5

T-Mobile LTE8.43 AM4 0 98%written HW #6 Fall:PHY205} Froblem solving Homework # 6Due November 07,start of lectureWrite your name at the top of each page of your hom...

Question

T-Mobile LTE8.43 AM4 0 98%written HW #6 Fall:PHY205} Froblem solving Homework # 6Due November 07,start of lectureWrite your name at the top of each page of your homework; pages may be separated for Erading: Make sure your homework i= legible and show all of your work:Asignmentb Eproblems3 * 10' 8 2* 10'TX0V(cm )Two moles of 4 monatomic Ideal g4s are enclosed in cylinder by movable piston: The gas is taken through the thermodynamic cycle shown in the figure above; The piston has crOSS-s

T-Mobile LTE 8.43 AM 4 0 98% written HW #6 Fall: PHY205} Froblem solving Homework # 6 Due November 07,start of lecture Write your name at the top of each page of your homework; pages may be separated for Erading: Make sure your homework i= legible and show all of your work: Asignmentb Eproblems 3 * 10' 8 2* 10' TX0 V(cm ) Two moles of 4 monatomic Ideal g4s are enclosed in cylinder by movable piston: The gas is taken through the thermodynamic cycle shown in the figure above; The piston has crOSS-scclional arca 0f 2 10-} m- (A) Calculate the force that the gas cxens on the piston in state A_ Calculate the temperature of the g1s in state B. Predict qualitatively how the tempcratun: of the gus changes 1s it is laken from state state B Justify your prediction in terms of the motion of the 2 particles - within the cylinder. (D) Predict qualitatively how the temperature 0f the gas changes &s it is taken from state B to state €. Justify your prediction in tcrms ofthe motion of the gas particles within the cylinder. (E) Determine the change in total kinctic encrgy ofthe g4s atoms #s the gas is taken directly from stale C t0 stale



Answers

An ideal diatomic gas, in a cylinder with a movable piston, undergoes the rectangular cyclic process shown in Figure $1.10(\mathrm{b}) .$ Assume that the temperature is always such that rotational degrees of freedom are active, but vibrational modes are "frozen out." Also assume that the only type of work done on the gas is quasistatic compression-expansion work. (a) For each of the four steps $A$ through $D$, compute the work done on the gas, the heat added to the gas, and the change in the energy content of the gas. Express all answers in terms of $P_{1}, P_{2}, V_{1},$ and $V_{2}$. (Hint: Compute $\Delta U$ before $Q,$ using the ideal gas law and the equipartition theorem.) (b) Describe in words what is physically being done during each of the four steps; for example, during step $A$, heat is added to the gas (from an external flame or something) while the piston is held fixed. (c) Compute the net work done on the gas, the net heat added to the gas, and the net change in the energy of the gas during the entire cycle. Are the results as you expected? Explain briefly.

