Hello. Ah, In this task we have to explore the function which represents time, dependence off the concentration. So first of all, we need to find the horizontal s entered. In order to accomplish this task, we have toe start. We have to find the limit off the function when time approaches infinity. So when the time approaches infinity, Um, the function limit is zero because ah, denominator off this fraction growth faster than the nominator because the denominator is presented by square time while denominator is only linear function off time. So therefore the horizontal a similar roads is C equals zero. Then we need to sketch the we need to sketch the function. So I I just calculated the function in excel and then plot it in graphical software. So it represents Yeah, the function is represented by the maximum which we go into calculate and as well we can see that it has a horizontal assented. C equals zero. So this is that seems like, um lastly, we have to find and ah, time at which concentration reaches its maximum. So in order to do it, we have to calculate the derivative of the fund concentration and then find when this derivative equals to zero. So the derivative off the function is shown here in the in the slide. So it equals to one minus two square over to the square, plus one all square. So and this function equals to zero when nominator when the nominator equals to zero. Therefore okay, in time there yeah, therefore t equals two plus minus square would off 0.5 hours. But as we know, time is positive. Therefore, there is only one solution which is square root of 0.5, which is 0.7 hours. Therefore, the answer the question see, is that consideration reaches maximum when time equals to 0.7 hours.