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13ZI10Lahel 3 7 9 i0...

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13ZI10Lahel 3 7 9 i0

13 ZI 10 Lahel 3 7 9 i0



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10. $$1,-\frac{1}{3}, \frac{1}{9},-\frac{1}{27}, \frac{1}{81}, \dots$$

All right. Today we will be continuing our discussion about probability distributions. Start out with reviewing our definition and our two rules that go with probability ministrations. And then we'll be looking at an example and determining if it is a probability distribution or just a distribution and not applicable to be a probability distribution. So to start with probability, distribution is table or an equation that links each outcome of a statistical experiment with its probability of occurrence. And the two rules that a company that it's number one all probabilities and the probability distribution must be between zero and one, can't have negative probabilities and can't have probabilities greater than one because, well, then they're not probabilities anymore. And number two, some of the low probabilities must equal. One is greater than one or less than one than either the probability distribution Waas incorrectly done. And then you're left with just a distribution or just a random example of just how some of them some collections of numbers can't be viewed as probability distributions. No. Are you an apple for today? Uses follows. We have our events over probabilities of said events, and our exes today are 379 12 and 14. And our probabilities are for over 13. 1/13. 3/13 1/13 and to over 13. No, just from writing it out, it's again. We can see that. Number one rule number one all probabilities in the probability distribution master between 01 and that rule is followed. We don't have any negatives and we don't have any thing exceeding one number to sum of all probabilities must equal one. So we need to calculate our total of all of our probabilities. It's going hadn't do that. We see four and one So 5/13 three plus one plus two, you know, together gannets 5/13. So our total comes 10/13. Unfortunately, that does not equal one. So rule number two not followed.

This question gives us a sequence and asked us to determine a formula. What we know that the numerator for each term is one, and the denominators essentially add the numbers after each other times, too. So, as we said, the numerator is one and the denominator times two minus one and this works. If you plug in 1 to 3, you'll got 1 1/3 1 fifth onwards.

You're one of Cube. Each numbers. So three Cube is gonna give us 27. Q is 1 20 by, you know, multiplied by their Super Bowl, which is one over nine. The 27 the nine can both be divided by nine. So I have three and one. So my answer is three over 1 25 and we want to see this improvised down any further in it, does it.

This question asked us to write a formula for the given sequence. What we know is that we alternate between positive and negative values. Therefore, each term is multiplied by negative one to the power and minus one. And then we know the numerator. Zahra Old perfect squares therefore were multiplying remote point by n squared. And then lastly, the denominators are one more than end. Therefore, the denominator is simply n plus one or one plus.


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