In this problem. We're gonna talk about the first law there one day. So what we need to remember is that the first law of thermodynamics tells us that delta you the variation in internal energy you have a gas is equal to the heat provided to the gas minus the work done by the gas. And it's important to remember this convention because if the heat were provided from the gas to the system that the heat B negative and the work if it was done on the gas, then it would be negative as well. Okay, Eso What we have in a problem are several processes that ah, gas under goals. Initially, the yes has a pressure of one ATM and a volume off three letters and it expanded constant pressure at 25 liters. Then, um, it's pressure increases that cost of volume 238 PM Then I X pressure decreases linearly with the volume to chew it him and three letters. And finally, the gas loses pressure at constant volume to 1. 80 m and three letters okay, and are going question a Mr. There are a P V diagrams off our gas of our process, actually. So here for P. We have one ATM to ATM three ATM, and the volume is three letters. Actually, I'm sorry. Um, yeah. Three letters and five letters. So initially, the initial boy is this one here. Okay, this point, then the gas expense at constant pressure to this point here, then it, um, keeps the pressure the volume constant and expense to 3. 80 m expense, Actually not expensive. Um increases pressure to three ATM. Then the pressure decreases linearly with the volume to, uh to ATM and the volume 23 letters. Finally, the pressure decreases to the original value off. Pressure and volume are at constant volume. So this is our graph and in question. Do we have to calculate how much heat flowed into the system or out of the system during this process? Well, um, we know the Delta U That is a variation in internal energy is zero. And why do we know that the internal energy of a system depends on Lee on it's point in the PVT space, meaning that even that P V and T are the same? Then you is gonna be the same because you depends. Only on P VNT. So if the guess returns to its original state, then the variation in internal energy must be zoo. So we know that zero the relation internal energy is in which a Q minus w so Q is it w So if we calculate the work done by the gas, um, we can find the heat. Now let's calculate what is the area of the area of this process here, and we know that w is the integral B d view many that it's the area under the graph in this area here, Um, and we can calculate this area in order to calculate w eso the area, and we call it a notice. Actually, that, uh, that will you is gonna be minus the area. And there's a reason for that. Um, notice that the process is actually in the counter clockwise direction. So the work for each for this process here for the process that where p decreases linearly with V Um, it's negative. The work is gonna be negative. Eso For that reason, we can say that the work is minus the area, since the area is an absolute value. Okay, so the area is one, actually one ATM because notice that we're trying to calculate the area off this trapezoid here. So it's one ATM to a T M offsides, and the base is equal to, uh, two leaders. So it's 1 80 m plus two HTM divided by two times two letters, and I'm going to transform this into, um as I into the international system. So we have 1.5 80 m, which 1.5 and 1.41 time sent to the fifth skulls times two leaders. So that's two times sent to the minus three cubic meters. So the area is equal to, um, there is able to 303 Jules. Meeting of the work is minus three or three usually, and for that reason Q is minus three or three hues with the heat is negative. Theatric Jews. Any other heat flows out off the system out of the guests, which concludes our accident

Well in this problem, we consider a chamber off unknown volume and an unknown amount of fighting ladies. It temperature T is equal to 300. Calvin, we teach a cylinder with movable piston, which we moved in our steps off 50 Milly later. Every time we moved the piston, the pressure in the chamber decreases because we allowed the case to fill a larger volume. When the cylinder is empty, the pressure is 4.3 five times 10 to the power five Newton per meter square Newton, 12 m square. Well, we use the ideal guest law in the form we not less volume off cylinder is equal to N. R. T Divided by B here we noticed the volume of the chamber. We see that this resembles the equation of a straight line. An equation of straight line is wise equal to hey, explicit B. This is the equation off the line here. By comparison, why is equal to volume of cylinder right and A is equal to and I, p and X is equal to one divided by B and B is equal to we Not right now. Using linear regression, we obtain the equation. Why is equal to why is equal to a times X lis be I'm sorry. So it's wise equal to we just like in numbers. So why is equal do? 173 0.73 times X minus 0.4 Right now you form volume are in meter cubed. The volume off the chamber is therefore we not is equal to forward and red 400 million later. And the chamber sorry and the number of Moses in R T is equal to a right and from here and is equal to a divided by our times. T, which is equal to 173.73 divided by our, which is 8.314 Multiply by 300 Galvin. So anything will do and is equal to well and is equal to zero point 07 more

Okay, here is our piston gas system. Now A asks what announced you want to use looking this problem Well, considering they're selling with a weight that's balanced with something that has a resistant force, I would say you want to talents forces. So this is going to be hey, uh, kind of Newton. Second long question. So let's go to part B then and explore. There's thes force equations a little more well can draw our forces in blue. So we know that this mass, the piston as a force and that's a gravitational force rate. So I'm gonna write that g. We also know that our gas has it forced up f p. And we also know that the gas on the outside the piston has 1/4 down on the piston. And that's gonna be FP not remember pressure. There's a force related to pressure. So we have the equation. F p equals F G plus f p. Not now. We can put in values for year. So FP is just will Force is equal to pressure times area f g is just MGI And then again we have pressure not times area. Okay, now we're told that we can assume that thesis ill Inder has a temperature t ah, number of moles end. So it was like the ideal gas law. And we can express our pressure as an r t over V. He also that volume is very the base eight times h. So this pressure becomes an R T over a h so we can put that in our equation import beef. So we have hopes and r t over a h times a is equal to m g plus p not a This able cancel out move stuff around and you should find that and our t over m g plus p not a equal to each.

