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StdchioyEiRTIdentifying the limiung rcactant in drawing ol mixtureThe drawing below shoivsmixmntmoleculescarbonhycrogennitrogensulfuroxygcnchlorineSuppose the follo...

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StdchioyEiRTIdentifying the limiung rcactant in drawing ol mixtureThe drawing below shoivsmixmntmoleculescarbonhycrogennitrogensulfuroxygcnchlorineSuppose the following chemlcal reactlon SO_(9)+0_(9) SO;(9)takc place thls mlxture:Ol which FnerniEhnmrnozkincn manA Antn[chcmic FoemudDpMich reactant ar therJcast Initia molestcientical (cmnul:Which rractant / the Mlmiting reactant? Erter iLs chemcal farnula:

StdchioyEiRT Identifying the limiung rcactant in drawing ol mixture The drawing below shoivs mixmnt molecules carbon hycrogen nitrogen sulfur oxygcn chlorine Suppose the following chemlcal reactlon SO_(9)+0_(9) SO;(9) takc place thls mlxture: Ol which Fnerni Ehnm rnozkincn manA Antn[ chcmic Foemud Dp Mich reactant ar ther Jcast Initia molest cientical (cmnul: Which rractant / the Mlmiting reactant? Erter iLs chemcal farnula:



Answers

Draw structures corresponding to the following names: (a) $p$ -Bromophenylacetamide (b) $m$ -Benzoylbenzamide (c) $2,2-$ Dimethylhexanamide (d) Cyclohexyl cyclohexanecarboxylate (e) Ethyl 2-cyclobutenecarboxylate (f) Succinic anhydride

