or goals. So the bond order is equivalent to 2 -1 divided by two which is 1/2. So one half bond order is very very very weak, comparatively speaking. So since even helium two doesn't exist essentially in nature, it's highly implausible that essentially even helium two plus doesn't exist in nature. It's quite implausible that H E two plus will exist in nature, so likely does not exist, and that's it.


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