Sorry, Uh, for this problem, it is quite long. So we have Basically we have four processes. The 1st 1 is, uh we have the initial pressure in the initial podium and the 1st 1 is the pressure is constant. Increase the volume, then the voting is constant. Increase the pressure. Next decrease the pressure really nerdy. And the vote him also decrease. Ah, the last step is we, Ah, last episode we decreased level degrees the pressure and to keep the voting constant. So also Ah, the idea guys equations no apply with much accuracy. So anyway, uh, let's look at the people diagram. Firstly, So this is a p misery Initially support. This is the initial point. And the unit for this one's a t m. The unit for the V is a later. So the initial point for P is one. There's the one. Okay. And for B is three. This is three. So for the first step, we increased the volume, but keep the p as constant just whores online, and then we increase the p I. Q b is constant. Uh, what the pressure comes to. Yeah, so then it's just a vertical line going up. Ah, the final state. That at this point, is, uh, you see, it's a 25 So this is a five, and we increased Ah, boarding. And we'll know that we use the pressure, too. Three. So this is a three. This is three. Okay? And then we decrease the volume. And, uh, pressure in Ernie into, uh becomes three. And the pressure becomes too. So this is a business position, too. So it is a straight line, okay? Pointed this direction. And lastly, just go back to the initial state. So this is the PV diagram. And, er, as it's stated in the problem, we not know. Oh, if the idea guess equation, we apply or not. So but the only thing we need to finally just that the next heat blowing into the cycle, right? Ah, So by using the first of them a law, we know that I'm sorry. There is no equal sign here by using the foot of the first of them. All we know, Q. He for the whole cycle, equal to that. You lot stop you. That EU is the changing to the energy for the whole cycle, and the work is the the W's the work done by the gas for the whole cycle because for the whole cycle, that air you better you ihsaa that you should be zero. Because just because the initial point in the bundle point of the same just this point so that a user is zero and cross this out. So basically accuse simply for the w and w the work equal to P T V by definition. And if we do the aim the grow for for the cycle you'll see that this intercourse just represented the area close to buy this lip. Okay, so this is the meaning of this office, integral. So then the probably easy. We just need to calculate the area with the shitty part. Ah, it is It is easy. You just you just need to apply the simple Jeremy Ah, geometric, geometric knowledge. So the area is, uh this is, uh this is the one loss. This is too. In times, this is a two. Do you buy two? And also don't forget that you need to transfer unit into the extent of the unit. So one a t m equal to 1.1 I'm staying to the fifth Posca. One leader is 10 to the negative. Three meters. Cute. Okay, Don't look at you need to do that. So, here. Then. You need thio times, Uh, vectors for the unit for so pressure is one point. 01 times 1 01 10 to 15 and, uh, times another one. Just so this defectors come from come from this, do it just for you. So the final solution should be, uh, 3.3 just 303 I think they're right. So three times. So there. 3.3 Yeah. Three or three kills. So Q is positive. It means that the heat flowing into the gas is positive. So it is means that the net Keats just blow into the guests. That's it.