Hello, sir today will be drawing a Lewis structures for different compounds. So let's start with methanol here. So let's count up our valence electrons. So carbon has four valence electrons. Hydrogen has one and therefore room and oxygen has six. So in total, we have 14 valence electrons that can be used in bonding. Now let's take a look at how maney Roelandts Electron each Adam needs, so carbon needs eight hydrogen needs to, and there are four of them and oxygen needs eight. So that's a total of 24 and you'll notice so une z rule to find out how Maney bonds you need is, take how many you need. So check him and you'll have and divide by two. And you see, in this case we need five bonds. So but get drawing. So let's take our carbon and bonded Teoh 23 hydrogen as we can see in the formula. Then we'll bonded toe on oxygen and von find that to the hydrogen. Sort of like how it's written in the formula here and now. You'll notice we have 12345 bonds so that sussmann e bonds as we need and this and everything has a full balance except for the oxygen and doesn't have its octet yet. So we add to lone parents and it has a full octet now. And if it kind of the electrons will see that we have 14 Now, let's go on to our next compound. So carbon has four valence electrons in there, Two of them hydrogen has one valence electron. And there six of, um, and oxygen has six valence electrons. So we have 20 valence electrons. Now, let's take a look of how how many we need in total. So carbon needs eight and there are two of them. Hydrogen needs to, and there six of them and oxygen needs eight. So let's take a look at that. You've got 16 plus 12 is 28 plus another eight is 36. So how many we need so trucked? How maney. We have divide by two and we will see that we need eight bonds. So let's have our carbon, and we're gonna bond it to three hydrogen ins. Then we're gonna bonded to a carbon, and that's gonna have to hide regions wanted to it. I'm gonna bonded to the oxygen and then that the hydrogen sort of the way the formulas written here. Now, if you count of how many bonds of have we have? 12345678 bonds. So we have all the bonds we need. Oxygen doesn't have a full octet, so we just add some long, pure pairs here. And if we count up, all the electrons will see that we have 20 and everything has a full Vaillant. So there we go. Now let's take a look at this compound right here. So let has four valence electrons. Carbon has four and there are eight of them. Hydrogen has one valence electron, and they're 20 evil. So that's a total of 56 electrons. Now let's take a look how many we need. So blood needs eight carbon needs eight and their eight of home and hydrogen needs to in their 20 of them. That's a total of 112 electrons. So now how many? We need truck, how many we have Divide by two, and we will see that we need 28 bonds. So let's get drawing. Let's have led in the middle here because if we look at the formula. It looks like that this group has a four. So therefore of, um So I'm so it kind of seems like letters in the middle and has four branches. So let's have fled in the middle are going to make four branches gonna bonded to a carbon that's gonna be wanted to to hide regions and a carbon does bonded to three high kittens And then we're gonna do it for each branch. And if we count of how many bonds we have 123456789 10 11 12 13 14 15 16 17 18 1920 2122 23 24 25 2016 7 28 So you have all 28 bonds here, And if we went back when with it we went encounter monthly. You should have 56 electrons. So this is the structure. Now let's look at this molecule right here. So the carbon has four valence electrons. Hydrogen has one and there are five of them and nitrogen has five. So that's a total of 14 valence electrons. Now let's take a look at how many we need in total so carbon needs eight hydrogen meets to in there are five of them, and nitrogen needs eight. So that's a total of 26 electrons. So how many we need subtract how many we have. Divide by two, and we will see that we need six bonds. So let's look at our formula. So let's have our carbon here, and we're gonna bind it to three hide regions. And then we're gonna bite it, toe a nitrogen which is bonded to to hide regions. And if we go and count em up, we will see that we have six bonds and you'll notice the nitrogen doesn't have a full locked out yet. So we add to a long pair and you'll see if you can't amount that we have 14 electrons and there's a structure right there. Now let's look at this long molecule. So that's kind of surveillance Electrons. Chlorine has seven and there are two of them. Carbon has four, and there is 1234 of, um, hydrogen has one and their 2468 of, um, then there Sulphur with six. And if we had that it up will get 44 electrons now Let's see how many we need. So chlorine needs eight. They're two of them. Carbon needs eight. Therefore, of, um, hydrogen needs to There are eight of them. Sulphur needs eight and so we'll get 72 electrons. So take how many we need. Subtract how many we have. Divide by two, and we will see that we need 14 bonds. So now let's draw this molecule. So let's follow the way the formulas written so coin, and we're gonna bind it to carbon. There's a hydrogen on top in the hydrogen on bottom and splendid to hide regions. It's also bonded toe a carbon, which is also bonded to to hide regions. And it's also going to be bonded toe a sulphur, which responded to a carbon with two hydrogen, and that's bonded to a carbon with another to hide regions, and that's funded to a coin. And if we count 123456789 10 11 12 13 14 We have 14 bonds, which is how many we needed. Now we make sure everything has a full octet, so we're gonna add three long payers to the coin. We're gonna add to long pairs to the sulfur. And if we count all our electrons up, we should have 44. Now let's go on to the next one. Let's count up our valence electrons. So nitrogen has five valence electrons and there are two of them. Hydrogen has one and they're affordable. Carbon has four and oxygen has six. So 10 plus 4 14 14 plus 4 18 plus 6 24 electrons. And now let's see how many we need in total. So nitrogen needs eight and there two of them hydrogen needs to. And there are for home. Carbon needs eight and oxygen needs eight. So 16 plus 8 24 plus another 8 32 plus another 8 40 So how many we need? Subtract Hominy. We have divided by two and we will see that we need a bonds. So if we see we see that this nitrogen into hydrogen group there's a to so that kind of implies that the other branches and they're connected to the carbon oxygen group. So how about we have carbon in the middle? It's gonna be bonded to the oxygen and the two nitrogen ins and the nitrogen zehr gonna be bonded toe hide to the two hydrogen, four hydrogen. So if we counted up, we've got 1234567 Bonds. But we need eight. And we need to think about where we want a double bond to go. And I'm gonna tell you right now you should put it on the oxygen, and I'm going to explain why. So if we put the Delavan on the oxygen and we put too long pairs here, this oxygen has four electrons and lone pairs and four in bonds. Now let's say that it owns half of the electrons in the bonds and all of the ones that are in the lone pairs. Then it has six electrons and total. It started off with six. So it's formal charge is zero. Carbon is also zero. So this is the configuration where all of the formal charges or zero, which is what you want. And this isn't complete quite yet. So nitrogen needs a full Loctite. So we're gonna add two lone pairs here. Well, one for each nitrogen. And if we can up our election Trans, we should have 24. Now, let's look at this compound right here. So it's con up our electron valence electrons. So nitrogen has five. Hydrogen has one and there are five of home. Carbon has four and they're two of, um, and oxygen has six, and there two of them. So add it all together, and that's 30 electrons. Now let's see how many we need. So nitrogen needs eight hydrogen needs to on their five old carbon needs. Eight, and there are two of them. And, uh, oxygen needs eight and they're tool. Um, so that's a total off 50 electrons. So how many we need subtract how many we have divide by two, you will see that we need 10 bonds. And now let's take a look at this so we'll have a nitrogen and spawned it to hide regions. And it's also bonded toe a carbon that's bonded to to hide regions and another carbon. And if you you some of you might be familiar with acetic acid. So when you see the c 00 h group, you probably want to think, Ah, carb, oxalic acid. So basically, think of a structure like this. The point is, show well why we need this double bond in the second, so you've got 123456789 10. So if we have thes this double bond here, we will get the 10 bonds that we need. Now, let's add up. The Valence Electron rolled the lone pairs. So everything has a full octet, All full Vaillant, and you'll see I chose the double bond to be on this oxygen right here cause it will have a formal charge of zero. And as we can see, everything is happy. Everything has a full valence and the Sylvia

