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Q4DEi Shift A+nCollakiv; Tnskrtione CC) (x-c) ~L B)VSx +Y...

Question

Q4DEi Shift A+nCollakiv; Tnskrtione CC) (x-c) ~L B)VSx +Y

Q4DEi Shift A+nCollakiv; Tnskrtione CC) (x-c) ~L B)VSx +Y



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} \underset{\text { red } \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow}} \mathrm{A} \stackrel{\mathrm{alc} \mathrm{KOH}}{\longrightarrow} \mathrm{B}$ What is $\mathrm{B} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$ (d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

In this problem that writing the reaction at C triple bone siete in presence of Acadia So four hatch too. And so four, it will give CS three CS 2 and it is in pageants. So see http. MdB uh, as village as to it will change into C h T T h do at see http and it is in pageants cell B B E R T. It will change it into see http. See it be uh, see http. DHT CHBS CS three. So, absolutely. It's correct. So absent thee age, correct answer for this problem.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.

So for this problem, we're trying to determine if the function Y equals Synnex, which is the function graft in the red is the same as Y equals co sign X. With just a horizontal shift. Now, as you can see like, well Sin X is going through the origin. Well Y equals co sign X is symmetric to the Y axis. But if you were to shift Y equals cosine X over Hi over 2 to the right, they would actually be identical functions. So for this problem, the answer would be true. Since the functions are identical, they're just shifted from each other pi over two um Either to the left or the right.

You know question is what is the correct corrupt C. So we are going to discuss what is the correct correct to see. Okay so and that can't be helped al Kind and simple. This one is the one this one is done sodium sort of C minus. So what will happen? I'll go and have acidic hydrogen. Okay that's why it will replace acidic hydrogen. Yeah. Then C minus will attack on the oxygen. Thanks. So this express will abstract then we will get oh minus that's plus R. C. H 20 N. E. Plus plus the people on the street actually yes or no. So this is not correct. Product B. So this one is that so this a reacting further vegetables. Then we will get ch to watch. Never going to ch Now this alcohol will get to summarize to summarize then we will get C. S. Trees correct option will be first he is the correct option. R. C. Okay thank you.


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