Similar Solved Questions

5 answers
Oddo Sprint12.44 PM692tor a petkin reactionHW3 What the purpose of the dicthyl ether extrction? _HWA: Fnor to tc acidilication stcp dunng Ihc workup: thc (arede cumpuand uas Soltble Mulct Inulbl 4ulctExplain this solubility trcnd:HWS Anct acidilication uuee Soluble mn Wulcr Insaluble #ictwerkup: the deled conpoand sExplzin this solbbtlity trcnd:
Oddo Sprint 12.44 PM 692 tor a petkin reaction HW3 What the purpose of the dicthyl ether extrction? _ HWA: Fnor to tc acidilication stcp dunng Ihc workup: thc (arede cumpuand uas Soltble Mulct Inulbl 4ulct Explain this solubility trcnd: HWS Anct acidilication uuee Soluble mn Wulcr Insaluble #ict ...
5 answers
Ccnckaf 18 iakxinginial value pieblend: ste) ein(r) y(e) = & s(0) ={0) Flndy (D)-Number01 Frd 38(D).Number
Ccnckaf 18 iakxinginial value pieblen d: ste) ein(r) y(e) = & s(0) = {0) Flndy (D)- Number 01 Frd 38(D). Number...
5 answers
What mRNA codon would the amino-acyl tRNA on the belov! associate with? USe the codon chart provided.# Yua Cga 888%% &&38384 B 9u6 9a6 9 8 AUG Ugg UGaCAGSelect one: 5 GAC-3"b. 5 GUC-3'5- CUG-3" d. 5'-GCA-3'5'CAC-3"
What mRNA codon would the amino-acyl tRNA on the belov! associate with? USe the codon chart provided. # Yua Cga 888%% &&38384 B 9u6 9a6 9 8 AUG Ugg UGa CAG Select one: 5 GAC-3" b. 5 GUC-3' 5- CUG-3" d. 5'-GCA-3' 5'CAC-3"...
5 answers
33 57 1258~ 36 254 -81 =03r" _ 14Z = 0 44(2x - 42x 1) =02 6z - 27 =0 10.32 +32-6=0 11.~9n(Sn - 5) =0
33 57 1258 ~ 36 254 -81 =0 3r" _ 14Z = 0 44 (2x - 42x 1) =0 2 6z - 27 =0 10. 32 +32-6=0 11. ~9n(Sn - 5) =0...
5 answers
3.3Find the critical value(s) and rejection region(s) for the indicated $ test;, lovel of significanco. and samplo sizo Left-Iailed lest, 025 Click Ihe icon view Ihe (-distrbution lableThe crilical value(s) IS/are (Round Ihe nearost Ihousandth a5 needud Uso cormtspafdlu unscensneeded )
3.3 Find the critical value(s) and rejection region(s) for the indicated $ test;, lovel of significanco. and samplo sizo Left-Iailed lest, 025 Click Ihe icon view Ihe (-distrbution lable The crilical value(s) IS/are (Round Ihe nearost Ihousandth a5 needud Uso cormt spafdlu unscens needed )...
5 answers
Pehts} Gien the Iollowina dala s0t, Iet x bo tha axplanalory varlabla 87228 Eieizebz #a least squates hine wus fttod thk data percenta ANSWER:(6) Compule tha corrolation coelliciont:
Pehts} Gien the Iollowina dala s0t, Iet x bo tha axplanalory varlabla 87228 Eieizebz #a least squates hine wus fttod thk data percenta ANSWER: (6) Compule tha corrolation coelliciont:...
5 answers
Activity B: Gauss's Law With Spherical SymmetryA spherica conductor of radius R has net charge of +Q. Your answers for this problem should only depend on the variables r, Q, and Eo.+Q(a) Find an expression for the electric field as a function of (distance from the center of the sphere); forr < R:RFind an expression for the electric field as function of r; for r > R:c) Sketch graph of Evs_ in the space below:
Activity B: Gauss's Law With Spherical Symmetry A spherica conductor of radius R has net charge of +Q. Your answers for this problem should only depend on the variables r, Q, and Eo. +Q (a) Find an expression for the electric field as a function of (distance from the center of the sphere); forr...
5 answers
(a) determine the value of $k$ so that $f(x)$ is a probability density function, and then (b) find the expected value of $f(x)$.$$f(x)=frac{k}{x^{2}+1}$$
(a) determine the value of $k$ so that $f(x)$ is a probability density function, and then (b) find the expected value of $f(x)$. $$f(x)=frac{k}{x^{2}+1}$$...
5 answers
DXunc of utc following TlcAcl Of mlicuaI nurpbcrs f a dcnie subsct af the sct of real numben Oonettu Heluaition curtctecnf 'Provt Ibul Your scqucTkC conlcrber )cqucDCnumibcrconiicmeImlional numherShow that (3 421/? is an algebraic number. cba Ldlbnr AEAC