Starting with part A. We're gonna draw the loose structure of methanol so we can see from, uh, this formula. We will have a carbon bonded to three hydrogen, and that carbon has bonded to an oxygen which is bonded to hydrogen. And then we will put two lone pairs on her oxygen to complete its octet. Next we have ethanol. You will have our first carbon bonded to three. Hydrogen got carbon is blinded to another carbon which is bonded to two hydrogen. And then we have our own. Each groups that carbon has brought it to an oxygen which is willing to a hydrogen and again well at two lone pairs under oxygen for park si, we have tetra ethyl lead. So we will have led as our central often. And what we can seem by this is we will have four, um, apple chains for So our lead is wanted to re carbon, which is bonded to two hydrogen and that carbon is bonded. 23 hydrogen to move it down. So let us our central Adam and then has to Ethel chains has four ankle chains. So each Jane consists of two carbons. I need to those carbon is attached to hide regions which completed sock test for party. We have methylene means, so you'll have a first carbon bonded to three hydrogen. That carbon is bumped to the next Gen. We just wanted to to hide regions. And then we'll add a lone pair on the nitrogen with the rest of our electrons and to complete the architect of the nitrogen for mustard gas. We will have her first carbon wanted to a Corinne and two hydrogen. But carbon is boland it to another carbon which is born into too high Christians, and you will have a sulfur in the middle and then two more carbons on the right. And each of those carbons has bonded to two hydrogen and our last carbon has brought it to a chlorine. Then they will go in and add lone pairs to our careens and our sulfur to complete their objects part up. You'll have a central carbon which is bonded to to and each two groups, so our nitrogen spotted to hide regions. Then we will have a carbon oxygen double bond, and then we will have one lone pair on each Mycogen and then to impairs on our oxygen. We're part chief. You will have hydrogen bonded to hydrogen. Um, androgynous, bonded to carbon, which has bought it's to hide regions and we'll have a car back. Silly gossip group. We have carbon little bonded to oxygen and then a hydroxyl group. Then we can go in and Advil in pairs to an insurgent and our oxygen's.

Guys is in problem. One of five Chapter two from the molecular structure. Shouldn't hear identified. The one that corresponds to each of the following species. So a chlorine gas. So chlorine remembers that die atomic? I make molecule. Well, also, it's gonna BCL two. So this is our 1st 1 And I'll just represent this by a be propane. Propane. Remember pro that prefix music. You have three carbons. Arbenz, this a hydrocarbon. So you only have hydrants and carbons, so you shouldn't see black and white spheres. So 123 And you only see black and white here. So this is your propane. Be next. We're nitrates. Nitrate has nitrogen of these three, this is the only one that is nitrogen. So that's nitrates? No. So for trackside, I mean your look of herself. Uh, Mollie, get so far in it. That's this one D and then met metal chlorate, right? So, by process elimination, this is e

So in this question you ask draw a molecular level diagram for the reaction in which sulfur. Yeah, I exaggerated the molecular oxygen to form sulfur draft site. Be sure to write and balance the equation first. Use the color. Yeah. Mhm. Child in section 2.3. to distinguish the items from each other. So no, will draw sulfur atom. Mhm. Yeah. Yes. Sal ferrara to. Uh huh. Mhm. Mhm. So there's some blue and make it even if so far. Yeah. Lunch. Yes. Mhm. Yeah. Oh, so far man. You know black and like it. So this black indicate mhm oxygen. Mhm. Yeah. Mhm. Susan. So do is sort plus. Mhm oxygen molecule. Yeah. Mhm. This is Yeah, sure. Mm oxygen while naked gifts two molecules. So three. Right. So well the second we'll drop luke and uh Yeah. Yes. Okay. Right. Mhm. This is so alfa bank when you drive here. Okay. Action action double bond. Yeah. Uh huh. Okay. You thought Yeah. So far. Yes. Oh. Mhm. Yeah, sure. Mhm mm. So blue color, Yeah, represent so far victims, right? Like replace Obama seizure night. Right? Mhm. Right. Uh huh. Mr mhm. Yeah. Thank you. Mhm. You bang, you know, cream 3% born. Yeah, between the Salle foreign obsession. But mhm. Yes, jesus. So yeah, this is what a diagram. Thanks a lot.


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