DXunc of utc following TlcAcl Of mlicuaI nurpbcrs f a dcnie subsct af the sct of real numben Oonettu Heluaition curtctecnf 'Provt Ibul Your scqucTkC conlcrber ) cqucDC numibcr coniicme Imlional numher Show that (3 421/? is an algebraic number. cba Ldlbnr AEAC...
1 answers
Briefly outline the events that control the progression of cells through the $\mathrm{G}_{1} / \mathrm{S}$ checkpoint in the cell cycle.
Briefly outline the events that control the progression of cells through the $\mathrm{G}_{1} / \mathrm{S}$ checkpoint in the cell cycle....
5 answers
(6) (8 pointo) If f(0) # 12 and f"(s) < 4f 1 < e <8,hom Iou coal 2(1} peeealy b9?
(6) (8 pointo) If f(0) # 12 and f"(s) < 4f 1 < e <8,hom Iou coal 2(1} peeealy b9?...
1 answers
Answer the following questions, assuming that $m_{s}$ could have three values rather than two and that the rules for $n, \ell,$ and $m_{\ell}$ are the normal ones. a. How many electrons would an orbital be able to hold? b. How many elements would the first and second periods in the periodic table contain? c. How many elements would be contained in the first transition metal series? d. How many electrons would the set of $4 f$ orbitals be able to hold?
Answer the following questions, assuming that $m_{s}$ could have three values rather than two and that the rules for $n, \ell,$ and $m_{\ell}$ are the normal ones. a. How many electrons would an orbital be able to hold? b. How many elements would the first and second periods in the periodic table co...
5 answers
(16 points) A 10mn chain of length-density 10 kg/m is hanging off of the side of & building that is 20 m tall. Calculate the amount of work required to wind up the chain $0 that only 5 meters is hanging off of the side of the building: Assume that acceleration due to gravity is 9.8 m/s? Inyour aTSWCT, be sure to draw sketch of the setup in the coordinate axes that inclucles your variable of integration.
(16 points) A 10mn chain of length-density 10 kg/m is hanging off of the side of & building that is 20 m tall. Calculate the amount of work required to wind up the chain $0 that only 5 meters is hanging off of the side of the building: Assume that acceleration due to gravity is 9.8 m/s? Inyour ...
5 answers
Simplify each complex fraction. See Example 5 .$$ rac{1+ rac{1}{1-b}}{1- rac{1}{1+b}}$$
Simplify each complex fraction. See Example 5 . $$\frac{1+\frac{1}{1-b}}{1-\frac{1}{1+b}}$$...
5 answers
Assume that f is continuous on [a, b] and differentiable on (a,b).(a) Then prove if f is non-increasing (monotone decreasing) thenf '≤ 0.(b) If f is strictly decreasing, is it true that f ' <0? Either give a counterexample and show where the proof of (a)fails or prove your statement
Assume that f is continuous on [a, b] and differentiable on (a, b). (a) Then prove if f is non-increasing (monotone decreasing) then f '≤ 0. (b) If f is strictly decreasing, is it true that f ' < 0? Either give a counterexample and show where the proof of (a) fails or prove your s...
5 answers
DescriptionFind a series solution fory" -xy = 0 around the point Xo = -2
Description Find a series solution for y" -xy = 0 around the point Xo = -2...
5 answers
Use the glven graph of f to state the value ofrdach quandty, If i exsto (Ifan ans(a)Iim fx) X=2(6) Iim fx) 2limg 4)023 W
Use the glven graph of f to state the value ofrdach quandty, If i exsto (Ifan ans (a) Iim fx) X=2 (6) Iim fx) 2 limg 4) 023 W...
4 answers
Score: 0/52 0/15, answeredQuestion 6Il your car gets 16 miles per gallon, how much does it cost to drive 453 miles when gas costs 2.62 per gallon. Show your work:(Round your answer t0 the nearest cent a5 necded)Submit Questiont
Score: 0/52 0/15, answered Question 6 Il your car gets 16 miles per gallon, how much does it cost to drive 453 miles when gas costs 2.62 per gallon. Show your work: (Round your answer t0 the nearest cent a5 necded) Submit Questiont...

-- 0.018052--